L081mathematical definition learning

The axioms are:
  - X forall pobi X if and only if does not sum even and does not contains 1
The candidates are: s0 set 2, 6, 8 and 9; s1 set 5 and 7; s2 set 2, 5, 6 and 7; s3 set 3 and 5.
What is the satisfies pobi?

Los axiomas son:
  - X para todo pobi: X si y sólo si no la suma even y no contiene: 1
Los candidatos son: s0 se fija en 2, 6, 8 y 9; s1 se fija en 5 y 7; s2 se fija en 2, 5, 6 y 7; s3 se fija en 3 y 5.
¿Qué satisfies: pobi?

公理如下：X对任意取值都满足pobi：X当且仅当不的总和是even和不包含：1。
候选项如下：s0的集合是2、6、8和9；s1的集合是5和7；s2的集合是2、5、6和7；s3的集合是3和5。
satisfies：pobi什么？

Belitler: X pobi: X sum even değil ve contains: 1 değil iff forall.
Adaylar: s0 2, 6, 8 ve 9 koymak; s1 5 ve 7 koymak; s2 2, 5, 6 ve 7 koymak; s3 3 ve 5 koymak.
Satisfies: pobi ne?

Axioms: X forall pobi: X iff si sum even na si contains: 1.
Wagombea ni: s0 seti 2, 6, 8 na 9; s1 seti 5 na 7; s2 seti 2, 5, 6 na 7; s3 seti 3 na 5.
Satisfies: pobi nini?

The axioms are:
  - X forall pobi X if and only if does not sum even and does not contains 1
The candidates are: s0 set 2, 6, 8 and 9; s1 set 5 and 7; s2 set 2, 5, 6 and 7; s3 set 3 and 5.
What is the satisfies pobi?

{axioms: [(forall X (iff (pobi X) (and (not (sum_even)) (not (contains 1)))))], candidates: [(set s0 [2 6 8 9]) (set s1 [5 7]) (set s2 [2 5 6 7]) (set s3 [3 5])], query: (which_satisfies pobi)}

Axiome: X forall pobi X gdw. nicht Summe eben und nicht contains 1.
Die Kandidaten sind: s0 set 2, 6, 8 und 9; s1 set 5 und 7; s2 set 2, 5, 6 und 7; s3 set 3 und 5.
Was satisfies pobi?

Аксѝо̄м: X forall pobi X iff не zbroj раван и не contains 1.
Кандѝда̄т: s0 се̏т 2, 6, 8 и 9; s1 се̏т 5 и 7; s2 се̏т 2, 5, 6 и 7; s3 се̏т 3 и 5.
Satisfies pobi kakav?

Perusväitteet: X forall pobi X joss ei summa tasainen ja ei contains 1.
Ehdokkaat: s0 set 2, 6, 8 ja 9; s1 set 5 ja 7; s2 set 2, 5, 6 ja 7; s3 set 3 ja 5.
Mikä satisfies pobi?

公理如下：X对任意取值都满足pobi：X当且仅当不的总和是even和不包含：1。
候选项如下：s0的集合是2、6、8和9；s1的集合是5和7；s2的集合是2、5、6和7；s3的集合是3和5。
satisfies：pobi什么？

公理:Xpobi:X総額平...ではないとcontains:1...ではないiffforall.
候補者:s02, 6, 8と9置く; s15と7置く; s22, 5, 6と7置く; s33と5置く.
satisfies:pobi何と?

Belitler: X pobi: X sum even değil ve contains: 1 değil iff forall.
Adaylar: s0 2, 6, 8 ve 9 koymak; s1 5 ve 7 koymak; s2 2, 5, 6 ve 7 koymak; s3 3 ve 5 koymak.
Satisfies: pobi ne?

بَدِيهِيَّة: forall X iff pobi X لَا مَجْمُوع مُسَطَّح وَـ لَا contains 1.
مُرَشَّح: وَضَع s0 2، 6، 8 وَـ 9؛ وَضَع s1 5 وَـ 7؛ وَضَع s2 2، 5، 6 وَـ 7؛ وَضَع s3 3 وَـ 5.
satisfies pobi مَاذَا؟

Აქსიომები: X pobi X არ ჯამი კი და არ contains 1 iff forall.
Კანდიდატები: s0 2, 6, 8 და 9 set; s1 5 და 7 set; s2 2, 5, 6 და 7 set; s3 3 და 5 set.
Satisfies pobi რა?

Axioms: forall X iff pobi X kāore tapeke papatairite me kāore contains 1.
Kaiwhakauru: whakawhenua s0 2, 6, 8 me 9; whakawhenua s1 5 me 7; whakawhenua s2 2, 5, 6 me 7; whakawhenua s3 3 me 5.
Satisfies pobi unutai?

Chân lý: X forall pobi X iff không tổng số bằng phẳng và không contains 1.
Candidates: s0 để 2, 6, 8 và 9; s1 để 5 và 7; s2 để 2, 5, 6 và 7; s3 để 3 và 5.
Satisfies pobi gì?

สัจพจน์:Xforallpobi:Xiffไม่sumแม้และไม่contains:1.
ผู้สมัคร:s0set2, 6, 8และ9; s1set5และ7; s2set2, 5, 6และ7; s3set3และ5.
satisfies:pobiอะไร?

axioms:
  - X pobi X sum இரட்டைப்படை இல்லை மற்றும் contains 1 இல்லை iff forall
வேட்பாளர்: s0 2, 6, 8 மற்றும் 9 set; s1 5 மற்றும் 7 set; s2 2, 5, 6 மற்றும் 7 set; s3 3 மற்றும் 5 set.
satisfies pobi என்ன?

Axioms: X forall pobi: X iff si sum even na si contains: 1.
Wagombea ni: s0 seti 2, 6, 8 na 9; s1 seti 5 na 7; s2 seti 2, 5, 6 na 7; s3 seti 3 na 5.
Satisfies: pobi nini?

Axioms: X pobi X dooda sum ndi dóó dooda contains 1 iff forall.
Candidates: s0 2, 6, 8 dóó 9 set; s1 5 dóó 7 set; s2 2, 5, 6 dóó 7 set; s3 3 dóó 5 set.
Satisfies pobi haʼátʼíísh?

Axioms: X pobi X sum even not aamma contains 1 not iff forall.
Candidates: s0 2, 6, 8 aamma 9 set; s1 5 aamma 7 set; s2 2, 5, 6 aamma 7 set; s3 3 aamma 5 set.
Satisfies pobi what?

Axioms: X forall pobi X iff not sum even na not contains 1.
Candidates: s0 set 2, 6, 8 na 9; s1 set 5 na 7; s2 set 2, 5, 6 na 7; s3 set 3 na 5.
Satisfies pobi what?

Axioms: X forall pobi X iff not sum even not contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
Satisfies pobi kwèch?

Axioms: X forall pobi X iff sum even ца а contains 1 ца.
Candidates: s0 set 2, 6, 8 а 9; s1 set 5 а 7; s2 set 2, 5, 6 а 7; s3 set 3 а 5.
Satisfies pobi фу?

공리: X pobi X 안 합계 고르다 안 contains 1 iff forall.
후보자: s0 2, 6, 8 9 두다; s1 5 7 두다; s2 2, 5, 6 7 두다; s3 3 5 두다.
satisfies pobi 무엇?

Axioms: X pobi X ez sum even eta ez contains 1 iff forall.
Kandidatu: s0 2, 6, 8 eta 9 multzo; s1 5 eta 7 multzo; s2 2, 5, 6 eta 7 multzo; s3 3 eta 5 multzo.
Satisfies pobi zer?

Axioms: X forall pobi X iff ᏝᏃ sum even ᎠᎴ ᏝᏃ contains 1.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 2, 6, 8 ᎠᎴ 9; s1 ᏭᏕᎵᎦ 5 ᎠᎴ 7; s2 ᏭᏕᎵᎦ 2, 5, 6 ᎠᎴ 7; s3 ᏭᏕᎵᎦ 3 ᎠᎴ 5.
What satisfies pobi?

Axioms: X forall pobi X iff ama qullu even ama contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
Satisfies pobi what?

Axioms: X pobi X not sum even ыкӏи not contains 1 iff forall.
Candidates: s0 2, 6, 8 ыкӏи 9 set; s1 5 ыкӏи 7 set; s2 2, 5, 6 ыкӏи 7 set; s3 3 ыкӏи 5 set.
Satisfies pobi сыд?

Axioms: X forall pobi X iff tsis sum even thiab tsis contains 1.
Candidates: s0 set 2, 6, 8 thiab 9; s1 set 5 thiab 7; s2 set 2, 5, 6 thiab 7; s3 set 3 thiab 5.
Satisfies pobi what?

Axioms: X forall pobi X iff woi sum even woi contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
Satisfies pobi ining-jak?

Axioms: X forall pobi X iff ki'yo sum even micha' ki'yo contains 1.
Candidates: s0 set 2, 6, 8 micha' 9; s1 set 5 micha' 7; s2 set 2, 5, 6 micha' 7; s3 set 3 micha' 5.
Satisfies pobi nanta?

Axioms: X pobi X ソモ sum even カ ソモ contains 1 iff forall.
Candidates: s0 2, 6, 8 カ 9 set; s1 5 カ 7 set; s2 2, 5, 6 カ 7 set; s3 3 カ 5 set.
Satisfies pobi what?

Axioms: X forall pobi X iff not sum even ынкъам not contains 1.
Candidates: s0 set 2, 6, 8 ынкъам 9; s1 set 5 ынкъам 7; s2 set 2, 5, 6 ынкъам 7; s3 set 3 ынкъам 5.
Satisfies pobi what?

Axioms: X forall pobi X iff ma' sum even yéetel ma' contains 1.
Candidates: s0 set 2, 6, 8 yéetel 9; s1 set 5 yéetel 7; s2 set 2, 5, 6 yéetel 7; s3 set 3 yéetel 5.
Satisfies pobi what?

Axioms: X forall pobi X iff not sum even not contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
Satisfies pobi híli?

Axioms: X pobi X sum even not na contains 1 not iff forall.
Candidates: s0 2, 6, 8 na 9 set; s1 5 na 7 set; s2 2, 5, 6 na 7 set; s3 3 na 5 set.
Satisfies pobi what?

Axioms: X forall pobi X iff nahániri sum even nahániri contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
Satisfies pobi what?

Axioms: X pobi X not sum even not contains 1 iff forall.
Candidates: s0 2, 6, 8 9 set; s1 5 7 set; s2 2, 5, 6 7 set; s3 3 5 set.
Satisfies pobi what?

Axioms: X forall pobi X iff ǁʻàa sum even ǂʻá ǁʻàa contains 1.
Candidates: s0 set 2, 6, 8 ǂʻá 9; s1 set 5 ǂʻá 7; s2 set 2, 5, 6 ǂʻá 7; s3 set 3 ǂʻá 5.
Satisfies pobi what?

Axioms: X pobi X not sum even not contains 1 iff forall.
Candidates: s0 2, 6, 8 9 set; s1 5 7 set; s2 2, 5, 6 7 set; s3 3 5 set.
Satisfies pobi what?

Axioms: X forall pobi X iff not sum even not contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
Satisfies pobi what?

Axioms: X pobi X not sum even not contains 1 iff forall.
Candidates: s0 2, 6, 8 9 set; s1 5 7 set; s2 2, 5, 6 7 set; s3 3 5 set.
Satisfies pobi what?

Axioms: X forall pobi X iff not sum even not contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
Satisfies pobi what?

Axioms: X forall pobi X iff inte sum even inte contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
Satisfies pobi tay?

Axiomes : X forall pobi X ssi pas somme plat et pas contains 1.
Les candidats sont : s0 poser 2, 6, 8 et 9 ; s1 poser 5 et 7 ; s2 poser 2, 5, 6 et 7 ; s3 poser 3 et 5.
Quoi satisfies pobi ?

Aksiomo: X forall pobi X iff ne sum ebena kaj ne contains 1.
Kandidato: s0 meti 2, 6, 8 kaj 9; s1 meti 5 kaj 7; s2 meti 2, 5, 6 kaj 7; s3 meti 3 kaj 5.
Satisfies pobi kio?

Axiómák: X forall pobi X acsa nem összeg egyenletes és nem contains 1.
Indulók: s0 set 2, 6, 8 és 9; s1 set 5 és 7; s2 set 2, 5, 6 és 7; s3 set 3 és 5.
Satisfies pobi melyik?

axioms:Xforallpobi:Xiff不sum更加及不contains:1.
候選人:s0set2, 6, 8及9; s1set5及7; s2set2, 5, 6及7; s3set3及5.
satisfies:pobi乜嘢?

Axioms: X forall pobi X iff not sum even とぅ not contains 1.
Candidates: s0 set 2, 6, 8 とぅ 9; s1 set 5 とぅ 7; s2 set 2, 5, 6 とぅ 7; s3 set 3 とぅ 5.
Satisfies pobi what?

Аксиома: X forall pobi X iff емес сом да және емес contains 1.
Үміткер: s0 жиын 2, 6, 8 және 9; s1 жиын 5 және 7; s2 жиын 2, 5, 6 және 7; s3 жиын 3 және 5.
Satisfies pobi не?

אַקְסְיוֹמָה: X forall pobi X אםם לא סְכוּם ערב וְ־ לא contains 1.
מועמדת: s0 הֵנִיח 2, 6, 8 וְ־ 9; s1 הֵנִיח 5 וְ־ 7; s2 הֵנִיח 2, 5, 6 וְ־ 7; s3 הֵנִיח 3 וְ־ 5.
איזה satisfies pobi?

Axioms: X forall pobi X iff not sum even დო not contains 1.
Candidates: s0 set 2, 6, 8 დო 9; s1 set 5 დო 7; s2 set 2, 5, 6 დო 7; s3 set 3 დო 5.
Satisfies pobi what?

Aksioma-aksioma: X forall pobi X iff tidak sum rata dan tidak contains 1.
Kandidat: s0 memperkenalkan 2, 6, 8 dan 9; s1 memperkenalkan 5 dan 7; s2 memperkenalkan 2, 5, 6 dan 7; s3 memperkenalkan 3 dan 5.
Satisfies pobi apa?

ស្វ័យសត្យ:Xforallpobi:Xiffមិន...ទេផលបូកសូម្បីនឹងមិន...ទេcontains:1.
បេក្ខជន:s0set2, 6, 8នឹង9; s1set5នឹង7; s2set2, 5, 6នឹង7; s3set3នឹង5.
satisfies:pobiអី?

ກົດຄວາມຈິງ:Xforallpobi:Xiffບໍ່sum evenແລະບໍ່contains:1.
ຜູ້ສະໝັກ:s0set2, 6, 8ແລະ9; s1set5ແລະ7; s2set2, 5, 6ແລະ7; s3set3ແລະ5.
satisfies:pobiຫຍັງ?

axioms: X pobi X sum చదునైన కాదు మరియు contains 1 కాదు iff forall.
candidates: s0 2, 6, 8 మరియు 9 set; s1 5 మరియు 7 set; s2 2, 5, 6 మరియు 7 set; s3 3 మరియు 5 set.
satisfies pobi ఏమిటి?

Axioms: X forall pobi X iff rárá sum even rárá contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
What satisfies pobi?

Axioms: X pobi X dawǫ́’ sum even dawǫ́’ contains 1 iff forall.
Candidates: s0 2, 6, 8 9 set; s1 5 7 set; s2 2, 5, 6 7 set; s3 3 5 set.
Satisfies pobi what?

axioms: X forall pobi X iff ᐋᒃᑲ sum even ᐋᒃᑲ contains 1.
candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
satisfies pobi what?

Axioms: X forall pobi X iff not sum even not contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
Satisfies pobi what?

Axioms: X forall pobi X iff not sum even not contains 1.
Candidates: s0 set 2, 6, 8 9; s1 set 5 7; s2 set 2, 5, 6 7; s3 set 3 5.
Satisfies pobi what?

Axioms: X pobi X sum even not contains 1 not iff forall.
Candidates: s0 2, 6, 8 9 set; s1 5 7 set; s2 2, 5, 6 7 set; s3 3 5 set.
Satisfies pobi вуч?

The axioms are: X forall gudi X if and only if size at least 4 and has odd.
The candidates are: s0 set 1, 5 and 8; s1 set 5, 8 and 9; s2 set 4, 6 and 9; s3 set 2, 3, 6, 8 and 9.
What is the satisfies gudi?

Los axiomas son: X para todo gudi: X si y sólo si tamaño en least: 4 y tiene odd.
Los candidatos son: s0 se fija en 1, 5 y 8; s1 se fija en 5, 8 y 9; s2 se fija en 4, 6 y 9; s3 se fija en 2, 3, 6, 8 y 9.
¿Qué satisfies: gudi?

公理如下：X对任意取值都满足gudi：X当且仅当大小在least：4和有odd。
候选项如下：s0的集合是1、5和8；s1的集合是5、8和9；s2的集合是4、6和9；s3的集合是2、3、6、8和9。
satisfies：gudi什么？

Belitler: X gudi: X boyut at least: 4 ve sahiptir odd iff forall.
Adaylar: s0 1, 5 ve 8 koymak; s1 5, 8 ve 9 koymak; s2 4, 6 ve 9 koymak; s3 2, 3, 6, 8 ve 9 koymak.
Satisfies: gudi ne?

Axioms: X forall gudi: X iff size katika least: 4 na ina odd.
Wagombea ni: s0 seti 1, 5 na 8; s1 seti 5, 8 na 9; s2 seti 4, 6 na 9; s3 seti 2, 3, 6, 8 na 9.
Satisfies: gudi nini?

The axioms are: X forall gudi X if and only if size at least 4 and has odd.
The candidates are: s0 set 1, 5 and 8; s1 set 5, 8 and 9; s2 set 4, 6 and 9; s3 set 2, 3, 6, 8 and 9.
What is the satisfies gudi?

{axioms: [(forall X (iff (gudi X) (and (size_at_least 4) (has_odd))))], candidates: [(set s0 [1 5 8]) (set s1 [5 8 9]) (set s2 [4 6 9]) (set s3 [2 3 6 8 9])], query: (which_satisfies gudi)}

Axiome: X forall gudi X gdw. Größe an geringst 4 und haben seltsam.
Die Kandidaten sind: s0 set 1, 5 und 8; s1 set 5, 8 und 9; s2 set 4, 6 und 9; s3 set 2, 3, 6, 8 und 9.
Was satisfies gudi?

Аксѝо̄м: X forall gudi X iff величѝна at minimalan 4 и имати непаран.
Кандѝда̄т: s0 се̏т 1, 5 и 8; s1 се̏т 5, 8 и 9; s2 се̏т 4, 6 и 9; s3 се̏т 2, 3, 6, 8 и 9.
Satisfies gudi kakav?

Perusväitteet: X forall gudi X joss koko luona vähin 4 ja omistaa outo.
Ehdokkaat: s0 set 1, 5 ja 8; s1 set 5, 8 ja 9; s2 set 4, 6 ja 9; s3 set 2, 3, 6, 8 ja 9.
Mikä satisfies gudi?

公理如下：X对任意取值都满足gudi：X当且仅当大小在least：4和有odd。
候选项如下：s0的集合是1、5和8；s1的集合是5、8和9；s2的集合是4、6和9；s3的集合是2、3、6、8和9。
satisfies：gudi什么？

公理:Xgudi:X大きさ...で最小の:4とhave変なiffforall.
候補者:s01, 5と8置く; s15, 8と9置く; s24, 6と9置く; s32, 3, 6, 8と9置く.
satisfies:gudi何と?

Belitler: X gudi: X boyut at least: 4 ve sahiptir odd iff forall.
Adaylar: s0 1, 5 ve 8 koymak; s1 5, 8 ve 9 koymak; s2 4, 6 ve 9 koymak; s3 2, 3, 6, 8 ve 9 koymak.
Satisfies: gudi ne?

بَدِيهِيَّة: forall X iff gudi X مَقَاس عِنْد أَقَلَّ 4 وَـ مَلَكَ فَرْدِيّ.
مُرَشَّح: وَضَع s0 1، 5 وَـ 8؛ وَضَع s1 5، 8 وَـ 9؛ وَضَع s2 4، 6 وَـ 9؛ وَضَع s3 2، 3، 6، 8 وَـ 9.
satisfies gudi مَاذَا؟

Აქსიომები: X gudi X ზომა at least 4 და ფლობს უცნაური iff forall.
Კანდიდატები: s0 1, 5 და 8 set; s1 5, 8 და 9 set; s2 4, 6 და 9 set; s3 2, 3, 6, 8 და 9 set.
Satisfies gudi რა?

Axioms: forall X iff gudi X size i least 4 me whai makere.
Kaiwhakauru: whakawhenua s0 1, 5 me 8; whakawhenua s1 5, 8 me 9; whakawhenua s2 4, 6 me 9; whakawhenua s3 2, 3, 6, 8 me 9.
Satisfies gudi unutai?

Chân lý: X forall gudi X iff kích thước lúc least 4 và có kỳ cục.
Candidates: s0 để 1, 5 và 8; s1 để 5, 8 và 9; s2 để 4, 6 và 9; s3 để 2, 3, 6, 8 và 9.
Satisfies gudi gì?

สัจพจน์:Xforallgudi:Xiffขนาดที่least:4และมีคี่.
ผู้สมัคร:s0set1, 5และ8; s1set5, 8และ9; s2set4, 6และ9; s3set2, 3, 6, 8และ9.
satisfies:gudiอะไร?

axioms: X gudi X size at least 4 மற்றும் have ஒற்றைப்படை iff forall.
வேட்பாளர்: s0 1, 5 மற்றும் 8 set; s1 5, 8 மற்றும் 9 set; s2 4, 6 மற்றும் 9 set; s3 2, 3, 6, 8 மற்றும் 9 set.
satisfies gudi என்ன?

Axioms: X forall gudi: X iff size katika least: 4 na ina odd.
Wagombea ni: s0 seti 1, 5 na 8; s1 seti 5, 8 na 9; s2 seti 4, 6 na 9; s3 seti 2, 3, 6, 8 na 9.
Satisfies: gudi nini?

Axioms: X gudi X size at least 4 dóó bee hólǫ́ odd iff forall.
Candidates: s0 1, 5 dóó 8 set; s1 5, 8 dóó 9 set; s2 4, 6 dóó 9 set; s3 2, 3, 6, 8 dóó 9 set.
Satisfies gudi haʼátʼíísh?

Axioms: X gudi X size at least 4 aamma qar odd iff forall.
Candidates: s0 1, 5 aamma 8 set; s1 5, 8 aamma 9 set; s2 4, 6 aamma 9 set; s3 2, 3, 6, 8 aamma 9 set.
Satisfies gudi what?

Axioms: X forall gudi X iff size long least 4 na have odd.
Candidates: s0 set 1, 5 na 8; s1 set 5, 8 na 9; s2 set 4, 6 na 9; s3 set 2, 3, 6, 8 na 9.
Satisfies gudi what?

Axioms: X forall gudi X iff size at least 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
Satisfies gudi kwèch?

Axioms: X forall gudi X iff size at least 4 а have odd.
Candidates: s0 set 1, 5 а 8; s1 set 5, 8 а 9; s2 set 4, 6 а 9; s3 set 2, 3, 6, 8 а 9.
Satisfies gudi фу?

공리: X gudi X 크기 at 가장 적게 4 있다 기수의 iff forall.
후보자: s0 1, 5 8 두다; s1 5, 8 9 두다; s2 4, 6 9 두다; s3 2, 3, 6, 8 9 두다.
satisfies gudi 무엇?

Axioms: X gudi X tamaina at least 4 eta eduki odd iff forall.
Kandidatu: s0 1, 5 eta 8 multzo; s1 5, 8 eta 9 multzo; s2 4, 6 eta 9 multzo; s3 2, 3, 6, 8 eta 9 multzo.
Satisfies gudi zer?

Axioms: X forall gudi X iff size at least 4 ᎠᎴ ᎤᎭ odd.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 1, 5 ᎠᎴ 8; s1 ᏭᏕᎵᎦ 5, 8 ᎠᎴ 9; s2 ᏭᏕᎵᎦ 4, 6 ᎠᎴ 9; s3 ᏭᏕᎵᎦ 2, 3, 6, 8 ᎠᎴ 9.
What satisfies gudi?

Axioms: X forall gudi X iff chhika at least 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
Satisfies gudi what?

Axioms: X gudi X size at least 4 ыкӏи have odd iff forall.
Candidates: s0 1, 5 ыкӏи 8 set; s1 5, 8 ыкӏи 9 set; s2 4, 6 ыкӏи 9 set; s3 2, 3, 6, 8 ыкӏи 9 set.
Satisfies gudi сыд?

Axioms: X forall gudi X iff size at least 4 thiab have odd.
Candidates: s0 set 1, 5 thiab 8; s1 set 5, 8 thiab 9; s2 set 4, 6 thiab 9; s3 set 2, 3, 6, 8 thiab 9.
Satisfies gudi what?

Axioms: X forall gudi X iff size jeyou wy krook 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
Satisfies gudi ining-jak?

Axioms: X forall gudi X iff size at least 4 micha' have odd.
Candidates: s0 set 1, 5 micha' 8; s1 set 5, 8 micha' 9; s2 set 4, 6 micha' 9; s3 set 2, 3, 6, 8 micha' 9.
Satisfies gudi nanta?

Axioms: X gudi X size at least 4 カ have odd iff forall.
Candidates: s0 1, 5 カ 8 set; s1 5, 8 カ 9 set; s2 4, 6 カ 9 set; s3 2, 3, 6, 8 カ 9 set.
Satisfies gudi what?

Axioms: X forall gudi X iff size at least 4 ынкъам рытык odd.
Candidates: s0 set 1, 5 ынкъам 8; s1 set 5, 8 ынкъам 9; s2 set 4, 6 ынкъам 9; s3 set 2, 3, 6, 8 ынкъам 9.
Satisfies gudi what?

Axioms: X forall gudi X iff size at least 4 yéetel have odd.
Candidates: s0 set 1, 5 yéetel 8; s1 set 5, 8 yéetel 9; s2 set 4, 6 yéetel 9; s3 set 2, 3, 6, 8 yéetel 9.
Satisfies gudi what?

Axioms: X forall gudi X iff size at least 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
Satisfies gudi híli?

Axioms: X gudi X size at least 4 na have odd iff forall.
Candidates: s0 1, 5 na 8 set; s1 5, 8 na 9 set; s2 4, 6 na 9 set; s3 2, 3, 6, 8 na 9 set.
Satisfies gudi what?

Axioms: X forall gudi X iff size at least 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
Satisfies gudi what?

Axioms: X gudi X size at least 4 have odd iff forall.
Candidates: s0 1, 5 8 set; s1 5, 8 9 set; s2 4, 6 9 set; s3 2, 3, 6, 8 9 set.
Satisfies gudi what?

Axioms: X forall gudi X iff ʻǁnàhã at least 4 ǂʻá have odd.
Candidates: s0 set 1, 5 ǂʻá 8; s1 set 5, 8 ǂʻá 9; s2 set 4, 6 ǂʻá 9; s3 set 2, 3, 6, 8 ǂʻá 9.
Satisfies gudi what?

Axioms: X gudi X size at least 4 have odd iff forall.
Candidates: s0 1, 5 8 set; s1 5, 8 9 set; s2 4, 6 9 set; s3 2, 3, 6, 8 9 set.
Satisfies gudi what?

Axioms: X forall gudi X iff size at least 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
Satisfies gudi what?

Axioms: X gudi X size at least 4 have odd iff forall.
Candidates: s0 1, 5 8 set; s1 5, 8 9 set; s2 4, 6 9 set; s3 2, 3, 6, 8 9 set.
Satisfies gudi what?

Axioms: X forall gudi X iff size at least 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
Satisfies gudi what?

Axioms: X forall gudi X iff size at least 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
Satisfies gudi tay?

Axiomes : X forall gudi X ssi taille au moindre 4 et avoir bizarre.
Les candidats sont : s0 poser 1, 5 et 8 ; s1 poser 5, 8 et 9 ; s2 poser 4, 6 et 9 ; s3 poser 2, 3, 6, 8 et 9.
Quoi satisfies gudi ?

Aksiomo: X forall gudi X iff grandeco ĉe plej malmulta 4 kaj havi stranga.
Kandidato: s0 meti 1, 5 kaj 8; s1 meti 5, 8 kaj 9; s2 meti 4, 6 kaj 9; s3 meti 2, 3, 6, 8 kaj 9.
Satisfies gudi kio?

Axiómák: X forall gudi X acsa méret at legkisebb 4 és bír furcsa.
Indulók: s0 set 1, 5 és 8; s1 set 5, 8 és 9; s2 set 4, 6 és 9; s3 set 2, 3, 6, 8 és 9.
Satisfies gudi melyik?

axioms:Xforallgudi:Xiffsize喺least:4及有odd.
候選人:s0set1, 5及8; s1set5, 8及9; s2set4, 6及9; s3set2, 3, 6, 8及9.
satisfies:gudi乜嘢?

Axioms: X forall gudi X iff size at least 4 とぅ have odd.
Candidates: s0 set 1, 5 とぅ 8; s1 set 5, 8 とぅ 9; s2 set 4, 6 とぅ 9; s3 set 2, 3, 6, 8 とぅ 9.
Satisfies gudi what?

Аксиома: X forall gudi X iff мөлшер at least 4 және have odd.
Үміткер: s0 жиын 1, 5 және 8; s1 жиын 5, 8 және 9; s2 жиын 4, 6 және 9; s3 жиын 2, 3, 6, 8 және 9.
Satisfies gudi не?

אַקְסְיוֹמָה: X forall gudi X אםם גֹּדֶל אֵצֶל least 4 וְ־ have משונה.
מועמדת: s0 הֵנִיח 1, 5 וְ־ 8; s1 הֵנִיח 5, 8 וְ־ 9; s2 הֵנִיח 4, 6 וְ־ 9; s3 הֵנִיח 2, 3, 6, 8 וְ־ 9.
איזה satisfies gudi?

Axioms: X forall gudi X iff size at least 4 დო have odd.
Candidates: s0 set 1, 5 დო 8; s1 set 5, 8 დო 9; s2 set 4, 6 დო 9; s3 set 2, 3, 6, 8 დო 9.
Satisfies gudi what?

Aksioma-aksioma: X forall gudi X iff ukuran at least 4 dan punya ganjil.
Kandidat: s0 memperkenalkan 1, 5 dan 8; s1 memperkenalkan 5, 8 dan 9; s2 memperkenalkan 4, 6 dan 9; s3 memperkenalkan 2, 3, 6, 8 dan 9.
Satisfies gudi apa?

ស្វ័យសត្យ:Xforallgudi:Xiffទំហំatleast:4នឹងមានសេស.
បេក្ខជន:s0set1, 5នឹង8; s1set5, 8នឹង9; s2set4, 6នឹង9; s3set2, 3, 6, 8នឹង9.
satisfies:gudiអី?

ກົດຄວາມຈິງ:Xforallgudi:Xiffຂະຫນາດທີ່least:4ແລະມີodd.
ຜູ້ສະໝັກ:s0set1, 5ແລະ8; s1set5, 8ແລະ9; s2set4, 6ແລະ9; s3set2, 3, 6, 8ແລະ9.
satisfies:gudiຫຍັງ?

axioms: X gudi X size వద్ద least 4 మరియు have విలక్షణమైన iff forall.
candidates: s0 1, 5 మరియు 8 set; s1 5, 8 మరియు 9 set; s2 4, 6 మరియు 9 set; s3 2, 3, 6, 8 మరియు 9 set.
satisfies gudi ఏమిటి?

Axioms: X forall gudi X iff size at least 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
What satisfies gudi?

Axioms: X gudi X size at least 4 have odd iff forall.
Candidates: s0 1, 5 8 set; s1 5, 8 9 set; s2 4, 6 9 set; s3 2, 3, 6, 8 9 set.
Satisfies gudi what?

axioms: X forall gudi X iff size at least 4 have odd.
candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
satisfies gudi what?

Axioms: X forall gudi X iff size at least 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
Satisfies gudi what?

Axioms: X forall gudi X iff size at least 4 have odd.
Candidates: s0 set 1, 5 8; s1 set 5, 8 9; s2 set 4, 6 9; s3 set 2, 3, 6, 8 9.
Satisfies gudi what?

Axioms: X gudi X size at least 4 have odd iff forall.
Candidates: s0 1, 5 8 set; s1 5, 8 9 set; s2 4, 6 9 set; s3 2, 3, 6, 8 9 set.
Satisfies gudi вуч?

The axioms are:
  - X forall badi X if and only if min at most 2 and does not has even
The candidates are: s0 set 5 and 6; s1 set 3, 5 and 9; s2 set 2 and 9; s3 set 1 and 9.
What is the satisfies badi?

Los axiomas son:
  - X para todo badi: X si y sólo si mínimo en la mayoría: 2 y no tiene even
Los candidatos son: s0 se fija en 5 y 6; s1 se fija en 3, 5 y 9; s2 se fija en 2 y 9; s3 se fija en 1 y 9.
¿Qué satisfies: badi?

公理如下：X对任意取值都满足badi：X当且仅当最小值在大多数：2和不有even。
候选项如下：s0的集合是5和6；s1的集合是3、5和9；s2的集合是2和9；s3的集合是1和9。
satisfies：badi什么？

Belitler: X badi: X min at çoğu: 2 ve sahiptir even değil iff forall.
Adaylar: s0 5 ve 6 koymak; s1 3, 5 ve 9 koymak; s2 2 ve 9 koymak; s3 1 ve 9 koymak.
Satisfies: badi ne?

Axioms: X forall badi: X iff min katika wengi: 2 na si ina even.
Wagombea ni: s0 seti 5 na 6; s1 seti 3, 5 na 9; s2 seti 2 na 9; s3 seti 1 na 9.
Satisfies: badi nini?

The axioms are:
  - X forall badi X if and only if min at most 2 and does not has even
The candidates are: s0 set 5 and 6; s1 set 3, 5 and 9; s2 set 2 and 9; s3 set 1 and 9.
What is the satisfies badi?

{axioms: [(forall X (iff (badi X) (and (min_at_most 2) (not (has_even)))))], candidates: [(set s0 [5 6]) (set s1 [3 5 9]) (set s2 [2 9]) (set s3 [1 9])], query: (which_satisfies badi)}

Axiome: X forall badi X gdw. min an die meisten 2 und nicht haben eben.
Die Kandidaten sind: s0 set 5 und 6; s1 set 3, 5 und 9; s2 set 2 und 9; s3 set 1 und 9.
Was satisfies badi?

Аксѝо̄м: X forall badi X iff min at većina 2 и не имати раван.
Кандѝда̄т: s0 се̏т 5 и 6; s1 се̏т 3, 5 и 9; s2 се̏т 2 и 9; s3 се̏т 1 и 9.
Satisfies badi kakav?

Perusväitteet: X forall badi X joss min luona useimmat 2 ja ei omistaa tasainen.
Ehdokkaat: s0 set 5 ja 6; s1 set 3, 5 ja 9; s2 set 2 ja 9; s3 set 1 ja 9.
Mikä satisfies badi?

公理如下：X对任意取值都满足badi：X当且仅当最小值在大多数：2和不有even。
候选项如下：s0的集合是5和6；s1的集合是3、5和9；s2的集合是2和9；s3的集合是1和9。
satisfies：badi什么？

公理:Xbadi:Xmin...で大部分:2とhave平...ではないiffforall.
候補者:s05と6置く; s13, 5と9置く; s22と9置く; s31と9置く.
satisfies:badi何と?

Belitler: X badi: X min at çoğu: 2 ve sahiptir even değil iff forall.
Adaylar: s0 5 ve 6 koymak; s1 3, 5 ve 9 koymak; s2 2 ve 9 koymak; s3 1 ve 9 koymak.
Satisfies: badi ne?

بَدِيهِيَّة: forall X iff badi X min عِنْد أَكْثَر 2 وَـ لَا مَلَكَ مُسَطَّح.
مُرَشَّح: وَضَع s0 5 وَـ 6؛ وَضَع s1 3، 5 وَـ 9؛ وَضَع s2 2 وَـ 9؛ وَضَع s3 1 وَـ 9.
satisfies badi مَاذَا؟

Აქსიომები: X badi X min at უმეტესობა 2 და არ ფლობს კი iff forall.
Კანდიდატები: s0 5 და 6 set; s1 3, 5 და 9 set; s2 2 და 9 set; s3 1 და 9 set.
Satisfies badi რა?

Axioms: forall X iff badi X min i nuinga 2 me kāore whai papatairite.
Kaiwhakauru: whakawhenua s0 5 me 6; whakawhenua s1 3, 5 me 9; whakawhenua s2 2 me 9; whakawhenua s3 1 me 9.
Satisfies badi unutai?

Chân lý: X forall badi X iff min lúc hầu hết 2 và không có bằng phẳng.
Candidates: s0 để 5 và 6; s1 để 3, 5 và 9; s2 để 2 và 9; s3 để 1 và 9.
Satisfies badi gì?

สัจพจน์:Xforallbadi:Xiffminที่ส่วนใหญ่:2และไม่มีแม้.
ผู้สมัคร:s0set5และ6; s1set3, 5และ9; s2set2และ9; s3set1และ9.
satisfies:badiอะไร?

axioms: X badi X min at most 2 மற்றும் have இரட்டைப்படை இல்லை iff forall.
வேட்பாளர்: s0 5 மற்றும் 6 set; s1 3, 5 மற்றும் 9 set; s2 2 மற்றும் 9 set; s3 1 மற்றும் 9 set.
satisfies badi என்ன?

Axioms: X forall badi: X iff min katika wengi: 2 na si ina even.
Wagombea ni: s0 seti 5 na 6; s1 seti 3, 5 na 9; s2 seti 2 na 9; s3 seti 1 na 9.
Satisfies: badi nini?

Axioms: X badi X min at most 2 dóó dooda bee hólǫ́ ndi iff forall.
Candidates: s0 5 dóó 6 set; s1 3, 5 dóó 9 set; s2 2 dóó 9 set; s3 1 dóó 9 set.
Satisfies badi haʼátʼíísh?

Axioms: X badi X min at most 2 aamma qar even not iff forall.
Candidates: s0 5 aamma 6 set; s1 3, 5 aamma 9 set; s2 2 aamma 9 set; s3 1 aamma 9 set.
Satisfies badi what?

Axioms: X forall badi X iff min long most 2 na not have even.
Candidates: s0 set 5 na 6; s1 set 3, 5 na 9; s2 set 2 na 9; s3 set 1 na 9.
Satisfies badi what?

Axioms: X forall badi X iff min at most 2 not have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
Satisfies badi kwèch?

Axioms: X forall badi X iff min at most 2 а have even ца.
Candidates: s0 set 5 а 6; s1 set 3, 5 а 9; s2 set 2 а 9; s3 set 1 а 9.
Satisfies badi фу?

공리: X badi X min at 가장 2 안 있다 고르다 iff forall.
후보자: s0 5 6 두다; s1 3, 5 9 두다; s2 2 9 두다; s3 1 9 두다.
satisfies badi 무엇?

Axioms: X badi X min at most 2 eta ez eduki even iff forall.
Kandidatu: s0 5 eta 6 multzo; s1 3, 5 eta 9 multzo; s2 2 eta 9 multzo; s3 1 eta 9 multzo.
Satisfies badi zer?

Axioms: X forall badi X iff min at ᎤᎪᏗᏗ 2 ᎠᎴ ᏝᏃ ᎤᎭ even.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 5 ᎠᎴ 6; s1 ᏭᏕᎵᎦ 3, 5 ᎠᎴ 9; s2 ᏭᏕᎵᎦ 2 ᎠᎴ 9; s3 ᏭᏕᎵᎦ 1 ᎠᎴ 9.
What satisfies badi?

Axioms: X forall badi X iff min at most 2 ama have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
Satisfies badi what?

Axioms: X badi X min at most 2 ыкӏи not have even iff forall.
Candidates: s0 5 ыкӏи 6 set; s1 3, 5 ыкӏи 9 set; s2 2 ыкӏи 9 set; s3 1 ыкӏи 9 set.
Satisfies badi сыд?

Axioms: X forall badi X iff min at most 2 thiab tsis have even.
Candidates: s0 set 5 thiab 6; s1 set 3, 5 thiab 9; s2 set 2 thiab 9; s3 set 1 thiab 9.
Satisfies badi what?

Axioms: X forall badi X iff min jeyou most 2 woi have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
Satisfies badi ining-jak?

Axioms: X forall badi X iff min at most 2 micha' ki'yo have even.
Candidates: s0 set 5 micha' 6; s1 set 3, 5 micha' 9; s2 set 2 micha' 9; s3 set 1 micha' 9.
Satisfies badi nanta?

Axioms: X badi X min at most 2 カ ソモ have even iff forall.
Candidates: s0 5 カ 6 set; s1 3, 5 カ 9 set; s2 2 カ 9 set; s3 1 カ 9 set.
Satisfies badi what?

Axioms: X forall badi X iff min at most 2 ынкъам not рытык even.
Candidates: s0 set 5 ынкъам 6; s1 set 3, 5 ынкъам 9; s2 set 2 ынкъам 9; s3 set 1 ынкъам 9.
Satisfies badi what?

Axioms: X forall badi X iff min at most 2 yéetel ma' have even.
Candidates: s0 set 5 yéetel 6; s1 set 3, 5 yéetel 9; s2 set 2 yéetel 9; s3 set 1 yéetel 9.
Satisfies badi what?

Axioms: X forall badi X iff min at most 2 not have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
Satisfies badi híli?

Axioms: X badi X min at most 2 na have even not iff forall.
Candidates: s0 5 na 6 set; s1 3, 5 na 9 set; s2 2 na 9 set; s3 1 na 9 set.
Satisfies badi what?

Axioms: X forall badi X iff min at most 2 nahániri have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
Satisfies badi what?

Axioms: X badi X min at most 2 not have even iff forall.
Candidates: s0 5 6 set; s1 3, 5 9 set; s2 2 9 set; s3 1 9 set.
Satisfies badi what?

Axioms: X forall badi X iff min at most 2 ǂʻá ǁʻàa have even.
Candidates: s0 set 5 ǂʻá 6; s1 set 3, 5 ǂʻá 9; s2 set 2 ǂʻá 9; s3 set 1 ǂʻá 9.
Satisfies badi what?

Axioms: X badi X min at most 2 not have even iff forall.
Candidates: s0 5 6 set; s1 3, 5 9 set; s2 2 9 set; s3 1 9 set.
Satisfies badi what?

Axioms: X forall badi X iff min at most 2 not have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
Satisfies badi what?

Axioms: X badi X min at most 2 not have even iff forall.
Candidates: s0 5 6 set; s1 3, 5 9 set; s2 2 9 set; s3 1 9 set.
Satisfies badi what?

Axioms: X forall badi X iff min at most 2 not have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
Satisfies badi what?

Axioms: X forall badi X iff min at most 2 inte have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
Satisfies badi tay?

Axiomes : X forall badi X ssi min au plus 2 et pas avoir plat.
Les candidats sont : s0 poser 5 et 6 ; s1 poser 3, 5 et 9 ; s2 poser 2 et 9 ; s3 poser 1 et 9.
Quoi satisfies badi ?

Aksiomo: X forall badi X iff min ĉe plej 2 kaj ne havi ebena.
Kandidato: s0 meti 5 kaj 6; s1 meti 3, 5 kaj 9; s2 meti 2 kaj 9; s3 meti 1 kaj 9.
Satisfies badi kio?

Axiómák: X forall badi X acsa min at legtöbb 2 és nem bír egyenletes.
Indulók: s0 set 5 és 6; s1 set 3, 5 és 9; s2 set 2 és 9; s3 set 1 és 9.
Satisfies badi melyik?

axioms:Xforallbadi:Xiffmin喺多數:2及不有更加.
候選人:s0set5及6; s1set3, 5及9; s2set2及9; s3set1及9.
satisfies:badi乜嘢?

Axioms: X forall badi X iff min at most 2 とぅ not have even.
Candidates: s0 set 5 とぅ 6; s1 set 3, 5 とぅ 9; s2 set 2 とぅ 9; s3 set 1 とぅ 9.
Satisfies badi what?

Аксиома: X forall badi X iff min at ең 2 және емес have да.
Үміткер: s0 жиын 5 және 6; s1 жиын 3, 5 және 9; s2 жиын 2 және 9; s3 жиын 1 және 9.
Satisfies badi не?

אַקְסְיוֹמָה: X forall badi X אםם min אֵצֶל רוב 2 וְ־ לא have ערב.
מועמדת: s0 הֵנִיח 5 וְ־ 6; s1 הֵנִיח 3, 5 וְ־ 9; s2 הֵנִיח 2 וְ־ 9; s3 הֵנִיח 1 וְ־ 9.
איזה satisfies badi?

Axioms: X forall badi X iff min at most 2 დო not have even.
Candidates: s0 set 5 დო 6; s1 set 3, 5 დო 9; s2 set 2 დო 9; s3 set 1 დო 9.
Satisfies badi what?

Aksioma-aksioma: X forall badi X iff min at most 2 dan tidak punya rata.
Kandidat: s0 memperkenalkan 5 dan 6; s1 memperkenalkan 3, 5 dan 9; s2 memperkenalkan 2 dan 9; s3 memperkenalkan 1 dan 9.
Satisfies badi apa?

ស្វ័យសត្យ:Xforallbadi:Xiffminatជាងគេ:2នឹងមិន...ទេមានសូម្បី.
បេក្ខជន:s0set5នឹង6; s1set3, 5នឹង9; s2set2នឹង9; s3set1នឹង9.
satisfies:badiអី?

ກົດຄວາມຈິງ:Xforallbadi:Xiffminທີ່...ທີ່ສຸດ:2ແລະບໍ່ມີeven.
ຜູ້ສະໝັກ:s0set5ແລະ6; s1set3, 5ແລະ9; s2set2ແລະ9; s3set1ແລະ9.
satisfies:badiຫຍັງ?

axioms: X badi X min వద్ద most 2 మరియు have చదునైన కాదు iff forall.
candidates: s0 5 మరియు 6 set; s1 3, 5 మరియు 9 set; s2 2 మరియు 9 set; s3 1 మరియు 9 set.
satisfies badi ఏమిటి?

Axioms: X forall badi X iff min at most 2 rárá have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
What satisfies badi?

Axioms: X badi X min at most 2 dawǫ́’ have even iff forall.
Candidates: s0 5 6 set; s1 3, 5 9 set; s2 2 9 set; s3 1 9 set.
Satisfies badi what?

axioms: X forall badi X iff min at most 2 ᐋᒃᑲ have even.
candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
satisfies badi what?

Axioms: X forall badi X iff min at most 2 not have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
Satisfies badi what?

Axioms: X forall badi X iff min at most 2 not have even.
Candidates: s0 set 5 6; s1 set 3, 5 9; s2 set 2 9; s3 set 1 9.
Satisfies badi what?

Axioms: X badi X min at most 2 have even not iff forall.
Candidates: s0 5 6 set; s1 3, 5 9 set; s2 2 9 set; s3 1 9 set.
Satisfies badi вуч?

The axioms are: X forall kuse X if and only if size at least 4 and min at most 3.
The candidates are: s0 set 3, 5, 8 and 9; s1 set 6 and 7; s2 set 6 and 8; s3 set 3 and 7.
What is the satisfies kuse?

Los axiomas son:
  - X para todo kuse: X si y sólo si tamaño en least: 4 y mínimo en la mayoría: 3
Los candidatos son: s0 se fija en 3, 5, 8 y 9; s1 se fija en 6 y 7; s2 se fija en 6 y 8; s3 se fija en 3 y 7.
¿Qué satisfies: kuse?

公理如下：X对任意取值都满足kuse：X当且仅当大小在least：4和最小值在大多数：3。
候选项如下：s0的集合是3、5、8和9；s1的集合是6和7；s2的集合是6和8；s3的集合是3和7。
satisfies：kuse什么？

Belitler: X kuse: X boyut at least: 4 ve min at çoğu: 3 iff forall.
Adaylar: s0 3, 5, 8 ve 9 koymak; s1 6 ve 7 koymak; s2 6 ve 8 koymak; s3 3 ve 7 koymak.
Satisfies: kuse ne?

Axioms: X forall kuse: X iff size katika least: 4 na min katika wengi: 3.
Wagombea ni: s0 seti 3, 5, 8 na 9; s1 seti 6 na 7; s2 seti 6 na 8; s3 seti 3 na 7.
Satisfies: kuse nini?

The axioms are: X forall kuse X if and only if size at least 4 and min at most 3.
The candidates are: s0 set 3, 5, 8 and 9; s1 set 6 and 7; s2 set 6 and 8; s3 set 3 and 7.
What is the satisfies kuse?

{axioms: [(forall X (iff (kuse X) (and (size_at_least 4) (min_at_most 3))))], candidates: [(set s0 [3 5 8 9]) (set s1 [6 7]) (set s2 [6 8]) (set s3 [3 7])], query: (which_satisfies kuse)}

Axiome:
  - X forall kuse X gdw. Größe an geringst 4 und min an die meisten 3
Die Kandidaten sind: s0 set 3, 5, 8 und 9; s1 set 6 und 7; s2 set 6 und 8; s3 set 3 und 7.
Was satisfies kuse?

Аксѝо̄м: X forall kuse X iff величѝна at minimalan 4 и min at većina 3.
Кандѝда̄т: s0 се̏т 3, 5, 8 и 9; s1 се̏т 6 и 7; s2 се̏т 6 и 8; s3 се̏т 3 и 7.
Satisfies kuse kakav?

Perusväitteet: X forall kuse X joss koko luona vähin 4 ja min luona useimmat 3.
Ehdokkaat: s0 set 3, 5, 8 ja 9; s1 set 6 ja 7; s2 set 6 ja 8; s3 set 3 ja 7.
Mikä satisfies kuse?

公理如下：X对任意取值都满足kuse：X当且仅当大小在least：4和最小值在大多数：3。
候选项如下：s0的集合是3、5、8和9；s1的集合是6和7；s2的集合是6和8；s3的集合是3和7。
satisfies：kuse什么？

公理:Xkuse:X大きさ...で最小の:4とmin...で大部分:3iffforall.
候補者:s03, 5, 8と9置く; s16と7置く; s26と8置く; s33と7置く.
satisfies:kuse何と?

Belitler: X kuse: X boyut at least: 4 ve min at çoğu: 3 iff forall.
Adaylar: s0 3, 5, 8 ve 9 koymak; s1 6 ve 7 koymak; s2 6 ve 8 koymak; s3 3 ve 7 koymak.
Satisfies: kuse ne?

بَدِيهِيَّة:
  - forall X iff kuse X مَقَاس عِنْد أَقَلَّ 4 وَـ min عِنْد أَكْثَر 3
مُرَشَّح: وَضَع s0 3، 5، 8 وَـ 9؛ وَضَع s1 6 وَـ 7؛ وَضَع s2 6 وَـ 8؛ وَضَع s3 3 وَـ 7.
satisfies kuse مَاذَا؟

Აქსიომები: X kuse X ზომა at least 4 და min at უმეტესობა 3 iff forall.
Კანდიდატები: s0 3, 5, 8 და 9 set; s1 6 და 7 set; s2 6 და 8 set; s3 3 და 7 set.
Satisfies kuse რა?

Axioms: forall X iff kuse X size i least 4 me min i nuinga 3.
Kaiwhakauru: whakawhenua s0 3, 5, 8 me 9; whakawhenua s1 6 me 7; whakawhenua s2 6 me 8; whakawhenua s3 3 me 7.
Satisfies kuse unutai?

Chân lý: X forall kuse X iff kích thước lúc least 4 và min lúc hầu hết 3.
Candidates: s0 để 3, 5, 8 và 9; s1 để 6 và 7; s2 để 6 và 8; s3 để 3 và 7.
Satisfies kuse gì?

สัจพจน์:Xforallkuse:Xiffขนาดที่least:4และminที่ส่วนใหญ่:3.
ผู้สมัคร:s0set3, 5, 8และ9; s1set6และ7; s2set6และ8; s3set3และ7.
satisfies:kuseอะไร?

axioms: X kuse X size at least 4 மற்றும் min at most 3 iff forall.
வேட்பாளர்: s0 3, 5, 8 மற்றும் 9 set; s1 6 மற்றும் 7 set; s2 6 மற்றும் 8 set; s3 3 மற்றும் 7 set.
satisfies kuse என்ன?

Axioms: X forall kuse: X iff size katika least: 4 na min katika wengi: 3.
Wagombea ni: s0 seti 3, 5, 8 na 9; s1 seti 6 na 7; s2 seti 6 na 8; s3 seti 3 na 7.
Satisfies: kuse nini?

Axioms: X kuse X size at least 4 dóó min at most 3 iff forall.
Candidates: s0 3, 5, 8 dóó 9 set; s1 6 dóó 7 set; s2 6 dóó 8 set; s3 3 dóó 7 set.
Satisfies kuse haʼátʼíísh?

Axioms: X kuse X size at least 4 aamma min at most 3 iff forall.
Candidates: s0 3, 5, 8 aamma 9 set; s1 6 aamma 7 set; s2 6 aamma 8 set; s3 3 aamma 7 set.
Satisfies kuse what?

Axioms: X forall kuse X iff size long least 4 na min long most 3.
Candidates: s0 set 3, 5, 8 na 9; s1 set 6 na 7; s2 set 6 na 8; s3 set 3 na 7.
Satisfies kuse what?

Axioms: X forall kuse X iff size at least 4 min at most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
Satisfies kuse kwèch?

Axioms: X forall kuse X iff size at least 4 а min at most 3.
Candidates: s0 set 3, 5, 8 а 9; s1 set 6 а 7; s2 set 6 а 8; s3 set 3 а 7.
Satisfies kuse фу?

공리: X kuse X 크기 at 가장 적게 4 min at 가장 3 iff forall.
후보자: s0 3, 5, 8 9 두다; s1 6 7 두다; s2 6 8 두다; s3 3 7 두다.
satisfies kuse 무엇?

Axioms: X kuse X tamaina at least 4 eta min at most 3 iff forall.
Kandidatu: s0 3, 5, 8 eta 9 multzo; s1 6 eta 7 multzo; s2 6 eta 8 multzo; s3 3 eta 7 multzo.
Satisfies kuse zer?

Axioms: X forall kuse X iff size at least 4 ᎠᎴ min at ᎤᎪᏗᏗ 3.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 3, 5, 8 ᎠᎴ 9; s1 ᏭᏕᎵᎦ 6 ᎠᎴ 7; s2 ᏭᏕᎵᎦ 6 ᎠᎴ 8; s3 ᏭᏕᎵᎦ 3 ᎠᎴ 7.
What satisfies kuse?

Axioms: X forall kuse X iff chhika at least 4 min at most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
Satisfies kuse what?

Axioms: X kuse X size at least 4 ыкӏи min at most 3 iff forall.
Candidates: s0 3, 5, 8 ыкӏи 9 set; s1 6 ыкӏи 7 set; s2 6 ыкӏи 8 set; s3 3 ыкӏи 7 set.
Satisfies kuse сыд?

Axioms: X forall kuse X iff size at least 4 thiab min at most 3.
Candidates: s0 set 3, 5, 8 thiab 9; s1 set 6 thiab 7; s2 set 6 thiab 8; s3 set 3 thiab 7.
Satisfies kuse what?

Axioms: X forall kuse X iff size jeyou wy krook 4 min jeyou most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
Satisfies kuse ining-jak?

Axioms: X forall kuse X iff size at least 4 micha' min at most 3.
Candidates: s0 set 3, 5, 8 micha' 9; s1 set 6 micha' 7; s2 set 6 micha' 8; s3 set 3 micha' 7.
Satisfies kuse nanta?

Axioms: X kuse X size at least 4 カ min at most 3 iff forall.
Candidates: s0 3, 5, 8 カ 9 set; s1 6 カ 7 set; s2 6 カ 8 set; s3 3 カ 7 set.
Satisfies kuse what?

Axioms: X forall kuse X iff size at least 4 ынкъам min at most 3.
Candidates: s0 set 3, 5, 8 ынкъам 9; s1 set 6 ынкъам 7; s2 set 6 ынкъам 8; s3 set 3 ынкъам 7.
Satisfies kuse what?

Axioms: X forall kuse X iff size at least 4 yéetel min at most 3.
Candidates: s0 set 3, 5, 8 yéetel 9; s1 set 6 yéetel 7; s2 set 6 yéetel 8; s3 set 3 yéetel 7.
Satisfies kuse what?

Axioms: X forall kuse X iff size at least 4 min at most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
Satisfies kuse híli?

Axioms: X kuse X size at least 4 na min at most 3 iff forall.
Candidates: s0 3, 5, 8 na 9 set; s1 6 na 7 set; s2 6 na 8 set; s3 3 na 7 set.
Satisfies kuse what?

Axioms: X forall kuse X iff size at least 4 min at most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
Satisfies kuse what?

Axioms: X kuse X size at least 4 min at most 3 iff forall.
Candidates: s0 3, 5, 8 9 set; s1 6 7 set; s2 6 8 set; s3 3 7 set.
Satisfies kuse what?

Axioms: X forall kuse X iff ʻǁnàhã at least 4 ǂʻá min at most 3.
Candidates: s0 set 3, 5, 8 ǂʻá 9; s1 set 6 ǂʻá 7; s2 set 6 ǂʻá 8; s3 set 3 ǂʻá 7.
Satisfies kuse what?

Axioms: X kuse X size at least 4 min at most 3 iff forall.
Candidates: s0 3, 5, 8 9 set; s1 6 7 set; s2 6 8 set; s3 3 7 set.
Satisfies kuse what?

Axioms: X forall kuse X iff size at least 4 min at most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
Satisfies kuse what?

Axioms: X kuse X size at least 4 min at most 3 iff forall.
Candidates: s0 3, 5, 8 9 set; s1 6 7 set; s2 6 8 set; s3 3 7 set.
Satisfies kuse what?

Axioms: X forall kuse X iff size at least 4 min at most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
Satisfies kuse what?

Axioms: X forall kuse X iff size at least 4 min at most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
Satisfies kuse tay?

Axiomes : X forall kuse X ssi taille au moindre 4 et min au plus 3.
Les candidats sont : s0 poser 3, 5, 8 et 9 ; s1 poser 6 et 7 ; s2 poser 6 et 8 ; s3 poser 3 et 7.
Quoi satisfies kuse ?

Aksiomo:
  - X forall kuse X iff grandeco ĉe plej malmulta 4 kaj min ĉe plej 3
Kandidato: s0 meti 3, 5, 8 kaj 9; s1 meti 6 kaj 7; s2 meti 6 kaj 8; s3 meti 3 kaj 7.
Satisfies kuse kio?

Axiómák: X forall kuse X acsa méret at legkisebb 4 és min at legtöbb 3.
Indulók: s0 set 3, 5, 8 és 9; s1 set 6 és 7; s2 set 6 és 8; s3 set 3 és 7.
Satisfies kuse melyik?

axioms:Xforallkuse:Xiffsize喺least:4及min喺多數:3.
候選人:s0set3, 5, 8及9; s1set6及7; s2set6及8; s3set3及7.
satisfies:kuse乜嘢?

Axioms: X forall kuse X iff size at least 4 とぅ min at most 3.
Candidates: s0 set 3, 5, 8 とぅ 9; s1 set 6 とぅ 7; s2 set 6 とぅ 8; s3 set 3 とぅ 7.
Satisfies kuse what?

Аксиома: X forall kuse X iff мөлшер at least 4 және min at ең 3.
Үміткер: s0 жиын 3, 5, 8 және 9; s1 жиын 6 және 7; s2 жиын 6 және 8; s3 жиын 3 және 7.
Satisfies kuse не?

אַקְסְיוֹמָה: X forall kuse X אםם גֹּדֶל אֵצֶל least 4 וְ־ min אֵצֶל רוב 3.
מועמדת: s0 הֵנִיח 3, 5, 8 וְ־ 9; s1 הֵנִיח 6 וְ־ 7; s2 הֵנִיח 6 וְ־ 8; s3 הֵנִיח 3 וְ־ 7.
איזה satisfies kuse?

Axioms: X forall kuse X iff size at least 4 დო min at most 3.
Candidates: s0 set 3, 5, 8 დო 9; s1 set 6 დო 7; s2 set 6 დო 8; s3 set 3 დო 7.
Satisfies kuse what?

Aksioma-aksioma: X forall kuse X iff ukuran at least 4 dan min at most 3.
Kandidat: s0 memperkenalkan 3, 5, 8 dan 9; s1 memperkenalkan 6 dan 7; s2 memperkenalkan 6 dan 8; s3 memperkenalkan 3 dan 7.
Satisfies kuse apa?

ស្វ័យសត្យ:Xforallkuse:Xiffទំហំatleast:4នឹងminatជាងគេ:3.
បេក្ខជន:s0set3, 5, 8នឹង9; s1set6នឹង7; s2set6នឹង8; s3set3នឹង7.
satisfies:kuseអី?

ກົດຄວາມຈິງ:Xforallkuse:Xiffຂະຫນາດທີ່least:4ແລະminທີ່...ທີ່ສຸດ:3.
ຜູ້ສະໝັກ:s0set3, 5, 8ແລະ9; s1set6ແລະ7; s2set6ແລະ8; s3set3ແລະ7.
satisfies:kuseຫຍັງ?

axioms: X kuse X size వద్ద least 4 మరియు min వద్ద most 3 iff forall.
candidates: s0 3, 5, 8 మరియు 9 set; s1 6 మరియు 7 set; s2 6 మరియు 8 set; s3 3 మరియు 7 set.
satisfies kuse ఏమిటి?

Axioms: X forall kuse X iff size at least 4 min at most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
What satisfies kuse?

Axioms: X kuse X size at least 4 min at most 3 iff forall.
Candidates: s0 3, 5, 8 9 set; s1 6 7 set; s2 6 8 set; s3 3 7 set.
Satisfies kuse what?

axioms: X forall kuse X iff size at least 4 min at most 3.
candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
satisfies kuse what?

Axioms: X forall kuse X iff size at least 4 min at most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
Satisfies kuse what?

Axioms: X forall kuse X iff size at least 4 min at most 3.
Candidates: s0 set 3, 5, 8 9; s1 set 6 7; s2 set 6 8; s3 set 3 7.
Satisfies kuse what?

Axioms: X kuse X size at least 4 min at most 3 iff forall.
Candidates: s0 3, 5, 8 9 set; s1 6 7 set; s2 6 8 set; s3 3 7 set.
Satisfies kuse вуч?

The axioms are:
  - X forall kido X if and only if does not sum even and min at most 4
The candidates are: s0 set 2, 7, 8 and 9; s1 set 1, 2, 3 and 5; s2 set 2, 4, 7, 8 and 9; s3 set 4, 7, 8 and 9.
What is the satisfies kido?

Los axiomas son:
  - X para todo kido: X si y sólo si no la suma even y mínimo en la mayoría: 4
Los candidatos son: s0 se fija en 2, 7, 8 y 9; s1 se fija en 1, 2, 3 y 5; s2 se fija en 2, 4, 7, 8 y 9; s3 se fija en 4, 7, 8 y 9.
¿Qué satisfies: kido?

公理如下：X对任意取值都满足kido：X当且仅当不的总和是even和最小值在大多数：4。
候选项如下：s0的集合是2、7、8和9；s1的集合是1、2、3和5；s2的集合是2、4、7、8和9；s3的集合是4、7、8和9。
satisfies：kido什么？

Belitler: X kido: X sum even değil ve min at çoğu: 4 iff forall.
Adaylar: s0 2, 7, 8 ve 9 koymak; s1 1, 2, 3 ve 5 koymak; s2 2, 4, 7, 8 ve 9 koymak; s3 4, 7, 8 ve 9 koymak.
Satisfies: kido ne?

Axioms: X forall kido: X iff si sum even na min katika wengi: 4.
Wagombea ni: s0 seti 2, 7, 8 na 9; s1 seti 1, 2, 3 na 5; s2 seti 2, 4, 7, 8 na 9; s3 seti 4, 7, 8 na 9.
Satisfies: kido nini?

The axioms are:
  - X forall kido X if and only if does not sum even and min at most 4
The candidates are: s0 set 2, 7, 8 and 9; s1 set 1, 2, 3 and 5; s2 set 2, 4, 7, 8 and 9; s3 set 4, 7, 8 and 9.
What is the satisfies kido?

{axioms: [(forall X (iff (kido X) (and (not (sum_even)) (min_at_most 4))))], candidates: [(set s0 [2 7 8 9]) (set s1 [1 2 3 5]) (set s2 [2 4 7 8 9]) (set s3 [4 7 8 9])], query: (which_satisfies kido)}

Axiome: X forall kido X gdw. nicht Summe eben und min an die meisten 4.
Die Kandidaten sind: s0 set 2, 7, 8 und 9; s1 set 1, 2, 3 und 5; s2 set 2, 4, 7, 8 und 9; s3 set 4, 7, 8 und 9.
Was satisfies kido?

Аксѝо̄м: X forall kido X iff не zbroj раван и min at većina 4.
Кандѝда̄т: s0 се̏т 2, 7, 8 и 9; s1 се̏т 1, 2, 3 и 5; s2 се̏т 2, 4, 7, 8 и 9; s3 се̏т 4, 7, 8 и 9.
Satisfies kido kakav?

Perusväitteet: X forall kido X joss ei summa tasainen ja min luona useimmat 4.
Ehdokkaat: s0 set 2, 7, 8 ja 9; s1 set 1, 2, 3 ja 5; s2 set 2, 4, 7, 8 ja 9; s3 set 4, 7, 8 ja 9.
Mikä satisfies kido?

公理如下：X对任意取值都满足kido：X当且仅当不的总和是even和最小值在大多数：4。
候选项如下：s0的集合是2、7、8和9；s1的集合是1、2、3和5；s2的集合是2、4、7、8和9；s3的集合是4、7、8和9。
satisfies：kido什么？

公理:Xkido:X総額平...ではないとmin...で大部分:4iffforall.
候補者:s02, 7, 8と9置く; s11, 2, 3と5置く; s22, 4, 7, 8と9置く; s34, 7, 8と9置く.
satisfies:kido何と?

Belitler: X kido: X sum even değil ve min at çoğu: 4 iff forall.
Adaylar: s0 2, 7, 8 ve 9 koymak; s1 1, 2, 3 ve 5 koymak; s2 2, 4, 7, 8 ve 9 koymak; s3 4, 7, 8 ve 9 koymak.
Satisfies: kido ne?

بَدِيهِيَّة:
  - forall X iff kido X لَا مَجْمُوع مُسَطَّح وَـ min عِنْد أَكْثَر 4
مُرَشَّح: وَضَع s0 2، 7، 8 وَـ 9؛ وَضَع s1 1، 2، 3 وَـ 5؛ وَضَع s2 2، 4، 7، 8 وَـ 9؛ وَضَع s3 4، 7، 8 وَـ 9.
satisfies kido مَاذَا؟

Აქსიომები: X kido X არ ჯამი კი და min at უმეტესობა 4 iff forall.
Კანდიდატები: s0 2, 7, 8 და 9 set; s1 1, 2, 3 და 5 set; s2 2, 4, 7, 8 და 9 set; s3 4, 7, 8 და 9 set.
Satisfies kido რა?

Axioms: forall X iff kido X kāore tapeke papatairite me min i nuinga 4.
Kaiwhakauru: whakawhenua s0 2, 7, 8 me 9; whakawhenua s1 1, 2, 3 me 5; whakawhenua s2 2, 4, 7, 8 me 9; whakawhenua s3 4, 7, 8 me 9.
Satisfies kido unutai?

Chân lý:
  - X forall kido X iff không tổng số bằng phẳng và min lúc hầu hết 4
Candidates: s0 để 2, 7, 8 và 9; s1 để 1, 2, 3 và 5; s2 để 2, 4, 7, 8 và 9; s3 để 4, 7, 8 và 9.
Satisfies kido gì?

สัจพจน์:Xforallkido:Xiffไม่sumแม้และminที่ส่วนใหญ่:4.
ผู้สมัคร:s0set2, 7, 8และ9; s1set1, 2, 3และ5; s2set2, 4, 7, 8และ9; s3set4, 7, 8และ9.
satisfies:kidoอะไร?

axioms: X kido X sum இரட்டைப்படை இல்லை மற்றும் min at most 4 iff forall.
வேட்பாளர்: s0 2, 7, 8 மற்றும் 9 set; s1 1, 2, 3 மற்றும் 5 set; s2 2, 4, 7, 8 மற்றும் 9 set; s3 4, 7, 8 மற்றும் 9 set.
satisfies kido என்ன?

Axioms: X forall kido: X iff si sum even na min katika wengi: 4.
Wagombea ni: s0 seti 2, 7, 8 na 9; s1 seti 1, 2, 3 na 5; s2 seti 2, 4, 7, 8 na 9; s3 seti 4, 7, 8 na 9.
Satisfies: kido nini?

Axioms: X kido X dooda sum ndi dóó min at most 4 iff forall.
Candidates: s0 2, 7, 8 dóó 9 set; s1 1, 2, 3 dóó 5 set; s2 2, 4, 7, 8 dóó 9 set; s3 4, 7, 8 dóó 9 set.
Satisfies kido haʼátʼíísh?

Axioms: X kido X sum even not aamma min at most 4 iff forall.
Candidates: s0 2, 7, 8 aamma 9 set; s1 1, 2, 3 aamma 5 set; s2 2, 4, 7, 8 aamma 9 set; s3 4, 7, 8 aamma 9 set.
Satisfies kido what?

Axioms: X forall kido X iff not sum even na min long most 4.
Candidates: s0 set 2, 7, 8 na 9; s1 set 1, 2, 3 na 5; s2 set 2, 4, 7, 8 na 9; s3 set 4, 7, 8 na 9.
Satisfies kido what?

Axioms: X forall kido X iff not sum even min at most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
Satisfies kido kwèch?

Axioms: X forall kido X iff sum even ца а min at most 4.
Candidates: s0 set 2, 7, 8 а 9; s1 set 1, 2, 3 а 5; s2 set 2, 4, 7, 8 а 9; s3 set 4, 7, 8 а 9.
Satisfies kido фу?

공리: X kido X 안 합계 고르다 min at 가장 4 iff forall.
후보자: s0 2, 7, 8 9 두다; s1 1, 2, 3 5 두다; s2 2, 4, 7, 8 9 두다; s3 4, 7, 8 9 두다.
satisfies kido 무엇?

Axioms: X kido X ez sum even eta min at most 4 iff forall.
Kandidatu: s0 2, 7, 8 eta 9 multzo; s1 1, 2, 3 eta 5 multzo; s2 2, 4, 7, 8 eta 9 multzo; s3 4, 7, 8 eta 9 multzo.
Satisfies kido zer?

Axioms: X forall kido X iff ᏝᏃ sum even ᎠᎴ min at ᎤᎪᏗᏗ 4.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 2, 7, 8 ᎠᎴ 9; s1 ᏭᏕᎵᎦ 1, 2, 3 ᎠᎴ 5; s2 ᏭᏕᎵᎦ 2, 4, 7, 8 ᎠᎴ 9; s3 ᏭᏕᎵᎦ 4, 7, 8 ᎠᎴ 9.
What satisfies kido?

Axioms: X forall kido X iff ama qullu even min at most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
Satisfies kido what?

Axioms: X kido X not sum even ыкӏи min at most 4 iff forall.
Candidates: s0 2, 7, 8 ыкӏи 9 set; s1 1, 2, 3 ыкӏи 5 set; s2 2, 4, 7, 8 ыкӏи 9 set; s3 4, 7, 8 ыкӏи 9 set.
Satisfies kido сыд?

Axioms: X forall kido X iff tsis sum even thiab min at most 4.
Candidates: s0 set 2, 7, 8 thiab 9; s1 set 1, 2, 3 thiab 5; s2 set 2, 4, 7, 8 thiab 9; s3 set 4, 7, 8 thiab 9.
Satisfies kido what?

Axioms: X forall kido X iff woi sum even min jeyou most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
Satisfies kido ining-jak?

Axioms: X forall kido X iff ki'yo sum even micha' min at most 4.
Candidates: s0 set 2, 7, 8 micha' 9; s1 set 1, 2, 3 micha' 5; s2 set 2, 4, 7, 8 micha' 9; s3 set 4, 7, 8 micha' 9.
Satisfies kido nanta?

Axioms: X kido X ソモ sum even カ min at most 4 iff forall.
Candidates: s0 2, 7, 8 カ 9 set; s1 1, 2, 3 カ 5 set; s2 2, 4, 7, 8 カ 9 set; s3 4, 7, 8 カ 9 set.
Satisfies kido what?

Axioms: X forall kido X iff not sum even ынкъам min at most 4.
Candidates: s0 set 2, 7, 8 ынкъам 9; s1 set 1, 2, 3 ынкъам 5; s2 set 2, 4, 7, 8 ынкъам 9; s3 set 4, 7, 8 ынкъам 9.
Satisfies kido what?

Axioms: X forall kido X iff ma' sum even yéetel min at most 4.
Candidates: s0 set 2, 7, 8 yéetel 9; s1 set 1, 2, 3 yéetel 5; s2 set 2, 4, 7, 8 yéetel 9; s3 set 4, 7, 8 yéetel 9.
Satisfies kido what?

Axioms: X forall kido X iff not sum even min at most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
Satisfies kido híli?

Axioms: X kido X sum even not na min at most 4 iff forall.
Candidates: s0 2, 7, 8 na 9 set; s1 1, 2, 3 na 5 set; s2 2, 4, 7, 8 na 9 set; s3 4, 7, 8 na 9 set.
Satisfies kido what?

Axioms: X forall kido X iff nahániri sum even min at most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
Satisfies kido what?

Axioms: X kido X not sum even min at most 4 iff forall.
Candidates: s0 2, 7, 8 9 set; s1 1, 2, 3 5 set; s2 2, 4, 7, 8 9 set; s3 4, 7, 8 9 set.
Satisfies kido what?

Axioms: X forall kido X iff ǁʻàa sum even ǂʻá min at most 4.
Candidates: s0 set 2, 7, 8 ǂʻá 9; s1 set 1, 2, 3 ǂʻá 5; s2 set 2, 4, 7, 8 ǂʻá 9; s3 set 4, 7, 8 ǂʻá 9.
Satisfies kido what?

Axioms: X kido X not sum even min at most 4 iff forall.
Candidates: s0 2, 7, 8 9 set; s1 1, 2, 3 5 set; s2 2, 4, 7, 8 9 set; s3 4, 7, 8 9 set.
Satisfies kido what?

Axioms: X forall kido X iff not sum even min at most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
Satisfies kido what?

Axioms: X kido X not sum even min at most 4 iff forall.
Candidates: s0 2, 7, 8 9 set; s1 1, 2, 3 5 set; s2 2, 4, 7, 8 9 set; s3 4, 7, 8 9 set.
Satisfies kido what?

Axioms: X forall kido X iff not sum even min at most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
Satisfies kido what?

Axioms: X forall kido X iff inte sum even min at most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
Satisfies kido tay?

Axiomes : X forall kido X ssi pas somme plat et min au plus 4.
Les candidats sont : s0 poser 2, 7, 8 et 9 ; s1 poser 1, 2, 3 et 5 ; s2 poser 2, 4, 7, 8 et 9 ; s3 poser 4, 7, 8 et 9.
Quoi satisfies kido ?

Aksiomo: X forall kido X iff ne sum ebena kaj min ĉe plej 4.
Kandidato: s0 meti 2, 7, 8 kaj 9; s1 meti 1, 2, 3 kaj 5; s2 meti 2, 4, 7, 8 kaj 9; s3 meti 4, 7, 8 kaj 9.
Satisfies kido kio?

Axiómák: X forall kido X acsa nem összeg egyenletes és min at legtöbb 4.
Indulók: s0 set 2, 7, 8 és 9; s1 set 1, 2, 3 és 5; s2 set 2, 4, 7, 8 és 9; s3 set 4, 7, 8 és 9.
Satisfies kido melyik?

axioms:Xforallkido:Xiff不sum更加及min喺多數:4.
候選人:s0set2, 7, 8及9; s1set1, 2, 3及5; s2set2, 4, 7, 8及9; s3set4, 7, 8及9.
satisfies:kido乜嘢?

Axioms: X forall kido X iff not sum even とぅ min at most 4.
Candidates: s0 set 2, 7, 8 とぅ 9; s1 set 1, 2, 3 とぅ 5; s2 set 2, 4, 7, 8 とぅ 9; s3 set 4, 7, 8 とぅ 9.
Satisfies kido what?

Аксиома: X forall kido X iff емес сом да және min at ең 4.
Үміткер: s0 жиын 2, 7, 8 және 9; s1 жиын 1, 2, 3 және 5; s2 жиын 2, 4, 7, 8 және 9; s3 жиын 4, 7, 8 және 9.
Satisfies kido не?

אַקְסְיוֹמָה: X forall kido X אםם לא סְכוּם ערב וְ־ min אֵצֶל רוב 4.
מועמדת: s0 הֵנִיח 2, 7, 8 וְ־ 9; s1 הֵנִיח 1, 2, 3 וְ־ 5; s2 הֵנִיח 2, 4, 7, 8 וְ־ 9; s3 הֵנִיח 4, 7, 8 וְ־ 9.
איזה satisfies kido?

Axioms: X forall kido X iff not sum even დო min at most 4.
Candidates: s0 set 2, 7, 8 დო 9; s1 set 1, 2, 3 დო 5; s2 set 2, 4, 7, 8 დო 9; s3 set 4, 7, 8 დო 9.
Satisfies kido what?

Aksioma-aksioma: X forall kido X iff tidak sum rata dan min at most 4.
Kandidat: s0 memperkenalkan 2, 7, 8 dan 9; s1 memperkenalkan 1, 2, 3 dan 5; s2 memperkenalkan 2, 4, 7, 8 dan 9; s3 memperkenalkan 4, 7, 8 dan 9.
Satisfies kido apa?

ស្វ័យសត្យ:Xforallkido:Xiffមិន...ទេផលបូកសូម្បីនឹងminatជាងគេ:4.
បេក្ខជន:s0set2, 7, 8នឹង9; s1set1, 2, 3នឹង5; s2set2, 4, 7, 8នឹង9; s3set4, 7, 8នឹង9.
satisfies:kidoអី?

ກົດຄວາມຈິງ:Xforallkido:Xiffບໍ່sum evenແລະminທີ່...ທີ່ສຸດ:4.
ຜູ້ສະໝັກ:s0set2, 7, 8ແລະ9; s1set1, 2, 3ແລະ5; s2set2, 4, 7, 8ແລະ9; s3set4, 7, 8ແລະ9.
satisfies:kidoຫຍັງ?

axioms: X kido X sum చదునైన కాదు మరియు min వద్ద most 4 iff forall.
candidates: s0 2, 7, 8 మరియు 9 set; s1 1, 2, 3 మరియు 5 set; s2 2, 4, 7, 8 మరియు 9 set; s3 4, 7, 8 మరియు 9 set.
satisfies kido ఏమిటి?

Axioms: X forall kido X iff rárá sum even min at most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
What satisfies kido?

Axioms: X kido X dawǫ́’ sum even min at most 4 iff forall.
Candidates: s0 2, 7, 8 9 set; s1 1, 2, 3 5 set; s2 2, 4, 7, 8 9 set; s3 4, 7, 8 9 set.
Satisfies kido what?

axioms: X forall kido X iff ᐋᒃᑲ sum even min at most 4.
candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
satisfies kido what?

Axioms: X forall kido X iff not sum even min at most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
Satisfies kido what?

Axioms: X forall kido X iff not sum even min at most 4.
Candidates: s0 set 2, 7, 8 9; s1 set 1, 2, 3 5; s2 set 2, 4, 7, 8 9; s3 set 4, 7, 8 9.
Satisfies kido what?

Axioms: X kido X sum even not min at most 4 iff forall.
Candidates: s0 2, 7, 8 9 set; s1 1, 2, 3 5 set; s2 2, 4, 7, 8 9 set; s3 4, 7, 8 9 set.
Satisfies kido вуч?

The axioms are: X forall tizi X if and only if contains 9 and has even.
The candidates are: s0 set 1, 3 and 9; s1 set 1 and 4; s2 set 4, 5, 8 and 9; s3 set 2, 5 and 7.
What is the satisfies tizi?

Los axiomas son: X para todo tizi: X si y sólo si contiene: 9 y tiene even.
Los candidatos son: s0 se fija en 1, 3 y 9; s1 se fija en 1 y 4; s2 se fija en 4, 5, 8 y 9; s3 se fija en 2, 5 y 7.
¿Qué satisfies: tizi?

公理如下：X对任意取值都满足tizi：X当且仅当包含：9和有even。
候选项如下：s0的集合是1、3和9；s1的集合是1和4；s2的集合是4、5、8和9；s3的集合是2、5和7。
satisfies：tizi什么？

Belitler: X tizi: X contains: 9 ve sahiptir even iff forall.
Adaylar: s0 1, 3 ve 9 koymak; s1 1 ve 4 koymak; s2 4, 5, 8 ve 9 koymak; s3 2, 5 ve 7 koymak.
Satisfies: tizi ne?

Axioms: X forall tizi: X iff contains: 9 na ina even.
Wagombea ni: s0 seti 1, 3 na 9; s1 seti 1 na 4; s2 seti 4, 5, 8 na 9; s3 seti 2, 5 na 7.
Satisfies: tizi nini?

The axioms are: X forall tizi X if and only if contains 9 and has even.
The candidates are: s0 set 1, 3 and 9; s1 set 1 and 4; s2 set 4, 5, 8 and 9; s3 set 2, 5 and 7.
What is the satisfies tizi?

{axioms: [(forall X (iff (tizi X) (and (contains 9) (has_even))))], candidates: [(set s0 [1 3 9]) (set s1 [1 4]) (set s2 [4 5 8 9]) (set s3 [2 5 7])], query: (which_satisfies tizi)}

Axiome: X forall tizi X gdw. contains 9 und haben eben.
Die Kandidaten sind: s0 set 1, 3 und 9; s1 set 1 und 4; s2 set 4, 5, 8 und 9; s3 set 2, 5 und 7.
Was satisfies tizi?

Аксѝо̄м: X forall tizi X iff contains 9 и имати раван.
Кандѝда̄т: s0 се̏т 1, 3 и 9; s1 се̏т 1 и 4; s2 се̏т 4, 5, 8 и 9; s3 се̏т 2, 5 и 7.
Satisfies tizi kakav?

Perusväitteet: X forall tizi X joss contains 9 ja omistaa tasainen.
Ehdokkaat: s0 set 1, 3 ja 9; s1 set 1 ja 4; s2 set 4, 5, 8 ja 9; s3 set 2, 5 ja 7.
Mikä satisfies tizi?

公理如下：X对任意取值都满足tizi：X当且仅当包含：9和有even。
候选项如下：s0的集合是1、3和9；s1的集合是1和4；s2的集合是4、5、8和9；s3的集合是2、5和7。
satisfies：tizi什么？

公理:Xtizi:Xcontains:9とhave平iffforall.
候補者:s01, 3と9置く; s11と4置く; s24, 5, 8と9置く; s32, 5と7置く.
satisfies:tizi何と?

Belitler: X tizi: X contains: 9 ve sahiptir even iff forall.
Adaylar: s0 1, 3 ve 9 koymak; s1 1 ve 4 koymak; s2 4, 5, 8 ve 9 koymak; s3 2, 5 ve 7 koymak.
Satisfies: tizi ne?

بَدِيهِيَّة: forall X iff tizi X contains 9 وَـ مَلَكَ مُسَطَّح.
مُرَشَّح: وَضَع s0 1، 3 وَـ 9؛ وَضَع s1 1 وَـ 4؛ وَضَع s2 4، 5، 8 وَـ 9؛ وَضَع s3 2، 5 وَـ 7.
satisfies tizi مَاذَا؟

Აქსიომები: X tizi X contains 9 და ფლობს კი iff forall.
Კანდიდატები: s0 1, 3 და 9 set; s1 1 და 4 set; s2 4, 5, 8 და 9 set; s3 2, 5 და 7 set.
Satisfies tizi რა?

Axioms: forall X iff tizi X contains 9 me whai papatairite.
Kaiwhakauru: whakawhenua s0 1, 3 me 9; whakawhenua s1 1 me 4; whakawhenua s2 4, 5, 8 me 9; whakawhenua s3 2, 5 me 7.
Satisfies tizi unutai?

Chân lý: X forall tizi X iff contains 9 và có bằng phẳng.
Candidates: s0 để 1, 3 và 9; s1 để 1 và 4; s2 để 4, 5, 8 và 9; s3 để 2, 5 và 7.
Satisfies tizi gì?

สัจพจน์:Xforalltizi:Xiffcontains:9และมีแม้.
ผู้สมัคร:s0set1, 3และ9; s1set1และ4; s2set4, 5, 8และ9; s3set2, 5และ7.
satisfies:tiziอะไร?

axioms: X tizi X contains 9 மற்றும் have இரட்டைப்படை iff forall.
வேட்பாளர்: s0 1, 3 மற்றும் 9 set; s1 1 மற்றும் 4 set; s2 4, 5, 8 மற்றும் 9 set; s3 2, 5 மற்றும் 7 set.
satisfies tizi என்ன?

Axioms: X forall tizi: X iff contains: 9 na ina even.
Wagombea ni: s0 seti 1, 3 na 9; s1 seti 1 na 4; s2 seti 4, 5, 8 na 9; s3 seti 2, 5 na 7.
Satisfies: tizi nini?

Axioms: X tizi X contains 9 dóó bee hólǫ́ ndi iff forall.
Candidates: s0 1, 3 dóó 9 set; s1 1 dóó 4 set; s2 4, 5, 8 dóó 9 set; s3 2, 5 dóó 7 set.
Satisfies tizi haʼátʼíísh?

Axioms: X tizi X contains 9 aamma qar even iff forall.
Candidates: s0 1, 3 aamma 9 set; s1 1 aamma 4 set; s2 4, 5, 8 aamma 9 set; s3 2, 5 aamma 7 set.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 na have even.
Candidates: s0 set 1, 3 na 9; s1 set 1 na 4; s2 set 4, 5, 8 na 9; s3 set 2, 5 na 7.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
Satisfies tizi kwèch?

Axioms: X forall tizi X iff contains 9 а have even.
Candidates: s0 set 1, 3 а 9; s1 set 1 а 4; s2 set 4, 5, 8 а 9; s3 set 2, 5 а 7.
Satisfies tizi фу?

공리: X tizi X contains 9 있다 고르다 iff forall.
후보자: s0 1, 3 9 두다; s1 1 4 두다; s2 4, 5, 8 9 두다; s3 2, 5 7 두다.
satisfies tizi 무엇?

Axioms: X tizi X contains 9 eta eduki even iff forall.
Kandidatu: s0 1, 3 eta 9 multzo; s1 1 eta 4 multzo; s2 4, 5, 8 eta 9 multzo; s3 2, 5 eta 7 multzo.
Satisfies tizi zer?

Axioms: X forall tizi X iff contains 9 ᎠᎴ ᎤᎭ even.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 1, 3 ᎠᎴ 9; s1 ᏭᏕᎵᎦ 1 ᎠᎴ 4; s2 ᏭᏕᎵᎦ 4, 5, 8 ᎠᎴ 9; s3 ᏭᏕᎵᎦ 2, 5 ᎠᎴ 7.
What satisfies tizi?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
Satisfies tizi what?

Axioms: X tizi X contains 9 ыкӏи have even iff forall.
Candidates: s0 1, 3 ыкӏи 9 set; s1 1 ыкӏи 4 set; s2 4, 5, 8 ыкӏи 9 set; s3 2, 5 ыкӏи 7 set.
Satisfies tizi сыд?

Axioms: X forall tizi X iff contains 9 thiab have even.
Candidates: s0 set 1, 3 thiab 9; s1 set 1 thiab 4; s2 set 4, 5, 8 thiab 9; s3 set 2, 5 thiab 7.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
Satisfies tizi ining-jak?

Axioms: X forall tizi X iff contains 9 micha' have even.
Candidates: s0 set 1, 3 micha' 9; s1 set 1 micha' 4; s2 set 4, 5, 8 micha' 9; s3 set 2, 5 micha' 7.
Satisfies tizi nanta?

Axioms: X tizi X contains 9 カ have even iff forall.
Candidates: s0 1, 3 カ 9 set; s1 1 カ 4 set; s2 4, 5, 8 カ 9 set; s3 2, 5 カ 7 set.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 ынкъам рытык even.
Candidates: s0 set 1, 3 ынкъам 9; s1 set 1 ынкъам 4; s2 set 4, 5, 8 ынкъам 9; s3 set 2, 5 ынкъам 7.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 yéetel have even.
Candidates: s0 set 1, 3 yéetel 9; s1 set 1 yéetel 4; s2 set 4, 5, 8 yéetel 9; s3 set 2, 5 yéetel 7.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
Satisfies tizi híli?

Axioms: X tizi X contains 9 na have even iff forall.
Candidates: s0 1, 3 na 9 set; s1 1 na 4 set; s2 4, 5, 8 na 9 set; s3 2, 5 na 7 set.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
Satisfies tizi what?

Axioms: X tizi X contains 9 have even iff forall.
Candidates: s0 1, 3 9 set; s1 1 4 set; s2 4, 5, 8 9 set; s3 2, 5 7 set.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 ǂʻá have even.
Candidates: s0 set 1, 3 ǂʻá 9; s1 set 1 ǂʻá 4; s2 set 4, 5, 8 ǂʻá 9; s3 set 2, 5 ǂʻá 7.
Satisfies tizi what?

Axioms: X tizi X contains 9 have even iff forall.
Candidates: s0 1, 3 9 set; s1 1 4 set; s2 4, 5, 8 9 set; s3 2, 5 7 set.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
Satisfies tizi what?

Axioms: X tizi X contains 9 have even iff forall.
Candidates: s0 1, 3 9 set; s1 1 4 set; s2 4, 5, 8 9 set; s3 2, 5 7 set.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
Satisfies tizi tay?

Axiomes : X forall tizi X ssi contains 9 et avoir plat.
Les candidats sont : s0 poser 1, 3 et 9 ; s1 poser 1 et 4 ; s2 poser 4, 5, 8 et 9 ; s3 poser 2, 5 et 7.
Quoi satisfies tizi ?

Aksiomo: X forall tizi X iff contains 9 kaj havi ebena.
Kandidato: s0 meti 1, 3 kaj 9; s1 meti 1 kaj 4; s2 meti 4, 5, 8 kaj 9; s3 meti 2, 5 kaj 7.
Satisfies tizi kio?

Axiómák: X forall tizi X acsa contains 9 és bír egyenletes.
Indulók: s0 set 1, 3 és 9; s1 set 1 és 4; s2 set 4, 5, 8 és 9; s3 set 2, 5 és 7.
Satisfies tizi melyik?

axioms:Xforalltizi:Xiffcontains:9及有更加.
候選人:s0set1, 3及9; s1set1及4; s2set4, 5, 8及9; s3set2, 5及7.
satisfies:tizi乜嘢?

Axioms: X forall tizi X iff contains 9 とぅ have even.
Candidates: s0 set 1, 3 とぅ 9; s1 set 1 とぅ 4; s2 set 4, 5, 8 とぅ 9; s3 set 2, 5 とぅ 7.
Satisfies tizi what?

Аксиома: X forall tizi X iff contains 9 және have да.
Үміткер: s0 жиын 1, 3 және 9; s1 жиын 1 және 4; s2 жиын 4, 5, 8 және 9; s3 жиын 2, 5 және 7.
Satisfies tizi не?

אַקְסְיוֹמָה: X forall tizi X אםם contains 9 וְ־ have ערב.
מועמדת: s0 הֵנִיח 1, 3 וְ־ 9; s1 הֵנִיח 1 וְ־ 4; s2 הֵנִיח 4, 5, 8 וְ־ 9; s3 הֵנִיח 2, 5 וְ־ 7.
איזה satisfies tizi?

Axioms: X forall tizi X iff contains 9 დო have even.
Candidates: s0 set 1, 3 დო 9; s1 set 1 დო 4; s2 set 4, 5, 8 დო 9; s3 set 2, 5 დო 7.
Satisfies tizi what?

Aksioma-aksioma: X forall tizi X iff contains 9 dan punya rata.
Kandidat: s0 memperkenalkan 1, 3 dan 9; s1 memperkenalkan 1 dan 4; s2 memperkenalkan 4, 5, 8 dan 9; s3 memperkenalkan 2, 5 dan 7.
Satisfies tizi apa?

ស្វ័យសត្យ:Xforalltizi:Xiffcontains:9នឹងមានសូម្បី.
បេក្ខជន:s0set1, 3នឹង9; s1set1នឹង4; s2set4, 5, 8នឹង9; s3set2, 5នឹង7.
satisfies:tiziអី?

ກົດຄວາມຈິງ:Xforalltizi:Xiffcontains:9ແລະມີeven.
ຜູ້ສະໝັກ:s0set1, 3ແລະ9; s1set1ແລະ4; s2set4, 5, 8ແລະ9; s3set2, 5ແລະ7.
satisfies:tiziຫຍັງ?

axioms: X tizi X contains 9 మరియు have చదునైన iff forall.
candidates: s0 1, 3 మరియు 9 set; s1 1 మరియు 4 set; s2 4, 5, 8 మరియు 9 set; s3 2, 5 మరియు 7 set.
satisfies tizi ఏమిటి?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
What satisfies tizi?

Axioms: X tizi X contains 9 have even iff forall.
Candidates: s0 1, 3 9 set; s1 1 4 set; s2 4, 5, 8 9 set; s3 2, 5 7 set.
Satisfies tizi what?

axioms: X forall tizi X iff contains 9 have even.
candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
satisfies tizi what?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
Satisfies tizi what?

Axioms: X forall tizi X iff contains 9 have even.
Candidates: s0 set 1, 3 9; s1 set 1 4; s2 set 4, 5, 8 9; s3 set 2, 5 7.
Satisfies tizi what?

Axioms: X tizi X contains 9 have even iff forall.
Candidates: s0 1, 3 9 set; s1 1 4 set; s2 4, 5, 8 9 set; s3 2, 5 7 set.
Satisfies tizi вуч?

The axioms are: X forall tari X if and only if has odd and does not has even.
The candidates are: s0 set 3 and 5; s1 set 1, 2, 5, 6 and 9; s2 set 1, 2, 6, 7 and 8; s3 set 1 and 8.
What is the satisfies tari?

Los axiomas son: X para todo tari: X si y sólo si tiene odd y no tiene even.
Los candidatos son: s0 se fija en 3 y 5; s1 se fija en 1, 2, 5, 6 y 9; s2 se fija en 1, 2, 6, 7 y 8; s3 se fija en 1 y 8.
¿Qué satisfies: tari?

公理如下：X对任意取值都满足tari：X当且仅当有odd和不有even。
候选项如下：s0的集合是3和5；s1的集合是1、2、5、6和9；s2的集合是1、2、6、7和8；s3的集合是1和8。
satisfies：tari什么？

Belitler: X tari: X sahiptir odd ve sahiptir even değil iff forall.
Adaylar: s0 3 ve 5 koymak; s1 1, 2, 5, 6 ve 9 koymak; s2 1, 2, 6, 7 ve 8 koymak; s3 1 ve 8 koymak.
Satisfies: tari ne?

Axioms: X forall tari: X iff ina odd na si ina even.
Wagombea ni: s0 seti 3 na 5; s1 seti 1, 2, 5, 6 na 9; s2 seti 1, 2, 6, 7 na 8; s3 seti 1 na 8.
Satisfies: tari nini?

The axioms are: X forall tari X if and only if has odd and does not has even.
The candidates are: s0 set 3 and 5; s1 set 1, 2, 5, 6 and 9; s2 set 1, 2, 6, 7 and 8; s3 set 1 and 8.
What is the satisfies tari?

{axioms: [(forall X (iff (tari X) (and (has_odd) (not (has_even)))))], candidates: [(set s0 [3 5]) (set s1 [1 2 5 6 9]) (set s2 [1 2 6 7 8]) (set s3 [1 8])], query: (which_satisfies tari)}

Axiome: X forall tari X gdw. haben seltsam und nicht haben eben.
Die Kandidaten sind: s0 set 3 und 5; s1 set 1, 2, 5, 6 und 9; s2 set 1, 2, 6, 7 und 8; s3 set 1 und 8.
Was satisfies tari?

Аксѝо̄м: X forall tari X iff имати непаран и не имати раван.
Кандѝда̄т: s0 се̏т 3 и 5; s1 се̏т 1, 2, 5, 6 и 9; s2 се̏т 1, 2, 6, 7 и 8; s3 се̏т 1 и 8.
Satisfies tari kakav?

Perusväitteet: X forall tari X joss omistaa outo ja ei omistaa tasainen.
Ehdokkaat: s0 set 3 ja 5; s1 set 1, 2, 5, 6 ja 9; s2 set 1, 2, 6, 7 ja 8; s3 set 1 ja 8.
Mikä satisfies tari?

公理如下：X对任意取值都满足tari：X当且仅当有odd和不有even。
候选项如下：s0的集合是3和5；s1的集合是1、2、5、6和9；s2的集合是1、2、6、7和8；s3的集合是1和8。
satisfies：tari什么？

公理:Xtari:Xhave変なとhave平...ではないiffforall.
候補者:s03と5置く; s11, 2, 5, 6と9置く; s21, 2, 6, 7と8置く; s31と8置く.
satisfies:tari何と?

Belitler: X tari: X sahiptir odd ve sahiptir even değil iff forall.
Adaylar: s0 3 ve 5 koymak; s1 1, 2, 5, 6 ve 9 koymak; s2 1, 2, 6, 7 ve 8 koymak; s3 1 ve 8 koymak.
Satisfies: tari ne?

بَدِيهِيَّة: forall X iff tari X مَلَكَ فَرْدِيّ وَـ لَا مَلَكَ مُسَطَّح.
مُرَشَّح: وَضَع s0 3 وَـ 5؛ وَضَع s1 1، 2، 5، 6 وَـ 9؛ وَضَع s2 1، 2، 6، 7 وَـ 8؛ وَضَع s3 1 وَـ 8.
satisfies tari مَاذَا؟

Აქსიომები: X tari X ფლობს უცნაური და არ ფლობს კი iff forall.
Კანდიდატები: s0 3 და 5 set; s1 1, 2, 5, 6 და 9 set; s2 1, 2, 6, 7 და 8 set; s3 1 და 8 set.
Satisfies tari რა?

Axioms: forall X iff tari X whai makere me kāore whai papatairite.
Kaiwhakauru: whakawhenua s0 3 me 5; whakawhenua s1 1, 2, 5, 6 me 9; whakawhenua s2 1, 2, 6, 7 me 8; whakawhenua s3 1 me 8.
Satisfies tari unutai?

Chân lý: X forall tari X iff có kỳ cục và không có bằng phẳng.
Candidates: s0 để 3 và 5; s1 để 1, 2, 5, 6 và 9; s2 để 1, 2, 6, 7 và 8; s3 để 1 và 8.
Satisfies tari gì?

สัจพจน์:Xforalltari:Xiffมีคี่และไม่มีแม้.
ผู้สมัคร:s0set3และ5; s1set1, 2, 5, 6และ9; s2set1, 2, 6, 7และ8; s3set1และ8.
satisfies:tariอะไร?

axioms:
  - X tari X have ஒற்றைப்படை மற்றும் have இரட்டைப்படை இல்லை iff forall
வேட்பாளர்: s0 3 மற்றும் 5 set; s1 1, 2, 5, 6 மற்றும் 9 set; s2 1, 2, 6, 7 மற்றும் 8 set; s3 1 மற்றும் 8 set.
satisfies tari என்ன?

Axioms: X forall tari: X iff ina odd na si ina even.
Wagombea ni: s0 seti 3 na 5; s1 seti 1, 2, 5, 6 na 9; s2 seti 1, 2, 6, 7 na 8; s3 seti 1 na 8.
Satisfies: tari nini?

Axioms: X tari X bee hólǫ́ odd dóó dooda bee hólǫ́ ndi iff forall.
Candidates: s0 3 dóó 5 set; s1 1, 2, 5, 6 dóó 9 set; s2 1, 2, 6, 7 dóó 8 set; s3 1 dóó 8 set.
Satisfies tari haʼátʼíísh?

Axioms: X tari X qar odd aamma qar even not iff forall.
Candidates: s0 3 aamma 5 set; s1 1, 2, 5, 6 aamma 9 set; s2 1, 2, 6, 7 aamma 8 set; s3 1 aamma 8 set.
Satisfies tari what?

Axioms: X forall tari X iff have odd na not have even.
Candidates: s0 set 3 na 5; s1 set 1, 2, 5, 6 na 9; s2 set 1, 2, 6, 7 na 8; s3 set 1 na 8.
Satisfies tari what?

Axioms: X forall tari X iff have odd not have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
Satisfies tari kwèch?

Axioms: X forall tari X iff have odd а have even ца.
Candidates: s0 set 3 а 5; s1 set 1, 2, 5, 6 а 9; s2 set 1, 2, 6, 7 а 8; s3 set 1 а 8.
Satisfies tari фу?

공리: X tari X 있다 기수의 안 있다 고르다 iff forall.
후보자: s0 3 5 두다; s1 1, 2, 5, 6 9 두다; s2 1, 2, 6, 7 8 두다; s3 1 8 두다.
satisfies tari 무엇?

Axioms: X tari X eduki odd eta ez eduki even iff forall.
Kandidatu: s0 3 eta 5 multzo; s1 1, 2, 5, 6 eta 9 multzo; s2 1, 2, 6, 7 eta 8 multzo; s3 1 eta 8 multzo.
Satisfies tari zer?

Axioms: X forall tari X iff ᎤᎭ odd ᎠᎴ ᏝᏃ ᎤᎭ even.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 3 ᎠᎴ 5; s1 ᏭᏕᎵᎦ 1, 2, 5, 6 ᎠᎴ 9; s2 ᏭᏕᎵᎦ 1, 2, 6, 7 ᎠᎴ 8; s3 ᏭᏕᎵᎦ 1 ᎠᎴ 8.
What satisfies tari?

Axioms: X forall tari X iff have odd ama have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
Satisfies tari what?

Axioms: X tari X have odd ыкӏи not have even iff forall.
Candidates: s0 3 ыкӏи 5 set; s1 1, 2, 5, 6 ыкӏи 9 set; s2 1, 2, 6, 7 ыкӏи 8 set; s3 1 ыкӏи 8 set.
Satisfies tari сыд?

Axioms: X forall tari X iff have odd thiab tsis have even.
Candidates: s0 set 3 thiab 5; s1 set 1, 2, 5, 6 thiab 9; s2 set 1, 2, 6, 7 thiab 8; s3 set 1 thiab 8.
Satisfies tari what?

Axioms: X forall tari X iff have odd woi have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
Satisfies tari ining-jak?

Axioms: X forall tari X iff have odd micha' ki'yo have even.
Candidates: s0 set 3 micha' 5; s1 set 1, 2, 5, 6 micha' 9; s2 set 1, 2, 6, 7 micha' 8; s3 set 1 micha' 8.
Satisfies tari nanta?

Axioms: X tari X have odd カ ソモ have even iff forall.
Candidates: s0 3 カ 5 set; s1 1, 2, 5, 6 カ 9 set; s2 1, 2, 6, 7 カ 8 set; s3 1 カ 8 set.
Satisfies tari what?

Axioms: X forall tari X iff рытык odd ынкъам not рытык even.
Candidates: s0 set 3 ынкъам 5; s1 set 1, 2, 5, 6 ынкъам 9; s2 set 1, 2, 6, 7 ынкъам 8; s3 set 1 ынкъам 8.
Satisfies tari what?

Axioms: X forall tari X iff have odd yéetel ma' have even.
Candidates: s0 set 3 yéetel 5; s1 set 1, 2, 5, 6 yéetel 9; s2 set 1, 2, 6, 7 yéetel 8; s3 set 1 yéetel 8.
Satisfies tari what?

Axioms: X forall tari X iff have odd not have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
Satisfies tari híli?

Axioms: X tari X have odd na have even not iff forall.
Candidates: s0 3 na 5 set; s1 1, 2, 5, 6 na 9 set; s2 1, 2, 6, 7 na 8 set; s3 1 na 8 set.
Satisfies tari what?

Axioms: X forall tari X iff have odd nahániri have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
Satisfies tari what?

Axioms: X tari X have odd not have even iff forall.
Candidates: s0 3 5 set; s1 1, 2, 5, 6 9 set; s2 1, 2, 6, 7 8 set; s3 1 8 set.
Satisfies tari what?

Axioms: X forall tari X iff have odd ǂʻá ǁʻàa have even.
Candidates: s0 set 3 ǂʻá 5; s1 set 1, 2, 5, 6 ǂʻá 9; s2 set 1, 2, 6, 7 ǂʻá 8; s3 set 1 ǂʻá 8.
Satisfies tari what?

Axioms: X tari X have odd not have even iff forall.
Candidates: s0 3 5 set; s1 1, 2, 5, 6 9 set; s2 1, 2, 6, 7 8 set; s3 1 8 set.
Satisfies tari what?

Axioms: X forall tari X iff have odd not have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
Satisfies tari what?

Axioms: X tari X have odd not have even iff forall.
Candidates: s0 3 5 set; s1 1, 2, 5, 6 9 set; s2 1, 2, 6, 7 8 set; s3 1 8 set.
Satisfies tari what?

Axioms: X forall tari X iff have odd not have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
Satisfies tari what?

Axioms: X forall tari X iff have odd inte have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
Satisfies tari tay?

Axiomes : X forall tari X ssi avoir bizarre et pas avoir plat.
Les candidats sont : s0 poser 3 et 5 ; s1 poser 1, 2, 5, 6 et 9 ; s2 poser 1, 2, 6, 7 et 8 ; s3 poser 1 et 8.
Quoi satisfies tari ?

Aksiomo: X forall tari X iff havi stranga kaj ne havi ebena.
Kandidato: s0 meti 3 kaj 5; s1 meti 1, 2, 5, 6 kaj 9; s2 meti 1, 2, 6, 7 kaj 8; s3 meti 1 kaj 8.
Satisfies tari kio?

Axiómák: X forall tari X acsa bír furcsa és nem bír egyenletes.
Indulók: s0 set 3 és 5; s1 set 1, 2, 5, 6 és 9; s2 set 1, 2, 6, 7 és 8; s3 set 1 és 8.
Satisfies tari melyik?

axioms:Xforalltari:Xiff有odd及不有更加.
候選人:s0set3及5; s1set1, 2, 5, 6及9; s2set1, 2, 6, 7及8; s3set1及8.
satisfies:tari乜嘢?

Axioms: X forall tari X iff have odd とぅ not have even.
Candidates: s0 set 3 とぅ 5; s1 set 1, 2, 5, 6 とぅ 9; s2 set 1, 2, 6, 7 とぅ 8; s3 set 1 とぅ 8.
Satisfies tari what?

Аксиома: X forall tari X iff have odd және емес have да.
Үміткер: s0 жиын 3 және 5; s1 жиын 1, 2, 5, 6 және 9; s2 жиын 1, 2, 6, 7 және 8; s3 жиын 1 және 8.
Satisfies tari не?

אַקְסְיוֹמָה: X forall tari X אםם have משונה וְ־ לא have ערב.
מועמדת: s0 הֵנִיח 3 וְ־ 5; s1 הֵנִיח 1, 2, 5, 6 וְ־ 9; s2 הֵנִיח 1, 2, 6, 7 וְ־ 8; s3 הֵנִיח 1 וְ־ 8.
איזה satisfies tari?

Axioms: X forall tari X iff have odd დო not have even.
Candidates: s0 set 3 დო 5; s1 set 1, 2, 5, 6 დო 9; s2 set 1, 2, 6, 7 დო 8; s3 set 1 დო 8.
Satisfies tari what?

Aksioma-aksioma: X forall tari X iff punya ganjil dan tidak punya rata.
Kandidat: s0 memperkenalkan 3 dan 5; s1 memperkenalkan 1, 2, 5, 6 dan 9; s2 memperkenalkan 1, 2, 6, 7 dan 8; s3 memperkenalkan 1 dan 8.
Satisfies tari apa?

ស្វ័យសត្យ:Xforalltari:Xiffមានសេសនឹងមិន...ទេមានសូម្បី.
បេក្ខជន:s0set3នឹង5; s1set1, 2, 5, 6នឹង9; s2set1, 2, 6, 7នឹង8; s3set1នឹង8.
satisfies:tariអី?

ກົດຄວາມຈິງ:Xforalltari:Xiffມີoddແລະບໍ່ມີeven.
ຜູ້ສະໝັກ:s0set3ແລະ5; s1set1, 2, 5, 6ແລະ9; s2set1, 2, 6, 7ແລະ8; s3set1ແລະ8.
satisfies:tariຫຍັງ?

axioms: X tari X have విలక్షణమైన మరియు have చదునైన కాదు iff forall.
candidates: s0 3 మరియు 5 set; s1 1, 2, 5, 6 మరియు 9 set; s2 1, 2, 6, 7 మరియు 8 set; s3 1 మరియు 8 set.
satisfies tari ఏమిటి?

Axioms: X forall tari X iff have odd rárá have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
What satisfies tari?

Axioms: X tari X have odd dawǫ́’ have even iff forall.
Candidates: s0 3 5 set; s1 1, 2, 5, 6 9 set; s2 1, 2, 6, 7 8 set; s3 1 8 set.
Satisfies tari what?

axioms: X forall tari X iff have odd ᐋᒃᑲ have even.
candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
satisfies tari what?

Axioms: X forall tari X iff have odd not have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
Satisfies tari what?

Axioms: X forall tari X iff have odd not have even.
Candidates: s0 set 3 5; s1 set 1, 2, 5, 6 9; s2 set 1, 2, 6, 7 8; s3 set 1 8.
Satisfies tari what?

Axioms: X tari X have odd have even not iff forall.
Candidates: s0 3 5 set; s1 1, 2, 5, 6 9 set; s2 1, 2, 6, 7 8 set; s3 1 8 set.
Satisfies tari вуч?

The axioms are: X forall nepa X if and only if min at most 5 and contains 6.
The candidates are: s0 set 2, 5 and 8; s1 set 1, 3, 5, 6 and 8; s2 set 7 and 9; s3 set 2, 4, 5 and 7.
What is the satisfies nepa?

Los axiomas son:
  - X para todo nepa: X si y sólo si mínimo en la mayoría: 5 y contiene: 6
Los candidatos son: s0 se fija en 2, 5 y 8; s1 se fija en 1, 3, 5, 6 y 8; s2 se fija en 7 y 9; s3 se fija en 2, 4, 5 y 7.
¿Qué satisfies: nepa?

公理如下：X对任意取值都满足nepa：X当且仅当最小值在大多数：5和包含：6。
候选项如下：s0的集合是2、5和8；s1的集合是1、3、5、6和8；s2的集合是7和9；s3的集合是2、4、5和7。
satisfies：nepa什么？

Belitler: X nepa: X min at çoğu: 5 ve contains: 6 iff forall.
Adaylar: s0 2, 5 ve 8 koymak; s1 1, 3, 5, 6 ve 8 koymak; s2 7 ve 9 koymak; s3 2, 4, 5 ve 7 koymak.
Satisfies: nepa ne?

Axioms: X forall nepa: X iff min katika wengi: 5 na contains: 6.
Wagombea ni: s0 seti 2, 5 na 8; s1 seti 1, 3, 5, 6 na 8; s2 seti 7 na 9; s3 seti 2, 4, 5 na 7.
Satisfies: nepa nini?

The axioms are: X forall nepa X if and only if min at most 5 and contains 6.
The candidates are: s0 set 2, 5 and 8; s1 set 1, 3, 5, 6 and 8; s2 set 7 and 9; s3 set 2, 4, 5 and 7.
What is the satisfies nepa?

{axioms: [(forall X (iff (nepa X) (and (min_at_most 5) (contains 6))))], candidates: [(set s0 [2 5 8]) (set s1 [1 3 5 6 8]) (set s2 [7 9]) (set s3 [2 4 5 7])], query: (which_satisfies nepa)}

Axiome: X forall nepa X gdw. min an die meisten 5 und contains 6.
Die Kandidaten sind: s0 set 2, 5 und 8; s1 set 1, 3, 5, 6 und 8; s2 set 7 und 9; s3 set 2, 4, 5 und 7.
Was satisfies nepa?

Аксѝо̄м: X forall nepa X iff min at većina 5 и contains 6.
Кандѝда̄т: s0 се̏т 2, 5 и 8; s1 се̏т 1, 3, 5, 6 и 8; s2 се̏т 7 и 9; s3 се̏т 2, 4, 5 и 7.
Satisfies nepa kakav?

Perusväitteet: X forall nepa X joss min luona useimmat 5 ja contains 6.
Ehdokkaat: s0 set 2, 5 ja 8; s1 set 1, 3, 5, 6 ja 8; s2 set 7 ja 9; s3 set 2, 4, 5 ja 7.
Mikä satisfies nepa?

公理如下：X对任意取值都满足nepa：X当且仅当最小值在大多数：5和包含：6。
候选项如下：s0的集合是2、5和8；s1的集合是1、3、5、6和8；s2的集合是7和9；s3的集合是2、4、5和7。
satisfies：nepa什么？

公理:Xnepa:Xmin...で大部分:5とcontains:6iffforall.
候補者:s02, 5と8置く; s11, 3, 5, 6と8置く; s27と9置く; s32, 4, 5と7置く.
satisfies:nepa何と?

Belitler: X nepa: X min at çoğu: 5 ve contains: 6 iff forall.
Adaylar: s0 2, 5 ve 8 koymak; s1 1, 3, 5, 6 ve 8 koymak; s2 7 ve 9 koymak; s3 2, 4, 5 ve 7 koymak.
Satisfies: nepa ne?

بَدِيهِيَّة: forall X iff nepa X min عِنْد أَكْثَر 5 وَـ contains 6.
مُرَشَّح: وَضَع s0 2، 5 وَـ 8؛ وَضَع s1 1، 3، 5، 6 وَـ 8؛ وَضَع s2 7 وَـ 9؛ وَضَع s3 2، 4، 5 وَـ 7.
satisfies nepa مَاذَا؟

Აქსიომები: X nepa X min at უმეტესობა 5 და contains 6 iff forall.
Კანდიდატები: s0 2, 5 და 8 set; s1 1, 3, 5, 6 და 8 set; s2 7 და 9 set; s3 2, 4, 5 და 7 set.
Satisfies nepa რა?

Axioms: forall X iff nepa X min i nuinga 5 me contains 6.
Kaiwhakauru: whakawhenua s0 2, 5 me 8; whakawhenua s1 1, 3, 5, 6 me 8; whakawhenua s2 7 me 9; whakawhenua s3 2, 4, 5 me 7.
Satisfies nepa unutai?

Chân lý: X forall nepa X iff min lúc hầu hết 5 và contains 6.
Candidates: s0 để 2, 5 và 8; s1 để 1, 3, 5, 6 và 8; s2 để 7 và 9; s3 để 2, 4, 5 và 7.
Satisfies nepa gì?

สัจพจน์:Xforallnepa:Xiffminที่ส่วนใหญ่:5และcontains:6.
ผู้สมัคร:s0set2, 5และ8; s1set1, 3, 5, 6และ8; s2set7และ9; s3set2, 4, 5และ7.
satisfies:nepaอะไร?

axioms: X nepa X min at most 5 மற்றும் contains 6 iff forall.
வேட்பாளர்: s0 2, 5 மற்றும் 8 set; s1 1, 3, 5, 6 மற்றும் 8 set; s2 7 மற்றும் 9 set; s3 2, 4, 5 மற்றும் 7 set.
satisfies nepa என்ன?

Axioms: X forall nepa: X iff min katika wengi: 5 na contains: 6.
Wagombea ni: s0 seti 2, 5 na 8; s1 seti 1, 3, 5, 6 na 8; s2 seti 7 na 9; s3 seti 2, 4, 5 na 7.
Satisfies: nepa nini?

Axioms: X nepa X min at most 5 dóó contains 6 iff forall.
Candidates: s0 2, 5 dóó 8 set; s1 1, 3, 5, 6 dóó 8 set; s2 7 dóó 9 set; s3 2, 4, 5 dóó 7 set.
Satisfies nepa haʼátʼíísh?

Axioms: X nepa X min at most 5 aamma contains 6 iff forall.
Candidates: s0 2, 5 aamma 8 set; s1 1, 3, 5, 6 aamma 8 set; s2 7 aamma 9 set; s3 2, 4, 5 aamma 7 set.
Satisfies nepa what?

Axioms: X forall nepa X iff min long most 5 na contains 6.
Candidates: s0 set 2, 5 na 8; s1 set 1, 3, 5, 6 na 8; s2 set 7 na 9; s3 set 2, 4, 5 na 7.
Satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
Satisfies nepa kwèch?

Axioms: X forall nepa X iff min at most 5 а contains 6.
Candidates: s0 set 2, 5 а 8; s1 set 1, 3, 5, 6 а 8; s2 set 7 а 9; s3 set 2, 4, 5 а 7.
Satisfies nepa фу?

공리: X nepa X min at 가장 5 contains 6 iff forall.
후보자: s0 2, 5 8 두다; s1 1, 3, 5, 6 8 두다; s2 7 9 두다; s3 2, 4, 5 7 두다.
satisfies nepa 무엇?

Axioms: X nepa X min at most 5 eta contains 6 iff forall.
Kandidatu: s0 2, 5 eta 8 multzo; s1 1, 3, 5, 6 eta 8 multzo; s2 7 eta 9 multzo; s3 2, 4, 5 eta 7 multzo.
Satisfies nepa zer?

Axioms: X forall nepa X iff min at ᎤᎪᏗᏗ 5 ᎠᎴ contains 6.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 2, 5 ᎠᎴ 8; s1 ᏭᏕᎵᎦ 1, 3, 5, 6 ᎠᎴ 8; s2 ᏭᏕᎵᎦ 7 ᎠᎴ 9; s3 ᏭᏕᎵᎦ 2, 4, 5 ᎠᎴ 7.
What satisfies nepa?

Axioms: X forall nepa X iff min at most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
Satisfies nepa what?

Axioms: X nepa X min at most 5 ыкӏи contains 6 iff forall.
Candidates: s0 2, 5 ыкӏи 8 set; s1 1, 3, 5, 6 ыкӏи 8 set; s2 7 ыкӏи 9 set; s3 2, 4, 5 ыкӏи 7 set.
Satisfies nepa сыд?

Axioms: X forall nepa X iff min at most 5 thiab contains 6.
Candidates: s0 set 2, 5 thiab 8; s1 set 1, 3, 5, 6 thiab 8; s2 set 7 thiab 9; s3 set 2, 4, 5 thiab 7.
Satisfies nepa what?

Axioms: X forall nepa X iff min jeyou most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
Satisfies nepa ining-jak?

Axioms: X forall nepa X iff min at most 5 micha' contains 6.
Candidates: s0 set 2, 5 micha' 8; s1 set 1, 3, 5, 6 micha' 8; s2 set 7 micha' 9; s3 set 2, 4, 5 micha' 7.
Satisfies nepa nanta?

Axioms: X nepa X min at most 5 カ contains 6 iff forall.
Candidates: s0 2, 5 カ 8 set; s1 1, 3, 5, 6 カ 8 set; s2 7 カ 9 set; s3 2, 4, 5 カ 7 set.
Satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 ынкъам contains 6.
Candidates: s0 set 2, 5 ынкъам 8; s1 set 1, 3, 5, 6 ынкъам 8; s2 set 7 ынкъам 9; s3 set 2, 4, 5 ынкъам 7.
Satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 yéetel contains 6.
Candidates: s0 set 2, 5 yéetel 8; s1 set 1, 3, 5, 6 yéetel 8; s2 set 7 yéetel 9; s3 set 2, 4, 5 yéetel 7.
Satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
Satisfies nepa híli?

Axioms: X nepa X min at most 5 na contains 6 iff forall.
Candidates: s0 2, 5 na 8 set; s1 1, 3, 5, 6 na 8 set; s2 7 na 9 set; s3 2, 4, 5 na 7 set.
Satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
Satisfies nepa what?

Axioms: X nepa X min at most 5 contains 6 iff forall.
Candidates: s0 2, 5 8 set; s1 1, 3, 5, 6 8 set; s2 7 9 set; s3 2, 4, 5 7 set.
Satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 ǂʻá contains 6.
Candidates: s0 set 2, 5 ǂʻá 8; s1 set 1, 3, 5, 6 ǂʻá 8; s2 set 7 ǂʻá 9; s3 set 2, 4, 5 ǂʻá 7.
Satisfies nepa what?

Axioms: X nepa X min at most 5 contains 6 iff forall.
Candidates: s0 2, 5 8 set; s1 1, 3, 5, 6 8 set; s2 7 9 set; s3 2, 4, 5 7 set.
Satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
Satisfies nepa what?

Axioms: X nepa X min at most 5 contains 6 iff forall.
Candidates: s0 2, 5 8 set; s1 1, 3, 5, 6 8 set; s2 7 9 set; s3 2, 4, 5 7 set.
Satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
Satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
Satisfies nepa tay?

Axiomes : X forall nepa X ssi min au plus 5 et contains 6.
Les candidats sont : s0 poser 2, 5 et 8 ; s1 poser 1, 3, 5, 6 et 8 ; s2 poser 7 et 9 ; s3 poser 2, 4, 5 et 7.
Quoi satisfies nepa ?

Aksiomo: X forall nepa X iff min ĉe plej 5 kaj contains 6.
Kandidato: s0 meti 2, 5 kaj 8; s1 meti 1, 3, 5, 6 kaj 8; s2 meti 7 kaj 9; s3 meti 2, 4, 5 kaj 7.
Satisfies nepa kio?

Axiómák: X forall nepa X acsa min at legtöbb 5 és contains 6.
Indulók: s0 set 2, 5 és 8; s1 set 1, 3, 5, 6 és 8; s2 set 7 és 9; s3 set 2, 4, 5 és 7.
Satisfies nepa melyik?

axioms:Xforallnepa:Xiffmin喺多數:5及contains:6.
候選人:s0set2, 5及8; s1set1, 3, 5, 6及8; s2set7及9; s3set2, 4, 5及7.
satisfies:nepa乜嘢?

Axioms: X forall nepa X iff min at most 5 とぅ contains 6.
Candidates: s0 set 2, 5 とぅ 8; s1 set 1, 3, 5, 6 とぅ 8; s2 set 7 とぅ 9; s3 set 2, 4, 5 とぅ 7.
Satisfies nepa what?

Аксиома: X forall nepa X iff min at ең 5 және contains 6.
Үміткер: s0 жиын 2, 5 және 8; s1 жиын 1, 3, 5, 6 және 8; s2 жиын 7 және 9; s3 жиын 2, 4, 5 және 7.
Satisfies nepa не?

אַקְסְיוֹמָה: X forall nepa X אםם min אֵצֶל רוב 5 וְ־ contains 6.
מועמדת: s0 הֵנִיח 2, 5 וְ־ 8; s1 הֵנִיח 1, 3, 5, 6 וְ־ 8; s2 הֵנִיח 7 וְ־ 9; s3 הֵנִיח 2, 4, 5 וְ־ 7.
איזה satisfies nepa?

Axioms: X forall nepa X iff min at most 5 დო contains 6.
Candidates: s0 set 2, 5 დო 8; s1 set 1, 3, 5, 6 დო 8; s2 set 7 დო 9; s3 set 2, 4, 5 დო 7.
Satisfies nepa what?

Aksioma-aksioma: X forall nepa X iff min at most 5 dan contains 6.
Kandidat: s0 memperkenalkan 2, 5 dan 8; s1 memperkenalkan 1, 3, 5, 6 dan 8; s2 memperkenalkan 7 dan 9; s3 memperkenalkan 2, 4, 5 dan 7.
Satisfies nepa apa?

ស្វ័យសត្យ:Xforallnepa:Xiffminatជាងគេ:5នឹងcontains:6.
បេក្ខជន:s0set2, 5នឹង8; s1set1, 3, 5, 6នឹង8; s2set7នឹង9; s3set2, 4, 5នឹង7.
satisfies:nepaអី?

ກົດຄວາມຈິງ:Xforallnepa:Xiffminທີ່...ທີ່ສຸດ:5ແລະcontains:6.
ຜູ້ສະໝັກ:s0set2, 5ແລະ8; s1set1, 3, 5, 6ແລະ8; s2set7ແລະ9; s3set2, 4, 5ແລະ7.
satisfies:nepaຫຍັງ?

axioms: X nepa X min వద్ద most 5 మరియు contains 6 iff forall.
candidates: s0 2, 5 మరియు 8 set; s1 1, 3, 5, 6 మరియు 8 set; s2 7 మరియు 9 set; s3 2, 4, 5 మరియు 7 set.
satisfies nepa ఏమిటి?

Axioms: X forall nepa X iff min at most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
What satisfies nepa?

Axioms: X nepa X min at most 5 contains 6 iff forall.
Candidates: s0 2, 5 8 set; s1 1, 3, 5, 6 8 set; s2 7 9 set; s3 2, 4, 5 7 set.
Satisfies nepa what?

axioms: X forall nepa X iff min at most 5 contains 6.
candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
Satisfies nepa what?

Axioms: X forall nepa X iff min at most 5 contains 6.
Candidates: s0 set 2, 5 8; s1 set 1, 3, 5, 6 8; s2 set 7 9; s3 set 2, 4, 5 7.
Satisfies nepa what?

Axioms: X nepa X min at most 5 contains 6 iff forall.
Candidates: s0 2, 5 8 set; s1 1, 3, 5, 6 8 set; s2 7 9 set; s3 2, 4, 5 7 set.
Satisfies nepa вуч?

The axioms are: X forall kipe X if and only if max at least 8 and sum even.
The candidates are: s0 set 1, 6, 7 and 9; s1 set 1, 3, 4, 6 and 8; s2 set 1, 2 and 7; s3 set 1, 3, 7 and 8.
What is the satisfies kipe?

Los axiomas son:
  - X para todo kipe: X si y sólo si máximo en least: 8 y la suma even
Los candidatos son: s0 se fija en 1, 6, 7 y 9; s1 se fija en 1, 3, 4, 6 y 8; s2 se fija en 1, 2 y 7; s3 se fija en 1, 3, 7 y 8.
¿Qué satisfies: kipe?

公理如下：X对任意取值都满足kipe：X当且仅当最大值在least：8和的总和是even。
候选项如下：s0的集合是1、6、7和9；s1的集合是1、3、4、6和8；s2的集合是1、2和7；s3的集合是1、3、7和8。
satisfies：kipe什么？

Belitler: X kipe: X max at least: 8 ve sum even iff forall.
Adaylar: s0 1, 6, 7 ve 9 koymak; s1 1, 3, 4, 6 ve 8 koymak; s2 1, 2 ve 7 koymak; s3 1, 3, 7 ve 8 koymak.
Satisfies: kipe ne?

Axioms: X forall kipe: X iff max katika least: 8 na sum even.
Wagombea ni: s0 seti 1, 6, 7 na 9; s1 seti 1, 3, 4, 6 na 8; s2 seti 1, 2 na 7; s3 seti 1, 3, 7 na 8.
Satisfies: kipe nini?

The axioms are: X forall kipe X if and only if max at least 8 and sum even.
The candidates are: s0 set 1, 6, 7 and 9; s1 set 1, 3, 4, 6 and 8; s2 set 1, 2 and 7; s3 set 1, 3, 7 and 8.
What is the satisfies kipe?

{axioms: [(forall X (iff (kipe X) (and (max_at_least 8) (sum_even))))], candidates: [(set s0 [1 6 7 9]) (set s1 [1 3 4 6 8]) (set s2 [1 2 7]) (set s3 [1 3 7 8])], query: (which_satisfies kipe)}

Axiome: X forall kipe X gdw. max an geringst 8 und Summe eben.
Die Kandidaten sind: s0 set 1, 6, 7 und 9; s1 set 1, 3, 4, 6 und 8; s2 set 1, 2 und 7; s3 set 1, 3, 7 und 8.
Was satisfies kipe?

Аксѝо̄м: X forall kipe X iff max at minimalan 8 и zbroj раван.
Кандѝда̄т: s0 се̏т 1, 6, 7 и 9; s1 се̏т 1, 3, 4, 6 и 8; s2 се̏т 1, 2 и 7; s3 се̏т 1, 3, 7 и 8.
Satisfies kipe kakav?

Perusväitteet: X forall kipe X joss max luona vähin 8 ja summa tasainen.
Ehdokkaat: s0 set 1, 6, 7 ja 9; s1 set 1, 3, 4, 6 ja 8; s2 set 1, 2 ja 7; s3 set 1, 3, 7 ja 8.
Mikä satisfies kipe?

公理如下：X对任意取值都满足kipe：X当且仅当最大值在least：8和的总和是even。
候选项如下：s0的集合是1、6、7和9；s1的集合是1、3、4、6和8；s2的集合是1、2和7；s3的集合是1、3、7和8。
satisfies：kipe什么？

公理:Xkipe:Xmax...で最小の:8と総額平iffforall.
候補者:s01, 6, 7と9置く; s11, 3, 4, 6と8置く; s21, 2と7置く; s31, 3, 7と8置く.
satisfies:kipe何と?

Belitler: X kipe: X max at least: 8 ve sum even iff forall.
Adaylar: s0 1, 6, 7 ve 9 koymak; s1 1, 3, 4, 6 ve 8 koymak; s2 1, 2 ve 7 koymak; s3 1, 3, 7 ve 8 koymak.
Satisfies: kipe ne?

بَدِيهِيَّة: forall X iff kipe X max عِنْد أَقَلَّ 8 وَـ مَجْمُوع مُسَطَّح.
مُرَشَّح: وَضَع s0 1، 6، 7 وَـ 9؛ وَضَع s1 1، 3، 4، 6 وَـ 8؛ وَضَع s2 1، 2 وَـ 7؛ وَضَع s3 1، 3، 7 وَـ 8.
satisfies kipe مَاذَا؟

Აქსიომები: X kipe X max at least 8 და ჯამი კი iff forall.
Კანდიდატები: s0 1, 6, 7 და 9 set; s1 1, 3, 4, 6 და 8 set; s2 1, 2 და 7 set; s3 1, 3, 7 და 8 set.
Satisfies kipe რა?

Axioms: forall X iff kipe X max i least 8 me tapeke papatairite.
Kaiwhakauru: whakawhenua s0 1, 6, 7 me 9; whakawhenua s1 1, 3, 4, 6 me 8; whakawhenua s2 1, 2 me 7; whakawhenua s3 1, 3, 7 me 8.
Satisfies kipe unutai?

Chân lý: X forall kipe X iff max lúc least 8 và tổng số bằng phẳng.
Candidates: s0 để 1, 6, 7 và 9; s1 để 1, 3, 4, 6 và 8; s2 để 1, 2 và 7; s3 để 1, 3, 7 và 8.
Satisfies kipe gì?

สัจพจน์:Xforallkipe:Xiffmaxที่least:8และsumแม้.
ผู้สมัคร:s0set1, 6, 7และ9; s1set1, 3, 4, 6และ8; s2set1, 2และ7; s3set1, 3, 7และ8.
satisfies:kipeอะไร?

axioms: X kipe X max at least 8 மற்றும் sum இரட்டைப்படை iff forall.
வேட்பாளர்: s0 1, 6, 7 மற்றும் 9 set; s1 1, 3, 4, 6 மற்றும் 8 set; s2 1, 2 மற்றும் 7 set; s3 1, 3, 7 மற்றும் 8 set.
satisfies kipe என்ன?

Axioms: X forall kipe: X iff max katika least: 8 na sum even.
Wagombea ni: s0 seti 1, 6, 7 na 9; s1 seti 1, 3, 4, 6 na 8; s2 seti 1, 2 na 7; s3 seti 1, 3, 7 na 8.
Satisfies: kipe nini?

Axioms: X kipe X max at least 8 dóó sum ndi iff forall.
Candidates: s0 1, 6, 7 dóó 9 set; s1 1, 3, 4, 6 dóó 8 set; s2 1, 2 dóó 7 set; s3 1, 3, 7 dóó 8 set.
Satisfies kipe haʼátʼíísh?

Axioms: X kipe X max at least 8 aamma sum even iff forall.
Candidates: s0 1, 6, 7 aamma 9 set; s1 1, 3, 4, 6 aamma 8 set; s2 1, 2 aamma 7 set; s3 1, 3, 7 aamma 8 set.
Satisfies kipe what?

Axioms: X forall kipe X iff max long least 8 na sum even.
Candidates: s0 set 1, 6, 7 na 9; s1 set 1, 3, 4, 6 na 8; s2 set 1, 2 na 7; s3 set 1, 3, 7 na 8.
Satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 sum even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
Satisfies kipe kwèch?

Axioms: X forall kipe X iff max at least 8 а sum even.
Candidates: s0 set 1, 6, 7 а 9; s1 set 1, 3, 4, 6 а 8; s2 set 1, 2 а 7; s3 set 1, 3, 7 а 8.
Satisfies kipe фу?

공리: X kipe X max at 가장 적게 8 합계 고르다 iff forall.
후보자: s0 1, 6, 7 9 두다; s1 1, 3, 4, 6 8 두다; s2 1, 2 7 두다; s3 1, 3, 7 8 두다.
satisfies kipe 무엇?

Axioms: X kipe X max at least 8 eta sum even iff forall.
Kandidatu: s0 1, 6, 7 eta 9 multzo; s1 1, 3, 4, 6 eta 8 multzo; s2 1, 2 eta 7 multzo; s3 1, 3, 7 eta 8 multzo.
Satisfies kipe zer?

Axioms: X forall kipe X iff max at least 8 ᎠᎴ sum even.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 1, 6, 7 ᎠᎴ 9; s1 ᏭᏕᎵᎦ 1, 3, 4, 6 ᎠᎴ 8; s2 ᏭᏕᎵᎦ 1, 2 ᎠᎴ 7; s3 ᏭᏕᎵᎦ 1, 3, 7 ᎠᎴ 8.
What satisfies kipe?

Axioms: X forall kipe X iff max at least 8 qullu even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
Satisfies kipe what?

Axioms: X kipe X max at least 8 ыкӏи sum even iff forall.
Candidates: s0 1, 6, 7 ыкӏи 9 set; s1 1, 3, 4, 6 ыкӏи 8 set; s2 1, 2 ыкӏи 7 set; s3 1, 3, 7 ыкӏи 8 set.
Satisfies kipe сыд?

Axioms: X forall kipe X iff max at least 8 thiab sum even.
Candidates: s0 set 1, 6, 7 thiab 9; s1 set 1, 3, 4, 6 thiab 8; s2 set 1, 2 thiab 7; s3 set 1, 3, 7 thiab 8.
Satisfies kipe what?

Axioms: X forall kipe X iff max jeyou wy krook 8 sum even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
Satisfies kipe ining-jak?

Axioms: X forall kipe X iff max at least 8 micha' sum even.
Candidates: s0 set 1, 6, 7 micha' 9; s1 set 1, 3, 4, 6 micha' 8; s2 set 1, 2 micha' 7; s3 set 1, 3, 7 micha' 8.
Satisfies kipe nanta?

Axioms: X kipe X max at least 8 カ sum even iff forall.
Candidates: s0 1, 6, 7 カ 9 set; s1 1, 3, 4, 6 カ 8 set; s2 1, 2 カ 7 set; s3 1, 3, 7 カ 8 set.
Satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 ынкъам sum even.
Candidates: s0 set 1, 6, 7 ынкъам 9; s1 set 1, 3, 4, 6 ынкъам 8; s2 set 1, 2 ынкъам 7; s3 set 1, 3, 7 ынкъам 8.
Satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 yéetel sum even.
Candidates: s0 set 1, 6, 7 yéetel 9; s1 set 1, 3, 4, 6 yéetel 8; s2 set 1, 2 yéetel 7; s3 set 1, 3, 7 yéetel 8.
Satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 sum even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
Satisfies kipe híli?

Axioms: X kipe X max at least 8 na sum even iff forall.
Candidates: s0 1, 6, 7 na 9 set; s1 1, 3, 4, 6 na 8 set; s2 1, 2 na 7 set; s3 1, 3, 7 na 8 set.
Satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 sum even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
Satisfies kipe what?

Axioms: X kipe X max at least 8 sum even iff forall.
Candidates: s0 1, 6, 7 9 set; s1 1, 3, 4, 6 8 set; s2 1, 2 7 set; s3 1, 3, 7 8 set.
Satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 ǂʻá sum even.
Candidates: s0 set 1, 6, 7 ǂʻá 9; s1 set 1, 3, 4, 6 ǂʻá 8; s2 set 1, 2 ǂʻá 7; s3 set 1, 3, 7 ǂʻá 8.
Satisfies kipe what?

Axioms: X kipe X max at least 8 sum even iff forall.
Candidates: s0 1, 6, 7 9 set; s1 1, 3, 4, 6 8 set; s2 1, 2 7 set; s3 1, 3, 7 8 set.
Satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 sum even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
Satisfies kipe what?

Axioms: X kipe X max at least 8 sum even iff forall.
Candidates: s0 1, 6, 7 9 set; s1 1, 3, 4, 6 8 set; s2 1, 2 7 set; s3 1, 3, 7 8 set.
Satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 sum even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
Satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 sum even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
Satisfies kipe tay?

Axiomes : X forall kipe X ssi max au moindre 8 et somme plat.
Les candidats sont : s0 poser 1, 6, 7 et 9 ; s1 poser 1, 3, 4, 6 et 8 ; s2 poser 1, 2 et 7 ; s3 poser 1, 3, 7 et 8.
Quoi satisfies kipe ?

Aksiomo: X forall kipe X iff max ĉe plej malmulta 8 kaj sum ebena.
Kandidato: s0 meti 1, 6, 7 kaj 9; s1 meti 1, 3, 4, 6 kaj 8; s2 meti 1, 2 kaj 7; s3 meti 1, 3, 7 kaj 8.
Satisfies kipe kio?

Axiómák: X forall kipe X acsa max at legkisebb 8 és összeg egyenletes.
Indulók: s0 set 1, 6, 7 és 9; s1 set 1, 3, 4, 6 és 8; s2 set 1, 2 és 7; s3 set 1, 3, 7 és 8.
Satisfies kipe melyik?

axioms:Xforallkipe:Xiffmax喺least:8及sum更加.
候選人:s0set1, 6, 7及9; s1set1, 3, 4, 6及8; s2set1, 2及7; s3set1, 3, 7及8.
satisfies:kipe乜嘢?

Axioms: X forall kipe X iff max at least 8 とぅ sum even.
Candidates: s0 set 1, 6, 7 とぅ 9; s1 set 1, 3, 4, 6 とぅ 8; s2 set 1, 2 とぅ 7; s3 set 1, 3, 7 とぅ 8.
Satisfies kipe what?

Аксиома: X forall kipe X iff max at least 8 және сом да.
Үміткер: s0 жиын 1, 6, 7 және 9; s1 жиын 1, 3, 4, 6 және 8; s2 жиын 1, 2 және 7; s3 жиын 1, 3, 7 және 8.
Satisfies kipe не?

אַקְסְיוֹמָה: X forall kipe X אםם max אֵצֶל least 8 וְ־ סְכוּם ערב.
מועמדת: s0 הֵנִיח 1, 6, 7 וְ־ 9; s1 הֵנִיח 1, 3, 4, 6 וְ־ 8; s2 הֵנִיח 1, 2 וְ־ 7; s3 הֵנִיח 1, 3, 7 וְ־ 8.
איזה satisfies kipe?

Axioms: X forall kipe X iff max at least 8 დო sum even.
Candidates: s0 set 1, 6, 7 დო 9; s1 set 1, 3, 4, 6 დო 8; s2 set 1, 2 დო 7; s3 set 1, 3, 7 დო 8.
Satisfies kipe what?

Aksioma-aksioma: X forall kipe X iff max at least 8 dan sum rata.
Kandidat: s0 memperkenalkan 1, 6, 7 dan 9; s1 memperkenalkan 1, 3, 4, 6 dan 8; s2 memperkenalkan 1, 2 dan 7; s3 memperkenalkan 1, 3, 7 dan 8.
Satisfies kipe apa?

ស្វ័យសត្យ:Xforallkipe:Xiffmax at least:8នឹងផលបូកសូម្បី.
បេក្ខជន:s0set1, 6, 7នឹង9; s1set1, 3, 4, 6នឹង8; s2set1, 2នឹង7; s3set1, 3, 7នឹង8.
satisfies:kipeអី?

ກົດຄວາມຈິງ:Xforallkipe:Xiffmaxທີ່least:8ແລະsum even.
ຜູ້ສະໝັກ:s0set1, 6, 7ແລະ9; s1set1, 3, 4, 6ແລະ8; s2set1, 2ແລະ7; s3set1, 3, 7ແລະ8.
satisfies:kipeຫຍັງ?

axioms: X kipe X max వద్ద least 8 మరియు sum చదునైన iff forall.
candidates: s0 1, 6, 7 మరియు 9 set; s1 1, 3, 4, 6 మరియు 8 set; s2 1, 2 మరియు 7 set; s3 1, 3, 7 మరియు 8 set.
satisfies kipe ఏమిటి?

Axioms: X forall kipe X iff max at least 8 sum even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
What satisfies kipe?

Axioms: X kipe X max at least 8 sum even iff forall.
Candidates: s0 1, 6, 7 9 set; s1 1, 3, 4, 6 8 set; s2 1, 2 7 set; s3 1, 3, 7 8 set.
Satisfies kipe what?

axioms: X forall kipe X iff max at least 8 sum even.
candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 sum even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
Satisfies kipe what?

Axioms: X forall kipe X iff max at least 8 sum even.
Candidates: s0 set 1, 6, 7 9; s1 set 1, 3, 4, 6 8; s2 set 1, 2 7; s3 set 1, 3, 7 8.
Satisfies kipe what?

Axioms: X kipe X max at least 8 sum even iff forall.
Candidates: s0 1, 6, 7 9 set; s1 1, 3, 4, 6 8 set; s2 1, 2 7 set; s3 1, 3, 7 8 set.
Satisfies kipe вуч?

The axioms are:
  - X forall runi X if and only if does not has odd and max at least 4
The candidates are: s0 set 1, 3, 4, 5 and 7; s1 set 6 and 8; s2 set 2, 3, 7 and 9; s3 set 1, 5 and 8.
What is the satisfies runi?

Los axiomas son:
  - X para todo runi: X si y sólo si no tiene odd y máximo en least: 4
Los candidatos son: s0 se fija en 1, 3, 4, 5 y 7; s1 se fija en 6 y 8; s2 se fija en 2, 3, 7 y 9; s3 se fija en 1, 5 y 8.
¿Qué satisfies: runi?

公理如下：X对任意取值都满足runi：X当且仅当不有odd和最大值在least：4。
候选项如下：s0的集合是1、3、4、5和7；s1的集合是6和8；s2的集合是2、3、7和9；s3的集合是1、5和8。
satisfies：runi什么？

Belitler: X runi: X sahiptir odd değil ve max at least: 4 iff forall.
Adaylar: s0 1, 3, 4, 5 ve 7 koymak; s1 6 ve 8 koymak; s2 2, 3, 7 ve 9 koymak; s3 1, 5 ve 8 koymak.
Satisfies: runi ne?

Axioms: X forall runi: X iff si ina odd na max katika least: 4.
Wagombea ni: s0 seti 1, 3, 4, 5 na 7; s1 seti 6 na 8; s2 seti 2, 3, 7 na 9; s3 seti 1, 5 na 8.
Satisfies: runi nini?

The axioms are:
  - X forall runi X if and only if does not has odd and max at least 4
The candidates are: s0 set 1, 3, 4, 5 and 7; s1 set 6 and 8; s2 set 2, 3, 7 and 9; s3 set 1, 5 and 8.
What is the satisfies runi?

{axioms: [(forall X (iff (runi X) (and (not (has_odd)) (max_at_least 4))))], candidates: [(set s0 [1 3 4 5 7]) (set s1 [6 8]) (set s2 [2 3 7 9]) (set s3 [1 5 8])], query: (which_satisfies runi)}

Axiome: X forall runi X gdw. nicht haben seltsam und max an geringst 4.
Die Kandidaten sind: s0 set 1, 3, 4, 5 und 7; s1 set 6 und 8; s2 set 2, 3, 7 und 9; s3 set 1, 5 und 8.
Was satisfies runi?

Аксѝо̄м: X forall runi X iff не имати непаран и max at minimalan 4.
Кандѝда̄т: s0 се̏т 1, 3, 4, 5 и 7; s1 се̏т 6 и 8; s2 се̏т 2, 3, 7 и 9; s3 се̏т 1, 5 и 8.
Satisfies runi kakav?

Perusväitteet: X forall runi X joss ei omistaa outo ja max luona vähin 4.
Ehdokkaat: s0 set 1, 3, 4, 5 ja 7; s1 set 6 ja 8; s2 set 2, 3, 7 ja 9; s3 set 1, 5 ja 8.
Mikä satisfies runi?

公理如下：X对任意取值都满足runi：X当且仅当不有odd和最大值在least：4。
候选项如下：s0的集合是1、3、4、5和7；s1的集合是6和8；s2的集合是2、3、7和9；s3的集合是1、5和8。
satisfies：runi什么？

公理:Xruni:Xhave変な...ではないとmax...で最小の:4iffforall.
候補者:s01, 3, 4, 5と7置く; s16と8置く; s22, 3, 7と9置く; s31, 5と8置く.
satisfies:runi何と?

Belitler: X runi: X sahiptir odd değil ve max at least: 4 iff forall.
Adaylar: s0 1, 3, 4, 5 ve 7 koymak; s1 6 ve 8 koymak; s2 2, 3, 7 ve 9 koymak; s3 1, 5 ve 8 koymak.
Satisfies: runi ne?

بَدِيهِيَّة: forall X iff runi X لَا مَلَكَ فَرْدِيّ وَـ max عِنْد أَقَلَّ 4.
مُرَشَّح: وَضَع s0 1، 3، 4، 5 وَـ 7؛ وَضَع s1 6 وَـ 8؛ وَضَع s2 2، 3، 7 وَـ 9؛ وَضَع s3 1، 5 وَـ 8.
satisfies runi مَاذَا؟

Აქსიომები: X runi X არ ფლობს უცნაური და max at least 4 iff forall.
Კანდიდატები: s0 1, 3, 4, 5 და 7 set; s1 6 და 8 set; s2 2, 3, 7 და 9 set; s3 1, 5 და 8 set.
Satisfies runi რა?

Axioms: forall X iff runi X kāore whai makere me max i least 4.
Kaiwhakauru: whakawhenua s0 1, 3, 4, 5 me 7; whakawhenua s1 6 me 8; whakawhenua s2 2, 3, 7 me 9; whakawhenua s3 1, 5 me 8.
Satisfies runi unutai?

Chân lý: X forall runi X iff không có kỳ cục và max lúc least 4.
Candidates: s0 để 1, 3, 4, 5 và 7; s1 để 6 và 8; s2 để 2, 3, 7 và 9; s3 để 1, 5 và 8.
Satisfies runi gì?

สัจพจน์:Xforallruni:Xiffไม่มีคี่และmaxที่least:4.
ผู้สมัคร:s0set1, 3, 4, 5และ7; s1set6และ8; s2set2, 3, 7และ9; s3set1, 5และ8.
satisfies:runiอะไร?

axioms: X runi X have ஒற்றைப்படை இல்லை மற்றும் max at least 4 iff forall.
வேட்பாளர்: s0 1, 3, 4, 5 மற்றும் 7 set; s1 6 மற்றும் 8 set; s2 2, 3, 7 மற்றும் 9 set; s3 1, 5 மற்றும் 8 set.
satisfies runi என்ன?

Axioms: X forall runi: X iff si ina odd na max katika least: 4.
Wagombea ni: s0 seti 1, 3, 4, 5 na 7; s1 seti 6 na 8; s2 seti 2, 3, 7 na 9; s3 seti 1, 5 na 8.
Satisfies: runi nini?

Axioms: X runi X dooda bee hólǫ́ odd dóó max at least 4 iff forall.
Candidates: s0 1, 3, 4, 5 dóó 7 set; s1 6 dóó 8 set; s2 2, 3, 7 dóó 9 set; s3 1, 5 dóó 8 set.
Satisfies runi haʼátʼíísh?

Axioms: X runi X qar odd not aamma max at least 4 iff forall.
Candidates: s0 1, 3, 4, 5 aamma 7 set; s1 6 aamma 8 set; s2 2, 3, 7 aamma 9 set; s3 1, 5 aamma 8 set.
Satisfies runi what?

Axioms: X forall runi X iff not have odd na max long least 4.
Candidates: s0 set 1, 3, 4, 5 na 7; s1 set 6 na 8; s2 set 2, 3, 7 na 9; s3 set 1, 5 na 8.
Satisfies runi what?

Axioms: X forall runi X iff not have odd max at least 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
Satisfies runi kwèch?

Axioms: X forall runi X iff have odd ца а max at least 4.
Candidates: s0 set 1, 3, 4, 5 а 7; s1 set 6 а 8; s2 set 2, 3, 7 а 9; s3 set 1, 5 а 8.
Satisfies runi фу?

공리: X runi X 안 있다 기수의 max at 가장 적게 4 iff forall.
후보자: s0 1, 3, 4, 5 7 두다; s1 6 8 두다; s2 2, 3, 7 9 두다; s3 1, 5 8 두다.
satisfies runi 무엇?

Axioms: X runi X ez eduki odd eta max at least 4 iff forall.
Kandidatu: s0 1, 3, 4, 5 eta 7 multzo; s1 6 eta 8 multzo; s2 2, 3, 7 eta 9 multzo; s3 1, 5 eta 8 multzo.
Satisfies runi zer?

Axioms: X forall runi X iff ᏝᏃ ᎤᎭ odd ᎠᎴ max at least 4.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 1, 3, 4, 5 ᎠᎴ 7; s1 ᏭᏕᎵᎦ 6 ᎠᎴ 8; s2 ᏭᏕᎵᎦ 2, 3, 7 ᎠᎴ 9; s3 ᏭᏕᎵᎦ 1, 5 ᎠᎴ 8.
What satisfies runi?

Axioms: X forall runi X iff ama have odd max at least 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
Satisfies runi what?

Axioms: X runi X not have odd ыкӏи max at least 4 iff forall.
Candidates: s0 1, 3, 4, 5 ыкӏи 7 set; s1 6 ыкӏи 8 set; s2 2, 3, 7 ыкӏи 9 set; s3 1, 5 ыкӏи 8 set.
Satisfies runi сыд?

Axioms: X forall runi X iff tsis have odd thiab max at least 4.
Candidates: s0 set 1, 3, 4, 5 thiab 7; s1 set 6 thiab 8; s2 set 2, 3, 7 thiab 9; s3 set 1, 5 thiab 8.
Satisfies runi what?

Axioms: X forall runi X iff woi have odd max jeyou wy krook 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
Satisfies runi ining-jak?

Axioms: X forall runi X iff ki'yo have odd micha' max at least 4.
Candidates: s0 set 1, 3, 4, 5 micha' 7; s1 set 6 micha' 8; s2 set 2, 3, 7 micha' 9; s3 set 1, 5 micha' 8.
Satisfies runi nanta?

Axioms: X runi X ソモ have odd カ max at least 4 iff forall.
Candidates: s0 1, 3, 4, 5 カ 7 set; s1 6 カ 8 set; s2 2, 3, 7 カ 9 set; s3 1, 5 カ 8 set.
Satisfies runi what?

Axioms: X forall runi X iff not рытык odd ынкъам max at least 4.
Candidates: s0 set 1, 3, 4, 5 ынкъам 7; s1 set 6 ынкъам 8; s2 set 2, 3, 7 ынкъам 9; s3 set 1, 5 ынкъам 8.
Satisfies runi what?

Axioms: X forall runi X iff ma' have odd yéetel max at least 4.
Candidates: s0 set 1, 3, 4, 5 yéetel 7; s1 set 6 yéetel 8; s2 set 2, 3, 7 yéetel 9; s3 set 1, 5 yéetel 8.
Satisfies runi what?

Axioms: X forall runi X iff not have odd max at least 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
Satisfies runi híli?

Axioms: X runi X have odd not na max at least 4 iff forall.
Candidates: s0 1, 3, 4, 5 na 7 set; s1 6 na 8 set; s2 2, 3, 7 na 9 set; s3 1, 5 na 8 set.
Satisfies runi what?

Axioms: X forall runi X iff nahániri have odd max at least 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
Satisfies runi what?

Axioms: X runi X not have odd max at least 4 iff forall.
Candidates: s0 1, 3, 4, 5 7 set; s1 6 8 set; s2 2, 3, 7 9 set; s3 1, 5 8 set.
Satisfies runi what?

Axioms: X forall runi X iff ǁʻàa have odd ǂʻá max at least 4.
Candidates: s0 set 1, 3, 4, 5 ǂʻá 7; s1 set 6 ǂʻá 8; s2 set 2, 3, 7 ǂʻá 9; s3 set 1, 5 ǂʻá 8.
Satisfies runi what?

Axioms: X runi X not have odd max at least 4 iff forall.
Candidates: s0 1, 3, 4, 5 7 set; s1 6 8 set; s2 2, 3, 7 9 set; s3 1, 5 8 set.
Satisfies runi what?

Axioms: X forall runi X iff not have odd max at least 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
Satisfies runi what?

Axioms: X runi X not have odd max at least 4 iff forall.
Candidates: s0 1, 3, 4, 5 7 set; s1 6 8 set; s2 2, 3, 7 9 set; s3 1, 5 8 set.
Satisfies runi what?

Axioms: X forall runi X iff not have odd max at least 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
Satisfies runi what?

Axioms: X forall runi X iff inte have odd max at least 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
Satisfies runi tay?

Axiomes : X forall runi X ssi pas avoir bizarre et max au moindre 4.
Les candidats sont : s0 poser 1, 3, 4, 5 et 7 ; s1 poser 6 et 8 ; s2 poser 2, 3, 7 et 9 ; s3 poser 1, 5 et 8.
Quoi satisfies runi ?

Aksiomo: X forall runi X iff ne havi stranga kaj max ĉe plej malmulta 4.
Kandidato: s0 meti 1, 3, 4, 5 kaj 7; s1 meti 6 kaj 8; s2 meti 2, 3, 7 kaj 9; s3 meti 1, 5 kaj 8.
Satisfies runi kio?

Axiómák: X forall runi X acsa nem bír furcsa és max at legkisebb 4.
Indulók: s0 set 1, 3, 4, 5 és 7; s1 set 6 és 8; s2 set 2, 3, 7 és 9; s3 set 1, 5 és 8.
Satisfies runi melyik?

axioms:Xforallruni:Xiff不有odd及max喺least:4.
候選人:s0set1, 3, 4, 5及7; s1set6及8; s2set2, 3, 7及9; s3set1, 5及8.
satisfies:runi乜嘢?

Axioms: X forall runi X iff not have odd とぅ max at least 4.
Candidates: s0 set 1, 3, 4, 5 とぅ 7; s1 set 6 とぅ 8; s2 set 2, 3, 7 とぅ 9; s3 set 1, 5 とぅ 8.
Satisfies runi what?

Аксиома: X forall runi X iff емес have odd және max at least 4.
Үміткер: s0 жиын 1, 3, 4, 5 және 7; s1 жиын 6 және 8; s2 жиын 2, 3, 7 және 9; s3 жиын 1, 5 және 8.
Satisfies runi не?

אַקְסְיוֹמָה: X forall runi X אםם לא have משונה וְ־ max אֵצֶל least 4.
מועמדת: s0 הֵנִיח 1, 3, 4, 5 וְ־ 7; s1 הֵנִיח 6 וְ־ 8; s2 הֵנִיח 2, 3, 7 וְ־ 9; s3 הֵנִיח 1, 5 וְ־ 8.
איזה satisfies runi?

Axioms: X forall runi X iff not have odd დო max at least 4.
Candidates: s0 set 1, 3, 4, 5 დო 7; s1 set 6 დო 8; s2 set 2, 3, 7 დო 9; s3 set 1, 5 დო 8.
Satisfies runi what?

Aksioma-aksioma: X forall runi X iff tidak punya ganjil dan max at least 4.
Kandidat: s0 memperkenalkan 1, 3, 4, 5 dan 7; s1 memperkenalkan 6 dan 8; s2 memperkenalkan 2, 3, 7 dan 9; s3 memperkenalkan 1, 5 dan 8.
Satisfies runi apa?

ស្វ័យសត្យ:Xforallruni:Xiffមិន...ទេមានសេសនឹងmax at least:4.
បេក្ខជន:s0set1, 3, 4, 5នឹង7; s1set6នឹង8; s2set2, 3, 7នឹង9; s3set1, 5នឹង8.
satisfies:runiអី?

ກົດຄວາມຈິງ:Xforallruni:Xiffບໍ່ມີoddແລະmaxທີ່least:4.
ຜູ້ສະໝັກ:s0set1, 3, 4, 5ແລະ7; s1set6ແລະ8; s2set2, 3, 7ແລະ9; s3set1, 5ແລະ8.
satisfies:runiຫຍັງ?

axioms: X runi X have విలక్షణమైన కాదు మరియు max వద్ద least 4 iff forall.
candidates: s0 1, 3, 4, 5 మరియు 7 set; s1 6 మరియు 8 set; s2 2, 3, 7 మరియు 9 set; s3 1, 5 మరియు 8 set.
satisfies runi ఏమిటి?

Axioms: X forall runi X iff rárá have odd max at least 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
What satisfies runi?

Axioms: X runi X dawǫ́’ have odd max at least 4 iff forall.
Candidates: s0 1, 3, 4, 5 7 set; s1 6 8 set; s2 2, 3, 7 9 set; s3 1, 5 8 set.
Satisfies runi what?

axioms: X forall runi X iff ᐋᒃᑲ have odd max at least 4.
candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
satisfies runi what?

Axioms: X forall runi X iff not have odd max at least 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
Satisfies runi what?

Axioms: X forall runi X iff not have odd max at least 4.
Candidates: s0 set 1, 3, 4, 5 7; s1 set 6 8; s2 set 2, 3, 7 9; s3 set 1, 5 8.
Satisfies runi what?

Axioms: X runi X have odd not max at least 4 iff forall.
Candidates: s0 1, 3, 4, 5 7 set; s1 6 8 set; s2 2, 3, 7 9 set; s3 1, 5 8 set.
Satisfies runi вуч?

The axioms are:
  - X forall tapo X if and only if size at least 3 and does not sum even
The candidates are: s0 set 2, 3, 4, 7 and 8; s1 set 6 and 9; s2 set 4, 5, 8 and 9; s3 set 2, 4 and 5.
What is the satisfies tapo?

Los axiomas son:
  - X para todo tapo: X si y sólo si tamaño en least: 3 y no la suma even
Los candidatos son: s0 se fija en 2, 3, 4, 7 y 8; s1 se fija en 6 y 9; s2 se fija en 4, 5, 8 y 9; s3 se fija en 2, 4 y 5.
¿Qué satisfies: tapo?

公理如下：X对任意取值都满足tapo：X当且仅当大小在least：3和不的总和是even。
候选项如下：s0的集合是2、3、4、7和8；s1的集合是6和9；s2的集合是4、5、8和9；s3的集合是2、4和5。
satisfies：tapo什么？

Belitler: X tapo: X boyut at least: 3 ve sum even değil iff forall.
Adaylar: s0 2, 3, 4, 7 ve 8 koymak; s1 6 ve 9 koymak; s2 4, 5, 8 ve 9 koymak; s3 2, 4 ve 5 koymak.
Satisfies: tapo ne?

Axioms: X forall tapo: X iff size katika least: 3 na si sum even.
Wagombea ni: s0 seti 2, 3, 4, 7 na 8; s1 seti 6 na 9; s2 seti 4, 5, 8 na 9; s3 seti 2, 4 na 5.
Satisfies: tapo nini?

The axioms are:
  - X forall tapo X if and only if size at least 3 and does not sum even
The candidates are: s0 set 2, 3, 4, 7 and 8; s1 set 6 and 9; s2 set 4, 5, 8 and 9; s3 set 2, 4 and 5.
What is the satisfies tapo?

{axioms: [(forall X (iff (tapo X) (and (size_at_least 3) (not (sum_even)))))], candidates: [(set s0 [2 3 4 7 8]) (set s1 [6 9]) (set s2 [4 5 8 9]) (set s3 [2 4 5])], query: (which_satisfies tapo)}

Axiome: X forall tapo X gdw. Größe an geringst 3 und nicht Summe eben.
Die Kandidaten sind: s0 set 2, 3, 4, 7 und 8; s1 set 6 und 9; s2 set 4, 5, 8 und 9; s3 set 2, 4 und 5.
Was satisfies tapo?

Аксѝо̄м: X forall tapo X iff величѝна at minimalan 3 и не zbroj раван.
Кандѝда̄т: s0 се̏т 2, 3, 4, 7 и 8; s1 се̏т 6 и 9; s2 се̏т 4, 5, 8 и 9; s3 се̏т 2, 4 и 5.
Satisfies tapo kakav?

Perusväitteet: X forall tapo X joss koko luona vähin 3 ja ei summa tasainen.
Ehdokkaat: s0 set 2, 3, 4, 7 ja 8; s1 set 6 ja 9; s2 set 4, 5, 8 ja 9; s3 set 2, 4 ja 5.
Mikä satisfies tapo?

公理如下：X对任意取值都满足tapo：X当且仅当大小在least：3和不的总和是even。
候选项如下：s0的集合是2、3、4、7和8；s1的集合是6和9；s2的集合是4、5、8和9；s3的集合是2、4和5。
satisfies：tapo什么？

公理:Xtapo:X大きさ...で最小の:3と総額平...ではないiffforall.
候補者:s02, 3, 4, 7と8置く; s16と9置く; s24, 5, 8と9置く; s32, 4と5置く.
satisfies:tapo何と?

Belitler: X tapo: X boyut at least: 3 ve sum even değil iff forall.
Adaylar: s0 2, 3, 4, 7 ve 8 koymak; s1 6 ve 9 koymak; s2 4, 5, 8 ve 9 koymak; s3 2, 4 ve 5 koymak.
Satisfies: tapo ne?

بَدِيهِيَّة:
  - forall X iff tapo X مَقَاس عِنْد أَقَلَّ 3 وَـ لَا مَجْمُوع مُسَطَّح
مُرَشَّح: وَضَع s0 2، 3، 4، 7 وَـ 8؛ وَضَع s1 6 وَـ 9؛ وَضَع s2 4، 5، 8 وَـ 9؛ وَضَع s3 2، 4 وَـ 5.
satisfies tapo مَاذَا؟

Აქსიომები: X tapo X ზომა at least 3 და არ ჯამი კი iff forall.
Კანდიდატები: s0 2, 3, 4, 7 და 8 set; s1 6 და 9 set; s2 4, 5, 8 და 9 set; s3 2, 4 და 5 set.
Satisfies tapo რა?

Axioms: forall X iff tapo X size i least 3 me kāore tapeke papatairite.
Kaiwhakauru: whakawhenua s0 2, 3, 4, 7 me 8; whakawhenua s1 6 me 9; whakawhenua s2 4, 5, 8 me 9; whakawhenua s3 2, 4 me 5.
Satisfies tapo unutai?

Chân lý:
  - X forall tapo X iff kích thước lúc least 3 và không tổng số bằng phẳng
Candidates: s0 để 2, 3, 4, 7 và 8; s1 để 6 và 9; s2 để 4, 5, 8 và 9; s3 để 2, 4 và 5.
Satisfies tapo gì?

สัจพจน์:Xforalltapo:Xiffขนาดที่least:3และไม่sumแม้.
ผู้สมัคร:s0set2, 3, 4, 7และ8; s1set6และ9; s2set4, 5, 8และ9; s3set2, 4และ5.
satisfies:tapoอะไร?

axioms:
  - X tapo X size at least 3 மற்றும் sum இரட்டைப்படை இல்லை iff forall
வேட்பாளர்: s0 2, 3, 4, 7 மற்றும் 8 set; s1 6 மற்றும் 9 set; s2 4, 5, 8 மற்றும் 9 set; s3 2, 4 மற்றும் 5 set.
satisfies tapo என்ன?

Axioms: X forall tapo: X iff size katika least: 3 na si sum even.
Wagombea ni: s0 seti 2, 3, 4, 7 na 8; s1 seti 6 na 9; s2 seti 4, 5, 8 na 9; s3 seti 2, 4 na 5.
Satisfies: tapo nini?

Axioms: X tapo X size at least 3 dóó dooda sum ndi iff forall.
Candidates: s0 2, 3, 4, 7 dóó 8 set; s1 6 dóó 9 set; s2 4, 5, 8 dóó 9 set; s3 2, 4 dóó 5 set.
Satisfies tapo haʼátʼíísh?

Axioms: X tapo X size at least 3 aamma sum even not iff forall.
Candidates: s0 2, 3, 4, 7 aamma 8 set; s1 6 aamma 9 set; s2 4, 5, 8 aamma 9 set; s3 2, 4 aamma 5 set.
Satisfies tapo what?

Axioms: X forall tapo X iff size long least 3 na not sum even.
Candidates: s0 set 2, 3, 4, 7 na 8; s1 set 6 na 9; s2 set 4, 5, 8 na 9; s3 set 2, 4 na 5.
Satisfies tapo what?

Axioms: X forall tapo X iff size at least 3 not sum even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
Satisfies tapo kwèch?

Axioms: X forall tapo X iff size at least 3 а sum even ца.
Candidates: s0 set 2, 3, 4, 7 а 8; s1 set 6 а 9; s2 set 4, 5, 8 а 9; s3 set 2, 4 а 5.
Satisfies tapo фу?

공리: X tapo X 크기 at 가장 적게 3 안 합계 고르다 iff forall.
후보자: s0 2, 3, 4, 7 8 두다; s1 6 9 두다; s2 4, 5, 8 9 두다; s3 2, 4 5 두다.
satisfies tapo 무엇?

Axioms: X tapo X tamaina at least 3 eta ez sum even iff forall.
Kandidatu: s0 2, 3, 4, 7 eta 8 multzo; s1 6 eta 9 multzo; s2 4, 5, 8 eta 9 multzo; s3 2, 4 eta 5 multzo.
Satisfies tapo zer?

Axioms: X forall tapo X iff size at least 3 ᎠᎴ ᏝᏃ sum even.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 2, 3, 4, 7 ᎠᎴ 8; s1 ᏭᏕᎵᎦ 6 ᎠᎴ 9; s2 ᏭᏕᎵᎦ 4, 5, 8 ᎠᎴ 9; s3 ᏭᏕᎵᎦ 2, 4 ᎠᎴ 5.
What satisfies tapo?

Axioms: X forall tapo X iff chhika at least 3 ama qullu even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
Satisfies tapo what?

Axioms: X tapo X size at least 3 ыкӏи not sum even iff forall.
Candidates: s0 2, 3, 4, 7 ыкӏи 8 set; s1 6 ыкӏи 9 set; s2 4, 5, 8 ыкӏи 9 set; s3 2, 4 ыкӏи 5 set.
Satisfies tapo сыд?

Axioms: X forall tapo X iff size at least 3 thiab tsis sum even.
Candidates: s0 set 2, 3, 4, 7 thiab 8; s1 set 6 thiab 9; s2 set 4, 5, 8 thiab 9; s3 set 2, 4 thiab 5.
Satisfies tapo what?

Axioms: X forall tapo X iff size jeyou wy krook 3 woi sum even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
Satisfies tapo ining-jak?

Axioms: X forall tapo X iff size at least 3 micha' ki'yo sum even.
Candidates: s0 set 2, 3, 4, 7 micha' 8; s1 set 6 micha' 9; s2 set 4, 5, 8 micha' 9; s3 set 2, 4 micha' 5.
Satisfies tapo nanta?

Axioms: X tapo X size at least 3 カ ソモ sum even iff forall.
Candidates: s0 2, 3, 4, 7 カ 8 set; s1 6 カ 9 set; s2 4, 5, 8 カ 9 set; s3 2, 4 カ 5 set.
Satisfies tapo what?

Axioms: X forall tapo X iff size at least 3 ынкъам not sum even.
Candidates: s0 set 2, 3, 4, 7 ынкъам 8; s1 set 6 ынкъам 9; s2 set 4, 5, 8 ынкъам 9; s3 set 2, 4 ынкъам 5.
Satisfies tapo what?

Axioms: X forall tapo X iff size at least 3 yéetel ma' sum even.
Candidates: s0 set 2, 3, 4, 7 yéetel 8; s1 set 6 yéetel 9; s2 set 4, 5, 8 yéetel 9; s3 set 2, 4 yéetel 5.
Satisfies tapo what?

Axioms: X forall tapo X iff size at least 3 not sum even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
Satisfies tapo híli?

Axioms: X tapo X size at least 3 na sum even not iff forall.
Candidates: s0 2, 3, 4, 7 na 8 set; s1 6 na 9 set; s2 4, 5, 8 na 9 set; s3 2, 4 na 5 set.
Satisfies tapo what?

Axioms: X forall tapo X iff size at least 3 nahániri sum even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
Satisfies tapo what?

Axioms: X tapo X size at least 3 not sum even iff forall.
Candidates: s0 2, 3, 4, 7 8 set; s1 6 9 set; s2 4, 5, 8 9 set; s3 2, 4 5 set.
Satisfies tapo what?

Axioms: X forall tapo X iff ʻǁnàhã at least 3 ǂʻá ǁʻàa sum even.
Candidates: s0 set 2, 3, 4, 7 ǂʻá 8; s1 set 6 ǂʻá 9; s2 set 4, 5, 8 ǂʻá 9; s3 set 2, 4 ǂʻá 5.
Satisfies tapo what?

Axioms: X tapo X size at least 3 not sum even iff forall.
Candidates: s0 2, 3, 4, 7 8 set; s1 6 9 set; s2 4, 5, 8 9 set; s3 2, 4 5 set.
Satisfies tapo what?

Axioms: X forall tapo X iff size at least 3 not sum even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
Satisfies tapo what?

Axioms: X tapo X size at least 3 not sum even iff forall.
Candidates: s0 2, 3, 4, 7 8 set; s1 6 9 set; s2 4, 5, 8 9 set; s3 2, 4 5 set.
Satisfies tapo what?

Axioms: X forall tapo X iff size at least 3 not sum even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
Satisfies tapo what?

Axioms: X forall tapo X iff size at least 3 inte sum even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
Satisfies tapo tay?

Axiomes : X forall tapo X ssi taille au moindre 3 et pas somme plat.
Les candidats sont : s0 poser 2, 3, 4, 7 et 8 ; s1 poser 6 et 9 ; s2 poser 4, 5, 8 et 9 ; s3 poser 2, 4 et 5.
Quoi satisfies tapo ?

Aksiomo: X forall tapo X iff grandeco ĉe plej malmulta 3 kaj ne sum ebena.
Kandidato: s0 meti 2, 3, 4, 7 kaj 8; s1 meti 6 kaj 9; s2 meti 4, 5, 8 kaj 9; s3 meti 2, 4 kaj 5.
Satisfies tapo kio?

Axiómák:
  - X forall tapo X acsa méret at legkisebb 3 és nem összeg egyenletes
Indulók: s0 set 2, 3, 4, 7 és 8; s1 set 6 és 9; s2 set 4, 5, 8 és 9; s3 set 2, 4 és 5.
Satisfies tapo melyik?

axioms:Xforalltapo:Xiffsize喺least:3及不sum更加.
候選人:s0set2, 3, 4, 7及8; s1set6及9; s2set4, 5, 8及9; s3set2, 4及5.
satisfies:tapo乜嘢?

Axioms: X forall tapo X iff size at least 3 とぅ not sum even.
Candidates: s0 set 2, 3, 4, 7 とぅ 8; s1 set 6 とぅ 9; s2 set 4, 5, 8 とぅ 9; s3 set 2, 4 とぅ 5.
Satisfies tapo what?

Аксиома: X forall tapo X iff мөлшер at least 3 және емес сом да.
Үміткер: s0 жиын 2, 3, 4, 7 және 8; s1 жиын 6 және 9; s2 жиын 4, 5, 8 және 9; s3 жиын 2, 4 және 5.
Satisfies tapo не?

אַקְסְיוֹמָה: X forall tapo X אםם גֹּדֶל אֵצֶל least 3 וְ־ לא סְכוּם ערב.
מועמדת: s0 הֵנִיח 2, 3, 4, 7 וְ־ 8; s1 הֵנִיח 6 וְ־ 9; s2 הֵנִיח 4, 5, 8 וְ־ 9; s3 הֵנִיח 2, 4 וְ־ 5.
איזה satisfies tapo?

Axioms: X forall tapo X iff size at least 3 დო not sum even.
Candidates: s0 set 2, 3, 4, 7 დო 8; s1 set 6 დო 9; s2 set 4, 5, 8 დო 9; s3 set 2, 4 დო 5.
Satisfies tapo what?

Aksioma-aksioma: X forall tapo X iff ukuran at least 3 dan tidak sum rata.
Kandidat: s0 memperkenalkan 2, 3, 4, 7 dan 8; s1 memperkenalkan 6 dan 9; s2 memperkenalkan 4, 5, 8 dan 9; s3 memperkenalkan 2, 4 dan 5.
Satisfies tapo apa?

ស្វ័យសត្យ:Xforalltapo:Xiffទំហំatleast:3នឹងមិន...ទេផលបូកសូម្បី.
បេក្ខជន:s0set2, 3, 4, 7នឹង8; s1set6នឹង9; s2set4, 5, 8នឹង9; s3set2, 4នឹង5.
satisfies:tapoអី?

ກົດຄວາມຈິງ:Xforalltapo:Xiffຂະຫນາດທີ່least:3ແລະບໍ່sum even.
ຜູ້ສະໝັກ:s0set2, 3, 4, 7ແລະ8; s1set6ແລະ9; s2set4, 5, 8ແລະ9; s3set2, 4ແລະ5.
satisfies:tapoຫຍັງ?

axioms: X tapo X size వద్ద least 3 మరియు sum చదునైన కాదు iff forall.
candidates: s0 2, 3, 4, 7 మరియు 8 set; s1 6 మరియు 9 set; s2 4, 5, 8 మరియు 9 set; s3 2, 4 మరియు 5 set.
satisfies tapo ఏమిటి?

Axioms: X forall tapo X iff size at least 3 rárá sum even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
What satisfies tapo?

Axioms: X tapo X size at least 3 dawǫ́’ sum even iff forall.
Candidates: s0 2, 3, 4, 7 8 set; s1 6 9 set; s2 4, 5, 8 9 set; s3 2, 4 5 set.
Satisfies tapo what?

axioms: X forall tapo X iff size at least 3 ᐋᒃᑲ sum even.
candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
satisfies tapo what?

Axioms: X forall tapo X iff size at least 3 not sum even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
Satisfies tapo what?

Axioms: X forall tapo X iff size at least 3 not sum even.
Candidates: s0 set 2, 3, 4, 7 8; s1 set 6 9; s2 set 4, 5, 8 9; s3 set 2, 4 5.
Satisfies tapo what?

Axioms: X tapo X size at least 3 sum even not iff forall.
Candidates: s0 2, 3, 4, 7 8 set; s1 6 9 set; s2 4, 5, 8 9 set; s3 2, 4 5 set.
Satisfies tapo вуч?

The axioms are:
  - X forall ruro X if and only if does not max at least 8 and has odd
The candidates are: s0 set 1 and 9; s1 set 1, 3, 5, 7 and 8; s2 set 1, 2 and 5; s3 set 2, 3 and 8.
What is the satisfies ruro?

Los axiomas son:
  - X para todo ruro: X si y sólo si no máximo en least: 8 y tiene odd
Los candidatos son: s0 se fija en 1 y 9; s1 se fija en 1, 3, 5, 7 y 8; s2 se fija en 1, 2 y 5; s3 se fija en 2, 3 y 8.
¿Qué satisfies: ruro?

公理如下：X对任意取值都满足ruro：X当且仅当不最大值在least：8和有odd。
候选项如下：s0的集合是1和9；s1的集合是1、3、5、7和8；s2的集合是1、2和5；s3的集合是2、3和8。
satisfies：ruro什么？

Belitler: X ruro: X max at least: 8 değil ve sahiptir odd iff forall.
Adaylar: s0 1 ve 9 koymak; s1 1, 3, 5, 7 ve 8 koymak; s2 1, 2 ve 5 koymak; s3 2, 3 ve 8 koymak.
Satisfies: ruro ne?

Axioms: X forall ruro: X iff si max katika least: 8 na ina odd.
Wagombea ni: s0 seti 1 na 9; s1 seti 1, 3, 5, 7 na 8; s2 seti 1, 2 na 5; s3 seti 2, 3 na 8.
Satisfies: ruro nini?

The axioms are:
  - X forall ruro X if and only if does not max at least 8 and has odd
The candidates are: s0 set 1 and 9; s1 set 1, 3, 5, 7 and 8; s2 set 1, 2 and 5; s3 set 2, 3 and 8.
What is the satisfies ruro?

{axioms: [(forall X (iff (ruro X) (and (not (max_at_least 8)) (has_odd))))], candidates: [(set s0 [1 9]) (set s1 [1 3 5 7 8]) (set s2 [1 2 5]) (set s3 [2 3 8])], query: (which_satisfies ruro)}

Axiome: X forall ruro X gdw. nicht max an geringst 8 und haben seltsam.
Die Kandidaten sind: s0 set 1 und 9; s1 set 1, 3, 5, 7 und 8; s2 set 1, 2 und 5; s3 set 2, 3 und 8.
Was satisfies ruro?

Аксѝо̄м: X forall ruro X iff не max at minimalan 8 и имати непаран.
Кандѝда̄т: s0 се̏т 1 и 9; s1 се̏т 1, 3, 5, 7 и 8; s2 се̏т 1, 2 и 5; s3 се̏т 2, 3 и 8.
Satisfies ruro kakav?

Perusväitteet: X forall ruro X joss ei max luona vähin 8 ja omistaa outo.
Ehdokkaat: s0 set 1 ja 9; s1 set 1, 3, 5, 7 ja 8; s2 set 1, 2 ja 5; s3 set 2, 3 ja 8.
Mikä satisfies ruro?

公理如下：X对任意取值都满足ruro：X当且仅当不最大值在least：8和有odd。
候选项如下：s0的集合是1和9；s1的集合是1、3、5、7和8；s2的集合是1、2和5；s3的集合是2、3和8。
satisfies：ruro什么？

公理:Xruro:Xmax...で最小の:8...ではないとhave変なiffforall.
候補者:s01と9置く; s11, 3, 5, 7と8置く; s21, 2と5置く; s32, 3と8置く.
satisfies:ruro何と?

Belitler: X ruro: X max at least: 8 değil ve sahiptir odd iff forall.
Adaylar: s0 1 ve 9 koymak; s1 1, 3, 5, 7 ve 8 koymak; s2 1, 2 ve 5 koymak; s3 2, 3 ve 8 koymak.
Satisfies: ruro ne?

بَدِيهِيَّة: forall X iff ruro X لَا max عِنْد أَقَلَّ 8 وَـ مَلَكَ فَرْدِيّ.
مُرَشَّح: وَضَع s0 1 وَـ 9؛ وَضَع s1 1، 3، 5، 7 وَـ 8؛ وَضَع s2 1، 2 وَـ 5؛ وَضَع s3 2، 3 وَـ 8.
satisfies ruro مَاذَا؟

Აქსიომები: X ruro X არ max at least 8 და ფლობს უცნაური iff forall.
Კანდიდატები: s0 1 და 9 set; s1 1, 3, 5, 7 და 8 set; s2 1, 2 და 5 set; s3 2, 3 და 8 set.
Satisfies ruro რა?

Axioms: forall X iff ruro X kāore max i least 8 me whai makere.
Kaiwhakauru: whakawhenua s0 1 me 9; whakawhenua s1 1, 3, 5, 7 me 8; whakawhenua s2 1, 2 me 5; whakawhenua s3 2, 3 me 8.
Satisfies ruro unutai?

Chân lý: X forall ruro X iff không max lúc least 8 và có kỳ cục.
Candidates: s0 để 1 và 9; s1 để 1, 3, 5, 7 và 8; s2 để 1, 2 và 5; s3 để 2, 3 và 8.
Satisfies ruro gì?

สัจพจน์:Xforallruro:Xiffไม่maxที่least:8และมีคี่.
ผู้สมัคร:s0set1และ9; s1set1, 3, 5, 7และ8; s2set1, 2และ5; s3set2, 3และ8.
satisfies:ruroอะไร?

axioms: X ruro X max at least 8 இல்லை மற்றும் have ஒற்றைப்படை iff forall.
வேட்பாளர்: s0 1 மற்றும் 9 set; s1 1, 3, 5, 7 மற்றும் 8 set; s2 1, 2 மற்றும் 5 set; s3 2, 3 மற்றும் 8 set.
satisfies ruro என்ன?

Axioms: X forall ruro: X iff si max katika least: 8 na ina odd.
Wagombea ni: s0 seti 1 na 9; s1 seti 1, 3, 5, 7 na 8; s2 seti 1, 2 na 5; s3 seti 2, 3 na 8.
Satisfies: ruro nini?

Axioms: X ruro X dooda max at least 8 dóó bee hólǫ́ odd iff forall.
Candidates: s0 1 dóó 9 set; s1 1, 3, 5, 7 dóó 8 set; s2 1, 2 dóó 5 set; s3 2, 3 dóó 8 set.
Satisfies ruro haʼátʼíísh?

Axioms: X ruro X max at least 8 not aamma qar odd iff forall.
Candidates: s0 1 aamma 9 set; s1 1, 3, 5, 7 aamma 8 set; s2 1, 2 aamma 5 set; s3 2, 3 aamma 8 set.
Satisfies ruro what?

Axioms: X forall ruro X iff not max long least 8 na have odd.
Candidates: s0 set 1 na 9; s1 set 1, 3, 5, 7 na 8; s2 set 1, 2 na 5; s3 set 2, 3 na 8.
Satisfies ruro what?

Axioms: X forall ruro X iff not max at least 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
Satisfies ruro kwèch?

Axioms: X forall ruro X iff max at least 8 ца а have odd.
Candidates: s0 set 1 а 9; s1 set 1, 3, 5, 7 а 8; s2 set 1, 2 а 5; s3 set 2, 3 а 8.
Satisfies ruro фу?

공리: X ruro X 안 max at 가장 적게 8 있다 기수의 iff forall.
후보자: s0 1 9 두다; s1 1, 3, 5, 7 8 두다; s2 1, 2 5 두다; s3 2, 3 8 두다.
satisfies ruro 무엇?

Axioms: X ruro X ez max at least 8 eta eduki odd iff forall.
Kandidatu: s0 1 eta 9 multzo; s1 1, 3, 5, 7 eta 8 multzo; s2 1, 2 eta 5 multzo; s3 2, 3 eta 8 multzo.
Satisfies ruro zer?

Axioms: X forall ruro X iff ᏝᏃ max at least 8 ᎠᎴ ᎤᎭ odd.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 1 ᎠᎴ 9; s1 ᏭᏕᎵᎦ 1, 3, 5, 7 ᎠᎴ 8; s2 ᏭᏕᎵᎦ 1, 2 ᎠᎴ 5; s3 ᏭᏕᎵᎦ 2, 3 ᎠᎴ 8.
What satisfies ruro?

Axioms: X forall ruro X iff ama max at least 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
Satisfies ruro what?

Axioms: X ruro X not max at least 8 ыкӏи have odd iff forall.
Candidates: s0 1 ыкӏи 9 set; s1 1, 3, 5, 7 ыкӏи 8 set; s2 1, 2 ыкӏи 5 set; s3 2, 3 ыкӏи 8 set.
Satisfies ruro сыд?

Axioms: X forall ruro X iff tsis max at least 8 thiab have odd.
Candidates: s0 set 1 thiab 9; s1 set 1, 3, 5, 7 thiab 8; s2 set 1, 2 thiab 5; s3 set 2, 3 thiab 8.
Satisfies ruro what?

Axioms: X forall ruro X iff woi max jeyou wy krook 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
Satisfies ruro ining-jak?

Axioms: X forall ruro X iff ki'yo max at least 8 micha' have odd.
Candidates: s0 set 1 micha' 9; s1 set 1, 3, 5, 7 micha' 8; s2 set 1, 2 micha' 5; s3 set 2, 3 micha' 8.
Satisfies ruro nanta?

Axioms: X ruro X ソモ max at least 8 カ have odd iff forall.
Candidates: s0 1 カ 9 set; s1 1, 3, 5, 7 カ 8 set; s2 1, 2 カ 5 set; s3 2, 3 カ 8 set.
Satisfies ruro what?

Axioms: X forall ruro X iff not max at least 8 ынкъам рытык odd.
Candidates: s0 set 1 ынкъам 9; s1 set 1, 3, 5, 7 ынкъам 8; s2 set 1, 2 ынкъам 5; s3 set 2, 3 ынкъам 8.
Satisfies ruro what?

Axioms: X forall ruro X iff ma' max at least 8 yéetel have odd.
Candidates: s0 set 1 yéetel 9; s1 set 1, 3, 5, 7 yéetel 8; s2 set 1, 2 yéetel 5; s3 set 2, 3 yéetel 8.
Satisfies ruro what?

Axioms: X forall ruro X iff not max at least 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
Satisfies ruro híli?

Axioms: X ruro X max at least 8 not na have odd iff forall.
Candidates: s0 1 na 9 set; s1 1, 3, 5, 7 na 8 set; s2 1, 2 na 5 set; s3 2, 3 na 8 set.
Satisfies ruro what?

Axioms: X forall ruro X iff nahániri max at least 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
Satisfies ruro what?

Axioms: X ruro X not max at least 8 have odd iff forall.
Candidates: s0 1 9 set; s1 1, 3, 5, 7 8 set; s2 1, 2 5 set; s3 2, 3 8 set.
Satisfies ruro what?

Axioms: X forall ruro X iff ǁʻàa max at least 8 ǂʻá have odd.
Candidates: s0 set 1 ǂʻá 9; s1 set 1, 3, 5, 7 ǂʻá 8; s2 set 1, 2 ǂʻá 5; s3 set 2, 3 ǂʻá 8.
Satisfies ruro what?

Axioms: X ruro X not max at least 8 have odd iff forall.
Candidates: s0 1 9 set; s1 1, 3, 5, 7 8 set; s2 1, 2 5 set; s3 2, 3 8 set.
Satisfies ruro what?

Axioms: X forall ruro X iff not max at least 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
Satisfies ruro what?

Axioms: X ruro X not max at least 8 have odd iff forall.
Candidates: s0 1 9 set; s1 1, 3, 5, 7 8 set; s2 1, 2 5 set; s3 2, 3 8 set.
Satisfies ruro what?

Axioms: X forall ruro X iff not max at least 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
Satisfies ruro what?

Axioms: X forall ruro X iff inte max at least 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
Satisfies ruro tay?

Axiomes : X forall ruro X ssi pas max au moindre 8 et avoir bizarre.
Les candidats sont : s0 poser 1 et 9 ; s1 poser 1, 3, 5, 7 et 8 ; s2 poser 1, 2 et 5 ; s3 poser 2, 3 et 8.
Quoi satisfies ruro ?

Aksiomo: X forall ruro X iff ne max ĉe plej malmulta 8 kaj havi stranga.
Kandidato: s0 meti 1 kaj 9; s1 meti 1, 3, 5, 7 kaj 8; s2 meti 1, 2 kaj 5; s3 meti 2, 3 kaj 8.
Satisfies ruro kio?

Axiómák: X forall ruro X acsa nem max at legkisebb 8 és bír furcsa.
Indulók: s0 set 1 és 9; s1 set 1, 3, 5, 7 és 8; s2 set 1, 2 és 5; s3 set 2, 3 és 8.
Satisfies ruro melyik?

axioms:Xforallruro:Xiff不max喺least:8及有odd.
候選人:s0set1及9; s1set1, 3, 5, 7及8; s2set1, 2及5; s3set2, 3及8.
satisfies:ruro乜嘢?

Axioms: X forall ruro X iff not max at least 8 とぅ have odd.
Candidates: s0 set 1 とぅ 9; s1 set 1, 3, 5, 7 とぅ 8; s2 set 1, 2 とぅ 5; s3 set 2, 3 とぅ 8.
Satisfies ruro what?

Аксиома: X forall ruro X iff емес max at least 8 және have odd.
Үміткер: s0 жиын 1 және 9; s1 жиын 1, 3, 5, 7 және 8; s2 жиын 1, 2 және 5; s3 жиын 2, 3 және 8.
Satisfies ruro не?

אַקְסְיוֹמָה: X forall ruro X אםם לא max אֵצֶל least 8 וְ־ have משונה.
מועמדת: s0 הֵנִיח 1 וְ־ 9; s1 הֵנִיח 1, 3, 5, 7 וְ־ 8; s2 הֵנִיח 1, 2 וְ־ 5; s3 הֵנִיח 2, 3 וְ־ 8.
איזה satisfies ruro?

Axioms: X forall ruro X iff not max at least 8 დო have odd.
Candidates: s0 set 1 დო 9; s1 set 1, 3, 5, 7 დო 8; s2 set 1, 2 დო 5; s3 set 2, 3 დო 8.
Satisfies ruro what?

Aksioma-aksioma: X forall ruro X iff tidak max at least 8 dan punya ganjil.
Kandidat: s0 memperkenalkan 1 dan 9; s1 memperkenalkan 1, 3, 5, 7 dan 8; s2 memperkenalkan 1, 2 dan 5; s3 memperkenalkan 2, 3 dan 8.
Satisfies ruro apa?

ស្វ័យសត្យ:Xforallruro:Xiffមិន...ទេmax at least:8នឹងមានសេស.
បេក្ខជន:s0set1នឹង9; s1set1, 3, 5, 7នឹង8; s2set1, 2នឹង5; s3set2, 3នឹង8.
satisfies:ruroអី?

ກົດຄວາມຈິງ:Xforallruro:Xiffບໍ່maxທີ່least:8ແລະມີodd.
ຜູ້ສະໝັກ:s0set1ແລະ9; s1set1, 3, 5, 7ແລະ8; s2set1, 2ແລະ5; s3set2, 3ແລະ8.
satisfies:ruroຫຍັງ?

axioms: X ruro X max వద్ద least 8 కాదు మరియు have విలక్షణమైన iff forall.
candidates: s0 1 మరియు 9 set; s1 1, 3, 5, 7 మరియు 8 set; s2 1, 2 మరియు 5 set; s3 2, 3 మరియు 8 set.
satisfies ruro ఏమిటి?

Axioms: X forall ruro X iff rárá max at least 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
What satisfies ruro?

Axioms: X ruro X dawǫ́’ max at least 8 have odd iff forall.
Candidates: s0 1 9 set; s1 1, 3, 5, 7 8 set; s2 1, 2 5 set; s3 2, 3 8 set.
Satisfies ruro what?

axioms: X forall ruro X iff ᐋᒃᑲ max at least 8 have odd.
candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
satisfies ruro what?

Axioms: X forall ruro X iff not max at least 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
Satisfies ruro what?

Axioms: X forall ruro X iff not max at least 8 have odd.
Candidates: s0 set 1 9; s1 set 1, 3, 5, 7 8; s2 set 1, 2 5; s3 set 2, 3 8.
Satisfies ruro what?

Axioms: X ruro X max at least 8 not have odd iff forall.
Candidates: s0 1 9 set; s1 1, 3, 5, 7 8 set; s2 1, 2 5 set; s3 2, 3 8 set.
Satisfies ruro вуч?

The axioms are: X forall rivu X if and only if max at least 7 and min at most 5.
The candidates are: s0 set 2 and 4; s1 set 6, 7, 8 and 9; s2 set 2, 3, 5, 7 and 8; s3 set 1, 3, 4 and 6.
What is the satisfies rivu?

Los axiomas son:
  - X para todo rivu: X si y sólo si máximo en least: 7 y mínimo en la mayoría: 5
Los candidatos son: s0 se fija en 2 y 4; s1 se fija en 6, 7, 8 y 9; s2 se fija en 2, 3, 5, 7 y 8; s3 se fija en 1, 3, 4 y 6.
¿Qué satisfies: rivu?

公理如下：X对任意取值都满足rivu：X当且仅当最大值在least：7和最小值在大多数：5。
候选项如下：s0的集合是2和4；s1的集合是6、7、8和9；s2的集合是2、3、5、7和8；s3的集合是1、3、4和6。
satisfies：rivu什么？

Belitler: X rivu: X max at least: 7 ve min at çoğu: 5 iff forall.
Adaylar: s0 2 ve 4 koymak; s1 6, 7, 8 ve 9 koymak; s2 2, 3, 5, 7 ve 8 koymak; s3 1, 3, 4 ve 6 koymak.
Satisfies: rivu ne?

Axioms: X forall rivu: X iff max katika least: 7 na min katika wengi: 5.
Wagombea ni: s0 seti 2 na 4; s1 seti 6, 7, 8 na 9; s2 seti 2, 3, 5, 7 na 8; s3 seti 1, 3, 4 na 6.
Satisfies: rivu nini?

The axioms are: X forall rivu X if and only if max at least 7 and min at most 5.
The candidates are: s0 set 2 and 4; s1 set 6, 7, 8 and 9; s2 set 2, 3, 5, 7 and 8; s3 set 1, 3, 4 and 6.
What is the satisfies rivu?

{axioms: [(forall X (iff (rivu X) (and (max_at_least 7) (min_at_most 5))))], candidates: [(set s0 [2 4]) (set s1 [6 7 8 9]) (set s2 [2 3 5 7 8]) (set s3 [1 3 4 6])], query: (which_satisfies rivu)}

Axiome: X forall rivu X gdw. max an geringst 7 und min an die meisten 5.
Die Kandidaten sind: s0 set 2 und 4; s1 set 6, 7, 8 und 9; s2 set 2, 3, 5, 7 und 8; s3 set 1, 3, 4 und 6.
Was satisfies rivu?

Аксѝо̄м: X forall rivu X iff max at minimalan 7 и min at većina 5.
Кандѝда̄т: s0 се̏т 2 и 4; s1 се̏т 6, 7, 8 и 9; s2 се̏т 2, 3, 5, 7 и 8; s3 се̏т 1, 3, 4 и 6.
Satisfies rivu kakav?

Perusväitteet: X forall rivu X joss max luona vähin 7 ja min luona useimmat 5.
Ehdokkaat: s0 set 2 ja 4; s1 set 6, 7, 8 ja 9; s2 set 2, 3, 5, 7 ja 8; s3 set 1, 3, 4 ja 6.
Mikä satisfies rivu?

公理如下：X对任意取值都满足rivu：X当且仅当最大值在least：7和最小值在大多数：5。
候选项如下：s0的集合是2和4；s1的集合是6、7、8和9；s2的集合是2、3、5、7和8；s3的集合是1、3、4和6。
satisfies：rivu什么？

公理:Xrivu:Xmax...で最小の:7とmin...で大部分:5iffforall.
候補者:s02と4置く; s16, 7, 8と9置く; s22, 3, 5, 7と8置く; s31, 3, 4と6置く.
satisfies:rivu何と?

Belitler: X rivu: X max at least: 7 ve min at çoğu: 5 iff forall.
Adaylar: s0 2 ve 4 koymak; s1 6, 7, 8 ve 9 koymak; s2 2, 3, 5, 7 ve 8 koymak; s3 1, 3, 4 ve 6 koymak.
Satisfies: rivu ne?

بَدِيهِيَّة: forall X iff rivu X max عِنْد أَقَلَّ 7 وَـ min عِنْد أَكْثَر 5.
مُرَشَّح: وَضَع s0 2 وَـ 4؛ وَضَع s1 6، 7، 8 وَـ 9؛ وَضَع s2 2، 3، 5، 7 وَـ 8؛ وَضَع s3 1، 3، 4 وَـ 6.
satisfies rivu مَاذَا؟

Აქსიომები: X rivu X max at least 7 და min at უმეტესობა 5 iff forall.
Კანდიდატები: s0 2 და 4 set; s1 6, 7, 8 და 9 set; s2 2, 3, 5, 7 და 8 set; s3 1, 3, 4 და 6 set.
Satisfies rivu რა?

Axioms: forall X iff rivu X max i least 7 me min i nuinga 5.
Kaiwhakauru: whakawhenua s0 2 me 4; whakawhenua s1 6, 7, 8 me 9; whakawhenua s2 2, 3, 5, 7 me 8; whakawhenua s3 1, 3, 4 me 6.
Satisfies rivu unutai?

Chân lý: X forall rivu X iff max lúc least 7 và min lúc hầu hết 5.
Candidates: s0 để 2 và 4; s1 để 6, 7, 8 và 9; s2 để 2, 3, 5, 7 và 8; s3 để 1, 3, 4 và 6.
Satisfies rivu gì?

สัจพจน์:Xforallrivu:Xiffmaxที่least:7และminที่ส่วนใหญ่:5.
ผู้สมัคร:s0set2และ4; s1set6, 7, 8และ9; s2set2, 3, 5, 7และ8; s3set1, 3, 4และ6.
satisfies:rivuอะไร?

axioms: X rivu X max at least 7 மற்றும் min at most 5 iff forall.
வேட்பாளர்: s0 2 மற்றும் 4 set; s1 6, 7, 8 மற்றும் 9 set; s2 2, 3, 5, 7 மற்றும் 8 set; s3 1, 3, 4 மற்றும் 6 set.
satisfies rivu என்ன?

Axioms: X forall rivu: X iff max katika least: 7 na min katika wengi: 5.
Wagombea ni: s0 seti 2 na 4; s1 seti 6, 7, 8 na 9; s2 seti 2, 3, 5, 7 na 8; s3 seti 1, 3, 4 na 6.
Satisfies: rivu nini?

Axioms: X rivu X max at least 7 dóó min at most 5 iff forall.
Candidates: s0 2 dóó 4 set; s1 6, 7, 8 dóó 9 set; s2 2, 3, 5, 7 dóó 8 set; s3 1, 3, 4 dóó 6 set.
Satisfies rivu haʼátʼíísh?

Axioms: X rivu X max at least 7 aamma min at most 5 iff forall.
Candidates: s0 2 aamma 4 set; s1 6, 7, 8 aamma 9 set; s2 2, 3, 5, 7 aamma 8 set; s3 1, 3, 4 aamma 6 set.
Satisfies rivu what?

Axioms: X forall rivu X iff max long least 7 na min long most 5.
Candidates: s0 set 2 na 4; s1 set 6, 7, 8 na 9; s2 set 2, 3, 5, 7 na 8; s3 set 1, 3, 4 na 6.
Satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 min at most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
Satisfies rivu kwèch?

Axioms: X forall rivu X iff max at least 7 а min at most 5.
Candidates: s0 set 2 а 4; s1 set 6, 7, 8 а 9; s2 set 2, 3, 5, 7 а 8; s3 set 1, 3, 4 а 6.
Satisfies rivu фу?

공리: X rivu X max at 가장 적게 7 min at 가장 5 iff forall.
후보자: s0 2 4 두다; s1 6, 7, 8 9 두다; s2 2, 3, 5, 7 8 두다; s3 1, 3, 4 6 두다.
satisfies rivu 무엇?

Axioms: X rivu X max at least 7 eta min at most 5 iff forall.
Kandidatu: s0 2 eta 4 multzo; s1 6, 7, 8 eta 9 multzo; s2 2, 3, 5, 7 eta 8 multzo; s3 1, 3, 4 eta 6 multzo.
Satisfies rivu zer?

Axioms: X forall rivu X iff max at least 7 ᎠᎴ min at ᎤᎪᏗᏗ 5.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 2 ᎠᎴ 4; s1 ᏭᏕᎵᎦ 6, 7, 8 ᎠᎴ 9; s2 ᏭᏕᎵᎦ 2, 3, 5, 7 ᎠᎴ 8; s3 ᏭᏕᎵᎦ 1, 3, 4 ᎠᎴ 6.
What satisfies rivu?

Axioms: X forall rivu X iff max at least 7 min at most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
Satisfies rivu what?

Axioms: X rivu X max at least 7 ыкӏи min at most 5 iff forall.
Candidates: s0 2 ыкӏи 4 set; s1 6, 7, 8 ыкӏи 9 set; s2 2, 3, 5, 7 ыкӏи 8 set; s3 1, 3, 4 ыкӏи 6 set.
Satisfies rivu сыд?

Axioms: X forall rivu X iff max at least 7 thiab min at most 5.
Candidates: s0 set 2 thiab 4; s1 set 6, 7, 8 thiab 9; s2 set 2, 3, 5, 7 thiab 8; s3 set 1, 3, 4 thiab 6.
Satisfies rivu what?

Axioms: X forall rivu X iff max jeyou wy krook 7 min jeyou most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
Satisfies rivu ining-jak?

Axioms: X forall rivu X iff max at least 7 micha' min at most 5.
Candidates: s0 set 2 micha' 4; s1 set 6, 7, 8 micha' 9; s2 set 2, 3, 5, 7 micha' 8; s3 set 1, 3, 4 micha' 6.
Satisfies rivu nanta?

Axioms: X rivu X max at least 7 カ min at most 5 iff forall.
Candidates: s0 2 カ 4 set; s1 6, 7, 8 カ 9 set; s2 2, 3, 5, 7 カ 8 set; s3 1, 3, 4 カ 6 set.
Satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 ынкъам min at most 5.
Candidates: s0 set 2 ынкъам 4; s1 set 6, 7, 8 ынкъам 9; s2 set 2, 3, 5, 7 ынкъам 8; s3 set 1, 3, 4 ынкъам 6.
Satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 yéetel min at most 5.
Candidates: s0 set 2 yéetel 4; s1 set 6, 7, 8 yéetel 9; s2 set 2, 3, 5, 7 yéetel 8; s3 set 1, 3, 4 yéetel 6.
Satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 min at most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
Satisfies rivu híli?

Axioms: X rivu X max at least 7 na min at most 5 iff forall.
Candidates: s0 2 na 4 set; s1 6, 7, 8 na 9 set; s2 2, 3, 5, 7 na 8 set; s3 1, 3, 4 na 6 set.
Satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 min at most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
Satisfies rivu what?

Axioms: X rivu X max at least 7 min at most 5 iff forall.
Candidates: s0 2 4 set; s1 6, 7, 8 9 set; s2 2, 3, 5, 7 8 set; s3 1, 3, 4 6 set.
Satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 ǂʻá min at most 5.
Candidates: s0 set 2 ǂʻá 4; s1 set 6, 7, 8 ǂʻá 9; s2 set 2, 3, 5, 7 ǂʻá 8; s3 set 1, 3, 4 ǂʻá 6.
Satisfies rivu what?

Axioms: X rivu X max at least 7 min at most 5 iff forall.
Candidates: s0 2 4 set; s1 6, 7, 8 9 set; s2 2, 3, 5, 7 8 set; s3 1, 3, 4 6 set.
Satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 min at most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
Satisfies rivu what?

Axioms: X rivu X max at least 7 min at most 5 iff forall.
Candidates: s0 2 4 set; s1 6, 7, 8 9 set; s2 2, 3, 5, 7 8 set; s3 1, 3, 4 6 set.
Satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 min at most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
Satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 min at most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
Satisfies rivu tay?

Axiomes : X forall rivu X ssi max au moindre 7 et min au plus 5.
Les candidats sont : s0 poser 2 et 4 ; s1 poser 6, 7, 8 et 9 ; s2 poser 2, 3, 5, 7 et 8 ; s3 poser 1, 3, 4 et 6.
Quoi satisfies rivu ?

Aksiomo: X forall rivu X iff max ĉe plej malmulta 7 kaj min ĉe plej 5.
Kandidato: s0 meti 2 kaj 4; s1 meti 6, 7, 8 kaj 9; s2 meti 2, 3, 5, 7 kaj 8; s3 meti 1, 3, 4 kaj 6.
Satisfies rivu kio?

Axiómák: X forall rivu X acsa max at legkisebb 7 és min at legtöbb 5.
Indulók: s0 set 2 és 4; s1 set 6, 7, 8 és 9; s2 set 2, 3, 5, 7 és 8; s3 set 1, 3, 4 és 6.
Satisfies rivu melyik?

axioms:Xforallrivu:Xiffmax喺least:7及min喺多數:5.
候選人:s0set2及4; s1set6, 7, 8及9; s2set2, 3, 5, 7及8; s3set1, 3, 4及6.
satisfies:rivu乜嘢?

Axioms: X forall rivu X iff max at least 7 とぅ min at most 5.
Candidates: s0 set 2 とぅ 4; s1 set 6, 7, 8 とぅ 9; s2 set 2, 3, 5, 7 とぅ 8; s3 set 1, 3, 4 とぅ 6.
Satisfies rivu what?

Аксиома: X forall rivu X iff max at least 7 және min at ең 5.
Үміткер: s0 жиын 2 және 4; s1 жиын 6, 7, 8 және 9; s2 жиын 2, 3, 5, 7 және 8; s3 жиын 1, 3, 4 және 6.
Satisfies rivu не?

אַקְסְיוֹמָה: X forall rivu X אםם max אֵצֶל least 7 וְ־ min אֵצֶל רוב 5.
מועמדת: s0 הֵנִיח 2 וְ־ 4; s1 הֵנִיח 6, 7, 8 וְ־ 9; s2 הֵנִיח 2, 3, 5, 7 וְ־ 8; s3 הֵנִיח 1, 3, 4 וְ־ 6.
איזה satisfies rivu?

Axioms: X forall rivu X iff max at least 7 დო min at most 5.
Candidates: s0 set 2 დო 4; s1 set 6, 7, 8 დო 9; s2 set 2, 3, 5, 7 დო 8; s3 set 1, 3, 4 დო 6.
Satisfies rivu what?

Aksioma-aksioma: X forall rivu X iff max at least 7 dan min at most 5.
Kandidat: s0 memperkenalkan 2 dan 4; s1 memperkenalkan 6, 7, 8 dan 9; s2 memperkenalkan 2, 3, 5, 7 dan 8; s3 memperkenalkan 1, 3, 4 dan 6.
Satisfies rivu apa?

ស្វ័យសត្យ:Xforallrivu:Xiffmax at least:7នឹងminatជាងគេ:5.
បេក្ខជន:s0set2នឹង4; s1set6, 7, 8នឹង9; s2set2, 3, 5, 7នឹង8; s3set1, 3, 4នឹង6.
satisfies:rivuអី?

ກົດຄວາມຈິງ:Xforallrivu:Xiffmaxທີ່least:7ແລະminທີ່...ທີ່ສຸດ:5.
ຜູ້ສະໝັກ:s0set2ແລະ4; s1set6, 7, 8ແລະ9; s2set2, 3, 5, 7ແລະ8; s3set1, 3, 4ແລະ6.
satisfies:rivuຫຍັງ?

axioms: X rivu X max వద్ద least 7 మరియు min వద్ద most 5 iff forall.
candidates: s0 2 మరియు 4 set; s1 6, 7, 8 మరియు 9 set; s2 2, 3, 5, 7 మరియు 8 set; s3 1, 3, 4 మరియు 6 set.
satisfies rivu ఏమిటి?

Axioms: X forall rivu X iff max at least 7 min at most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
What satisfies rivu?

Axioms: X rivu X max at least 7 min at most 5 iff forall.
Candidates: s0 2 4 set; s1 6, 7, 8 9 set; s2 2, 3, 5, 7 8 set; s3 1, 3, 4 6 set.
Satisfies rivu what?

axioms: X forall rivu X iff max at least 7 min at most 5.
candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 min at most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
Satisfies rivu what?

Axioms: X forall rivu X iff max at least 7 min at most 5.
Candidates: s0 set 2 4; s1 set 6, 7, 8 9; s2 set 2, 3, 5, 7 8; s3 set 1, 3, 4 6.
Satisfies rivu what?

Axioms: X rivu X max at least 7 min at most 5 iff forall.
Candidates: s0 2 4 set; s1 6, 7, 8 9 set; s2 2, 3, 5, 7 8 set; s3 1, 3, 4 6 set.
Satisfies rivu вуч?

The axioms are:
  - X forall mive X if and only if size at least 4 and does not contains 8
The candidates are: s0 set 2, 3, 5, 6 and 8; s1 set 2, 4 and 8; s2 set 1 and 6; s3 set 2, 3, 5 and 7.
What is the satisfies mive?

Los axiomas son:
  - X para todo mive: X si y sólo si tamaño en least: 4 y no contiene: 8
Los candidatos son: s0 se fija en 2, 3, 5, 6 y 8; s1 se fija en 2, 4 y 8; s2 se fija en 1 y 6; s3 se fija en 2, 3, 5 y 7.
¿Qué satisfies: mive?

公理如下：X对任意取值都满足mive：X当且仅当大小在least：4和不包含：8。
候选项如下：s0的集合是2、3、5、6和8；s1的集合是2、4和8；s2的集合是1和6；s3的集合是2、3、5和7。
satisfies：mive什么？

Belitler: X mive: X boyut at least: 4 ve contains: 8 değil iff forall.
Adaylar: s0 2, 3, 5, 6 ve 8 koymak; s1 2, 4 ve 8 koymak; s2 1 ve 6 koymak; s3 2, 3, 5 ve 7 koymak.
Satisfies: mive ne?

Axioms: X forall mive: X iff size katika least: 4 na si contains: 8.
Wagombea ni: s0 seti 2, 3, 5, 6 na 8; s1 seti 2, 4 na 8; s2 seti 1 na 6; s3 seti 2, 3, 5 na 7.
Satisfies: mive nini?

The axioms are:
  - X forall mive X if and only if size at least 4 and does not contains 8
The candidates are: s0 set 2, 3, 5, 6 and 8; s1 set 2, 4 and 8; s2 set 1 and 6; s3 set 2, 3, 5 and 7.
What is the satisfies mive?

{axioms: [(forall X (iff (mive X) (and (size_at_least 4) (not (contains 8)))))], candidates: [(set s0 [2 3 5 6 8]) (set s1 [2 4 8]) (set s2 [1 6]) (set s3 [2 3 5 7])], query: (which_satisfies mive)}

Axiome: X forall mive X gdw. Größe an geringst 4 und nicht contains 8.
Die Kandidaten sind: s0 set 2, 3, 5, 6 und 8; s1 set 2, 4 und 8; s2 set 1 und 6; s3 set 2, 3, 5 und 7.
Was satisfies mive?

Аксѝо̄м: X forall mive X iff величѝна at minimalan 4 и не contains 8.
Кандѝда̄т: s0 се̏т 2, 3, 5, 6 и 8; s1 се̏т 2, 4 и 8; s2 се̏т 1 и 6; s3 се̏т 2, 3, 5 и 7.
Satisfies mive kakav?

Perusväitteet: X forall mive X joss koko luona vähin 4 ja ei contains 8.
Ehdokkaat: s0 set 2, 3, 5, 6 ja 8; s1 set 2, 4 ja 8; s2 set 1 ja 6; s3 set 2, 3, 5 ja 7.
Mikä satisfies mive?

公理如下：X对任意取值都满足mive：X当且仅当大小在least：4和不包含：8。
候选项如下：s0的集合是2、3、5、6和8；s1的集合是2、4和8；s2的集合是1和6；s3的集合是2、3、5和7。
satisfies：mive什么？

公理:Xmive:X大きさ...で最小の:4とcontains:8...ではないiffforall.
候補者:s02, 3, 5, 6と8置く; s12, 4と8置く; s21と6置く; s32, 3, 5と7置く.
satisfies:mive何と?

Belitler: X mive: X boyut at least: 4 ve contains: 8 değil iff forall.
Adaylar: s0 2, 3, 5, 6 ve 8 koymak; s1 2, 4 ve 8 koymak; s2 1 ve 6 koymak; s3 2, 3, 5 ve 7 koymak.
Satisfies: mive ne?

بَدِيهِيَّة: forall X iff mive X مَقَاس عِنْد أَقَلَّ 4 وَـ لَا contains 8.
مُرَشَّح: وَضَع s0 2، 3، 5، 6 وَـ 8؛ وَضَع s1 2، 4 وَـ 8؛ وَضَع s2 1 وَـ 6؛ وَضَع s3 2، 3، 5 وَـ 7.
satisfies mive مَاذَا؟

Აქსიომები: X mive X ზომა at least 4 და არ contains 8 iff forall.
Კანდიდატები: s0 2, 3, 5, 6 და 8 set; s1 2, 4 და 8 set; s2 1 და 6 set; s3 2, 3, 5 და 7 set.
Satisfies mive რა?

Axioms: forall X iff mive X size i least 4 me kāore contains 8.
Kaiwhakauru: whakawhenua s0 2, 3, 5, 6 me 8; whakawhenua s1 2, 4 me 8; whakawhenua s2 1 me 6; whakawhenua s3 2, 3, 5 me 7.
Satisfies mive unutai?

Chân lý: X forall mive X iff kích thước lúc least 4 và không contains 8.
Candidates: s0 để 2, 3, 5, 6 và 8; s1 để 2, 4 và 8; s2 để 1 và 6; s3 để 2, 3, 5 và 7.
Satisfies mive gì?

สัจพจน์:Xforallmive:Xiffขนาดที่least:4และไม่contains:8.
ผู้สมัคร:s0set2, 3, 5, 6และ8; s1set2, 4และ8; s2set1และ6; s3set2, 3, 5และ7.
satisfies:miveอะไร?

axioms: X mive X size at least 4 மற்றும் contains 8 இல்லை iff forall.
வேட்பாளர்: s0 2, 3, 5, 6 மற்றும் 8 set; s1 2, 4 மற்றும் 8 set; s2 1 மற்றும் 6 set; s3 2, 3, 5 மற்றும் 7 set.
satisfies mive என்ன?

Axioms: X forall mive: X iff size katika least: 4 na si contains: 8.
Wagombea ni: s0 seti 2, 3, 5, 6 na 8; s1 seti 2, 4 na 8; s2 seti 1 na 6; s3 seti 2, 3, 5 na 7.
Satisfies: mive nini?

Axioms: X mive X size at least 4 dóó dooda contains 8 iff forall.
Candidates: s0 2, 3, 5, 6 dóó 8 set; s1 2, 4 dóó 8 set; s2 1 dóó 6 set; s3 2, 3, 5 dóó 7 set.
Satisfies mive haʼátʼíísh?

Axioms: X mive X size at least 4 aamma contains 8 not iff forall.
Candidates: s0 2, 3, 5, 6 aamma 8 set; s1 2, 4 aamma 8 set; s2 1 aamma 6 set; s3 2, 3, 5 aamma 7 set.
Satisfies mive what?

Axioms: X forall mive X iff size long least 4 na not contains 8.
Candidates: s0 set 2, 3, 5, 6 na 8; s1 set 2, 4 na 8; s2 set 1 na 6; s3 set 2, 3, 5 na 7.
Satisfies mive what?

Axioms: X forall mive X iff size at least 4 not contains 8.
Candidates: s0 set 2, 3, 5, 6 8; s1 set 2, 4 8; s2 set 1 6; s3 set 2, 3, 5 7.
Satisfies mive kwèch?

Axioms: X forall mive X iff size at least 4 а contains 8 ца.
Candidates: s0 set 2, 3, 5, 6 а 8; s1 set 2, 4 а 8; s2 set 1 а 6; s3 set 2, 3, 5 а 7.
Satisfies mive фу?

공리: X mive X 크기 at 가장 적게 4 안 contains 8 iff forall.
후보자: s0 2, 3, 5, 6 8 두다; s1 2, 4 8 두다; s2 1 6 두다; s3 2, 3, 5 7 두다.
satisfies mive 무엇?

Axioms: X mive X tamaina at least 4 eta ez contains 8 iff forall.
Kandidatu: s0 2, 3, 5, 6 eta 8 multzo; s1 2, 4 eta 8 multzo; s2 1 eta 6 multzo; s3 2, 3, 5 eta 7 multzo.
Satisfies mive zer?

Axioms: X forall mive X iff size at least 4 ᎠᎴ ᏝᏃ contains 8.
ᎠᏙᎩᏯᏍᎩ: s0 ᏭᏕᎵᎦ 2, 3, 5, 6 ᎠᎴ 8; s1 ᏭᏕᎵᎦ 2, 4 ᎠᎴ 8; s2 ᏭᏕᎵᎦ 1 ᎠᎴ 6; s3 ᏭᏕᎵᎦ 2, 3, 5 ᎠᎴ 7.
What satisfies mive?

Axioms: X forall mive X iff chhika at least 4 ama contains 8.
Candidates: s0 set 2, 3, 5, 6 8; s1 set 2, 4 8; s2 set 1 6; s3 set 2, 3, 5 7.
Satisfies mive what?

Axioms: X mive X size at least 4 ыкӏи not contains 8 iff forall.
Candidates: s0 2, 3, 5, 6 ыкӏи 8 set; s1 2, 4 ыкӏи 8 set; s2 1 ыкӏи 6 set; s3 2, 3, 5 ыкӏи 7 set.
Satisfies mive сыд?

Axioms: X forall mive X iff size at least 4 thiab tsis contains 8.
Candidates: s0 set 2, 3, 5, 6 thiab 8; s1 set 2, 4 thiab 8; s2 set 1 thiab 6; s3 set 2, 3, 5 thiab 7.
Satisfies mive what?

Axioms: X forall mive X iff size jeyou wy krook 4 woi contains 8.
Candidates: s0 set 2, 3, 5, 6 8; s1 set 2, 4 8; s2 set 1 6; s3 set 2, 3, 5 7.
Satisfies mive ining-jak?

Axioms: X forall mive X iff size at least 4 micha' ki'yo contains 8.
Candidates: s0 set 2, 3, 5, 6 micha' 8; s1 set 2, 4 micha' 8; s2 set 1 micha' 6; s3 set 2, 3, 5 micha' 7.
Satisfies mive nanta?

Axioms: X mive X size at least 4 カ ソモ contains 8 iff forall.
Candidates: s0 2, 3, 5, 6 カ 8 set; s1 2, 4 カ 8 set; s2 1 カ 6 set; s3 2, 3, 5 カ 7 set.
Satisfies mive what?

Axioms: X forall mive X iff size at least 4 ынкъам not contains 8.
Candidates: s0 set 2, 3, 5, 6 ынкъам 8; s1 set 2, 4 ынкъам 8; s2 set 1 ынкъам 6; s3 set 2, 3, 5 ынкъам 7.
Satisfies mive what?

Axioms: X forall mive X iff size at least 4 yéetel ma' contains 8.
Candidates: s0 set 2, 3, 5, 6 yéetel 8; s1 set 2, 4 yéetel 8; s2 set 1 yéetel 6; s3 set 2, 3, 5 yéetel 7.
Satisfies mive what?

Axioms: X forall mive X iff size at least 4 not contains 8.
Candidates: s0 set 2, 3, 5, 6 8; s1 set 2, 4 8; s2 set 1 6; s3 set 2, 3, 5 7.
Satisfies mive híli?

Axioms: X mive X size at least 4 na contains 8 not iff forall.
Candidates: s0 2, 3, 5, 6 na 8 set; s1 2, 4 na 8 set; s2 1 na 6 set; s3 2, 3, 5 na 7 set.
Satisfies mive what?

Axioms: X forall mive X iff size at least 4 nahániri contains 8.
Candidates: s0 set 2, 3, 5, 6 8; s1 set 2, 4 8; s2 set 1 6; s3 set 2, 3, 5 7.
Satisfies mive what?

Axioms: X mive X size at least 4 not contains 8 iff forall.
Candidates: s0 2, 3, 5, 6 8 set; s1 2, 4 8 set; s2 1 6 set; s3 2, 3, 5 7 set.
Satisfies mive what?

Axioms: X forall mive X iff ʻǁnàhã at least 4 ǂʻá ǁʻàa contains 8.
Candidates: s0 set 2, 3, 5, 6 ǂʻá 8; s1 set 2, 4 ǂʻá 8; s2 set 1 ǂʻá 6; s3 set 2, 3, 5 ǂʻá 7.
Satisfies mive what?

Axioms: X mive X size at least 4 not contains 8 iff forall.
Candidates: s0 2, 3, 5, 6 8 set; s1 2, 4 8 set; s2 1 6 set; s3 2, 3, 5 7 set.
Satisfies mive what?

Axioms: X forall mive X iff size at least 4 not contains 8.
Candidates: s0 set 2, 3, 5, 6 8; s1 set 2, 4 8; s2 set 1 6; s3 set 2, 3, 5 7.
Satisfies mive what?

Axioms: X mive X size at least 4 not contains 8 iff forall.
Candidates: s0 2, 3, 5, 6 8 set; s1 2, 4 8 set; s2 1 6 set; s3 2, 3, 5 7 set.
Satisfies mive what?

Axioms: X forall mive X iff size at least 4 not contains 8.
Candidates: s0 set 2, 3, 5, 6 8; s1 set 2, 4 8; s2 set 1 6; s3 set 2, 3, 5 7.
Satisfies mive what?

Axioms: X forall mive X iff size at least 4 inte contains 8.
Candidates: s0 set 2, 3, 5, 6 8; s1 set 2, 4 8; s2 set 1 6; s3 set 2, 3, 5 7.
Satisfies mive tay?

Axiomes : X forall mive X ssi taille au moindre 4 et pas contains 8.
Les candidats sont : s0 poser 2, 3, 5, 6 et 8 ; s1 poser 2, 4 et 8 ; s2 poser 1 et 6 ; s3 poser 2, 3, 5 et 7.
Quoi satisfies mive ?

Aksiomo:
  - X forall mive X iff grandeco ĉe plej malmulta 4 kaj ne contains 8
Kandidato: s0 meti 2, 3, 5, 6 kaj 8; s1 meti 2, 4 kaj 8; s2 meti 1 kaj 6; s3 meti 2, 3, 5 kaj 7.
Satisfies mive kio?

Axiómák: X forall mive X acsa méret at legkisebb 4 és nem contains 8.
Indulók: s0 set 2, 3, 5, 6 és 8; s1 set 2, 4 és 8; s2 set 1 és 6; s3 set 2, 3, 5 és 7.
Satisfies mive melyik?

axioms:Xforallmive:Xiffsize喺least:4及不contains:8.
候選人:s0set2, 3, 5, 6及8; s1set2, 4及8; s2set1及6; s3set2, 3, 5及7.
satisfies:mive乜嘢?

Axioms: X forall mive X iff size at least 4 とぅ not contains 8.
Candidates: s0 set 2, 3, 5, 6 とぅ 8; s1 set 2, 4 とぅ 8; s2 set 1 とぅ 6; s3 set 2, 3, 5 とぅ 7.
Satisfies mive what?

Аксиома: X forall mive X iff мөлшер at least 4 және емес contains 8.
Үміткер: s0 жиын 2, 3, 5, 6 және 8; s1 жиын 2, 4 және 8; s2 жиын 1 және 6; s3 жиын 2, 3, 5 және 7.
Satisfies mive не?

אַקְסְיוֹמָה: X forall mive X אםם גֹּדֶל אֵצֶל least 4 וְ־ לא contains 8.
מועמדת: s0 הֵנִיח 2, 3, 5, 6 וְ־ 8; s1 הֵנִיח 2, 4 וְ־ 8; s2 הֵנִיח 1 וְ־ 6; s3 הֵנִיח 2, 3, 5 וְ־ 7.
איזה satisfies mive?